Originally posted by wantomake
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You should listen to someone who knows what they are doing and that's obviously not ME. I guess I wasn't thinking when I drew that schematic. Here is what I am ACTUALLY running. Instead of a second boost I am running a DC to DC converter, which acts much the same, but is more efficient. And I have a cap across the input. It probably isn't necessary, but that DC to DC is like $130 rather than $30, so I take no chances. I am changing the picture on the previous post to the correct one. The main ISSUE is which side of the diode the LOAD is on. It changes the relationship between potential differences. No wonder bistander asked if I had ever run that circuit before.
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