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Confirming the Delayed Lenz Effect

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  • brusers
    replied
    Calculation questions

    Originally posted by Overunityguide View Post
    Hi You All,

    Please See my Latest Video About: 'How to Calculate the Delayed Lenz Effect'
    Calculation of the Delayed Lenz Effect - YouTube

    This Video demonstrates how we can calculate the desired Delayed Lenz Effect, and shows that the experimental results of my previous video about: the Difference between Loading and Shorting the Regenerative Acceleration Generator coil can be explained and can be calculated. So than again high impedance is really important. And the Lenz Delay can be calculated by L/R

    With Kind Regards, Overunityguide
    Hello Overunityguide.

    In your calculations there, you use your figures from you coil, and get 3.733 mS for your time constant. 3000 RPM with 12 magnets gives 300 Hz, or T = 3.33, which is about the same as your time constant for your coil. Also in your video you show, in steps, that this is the "hump" at where the effect starts to take place.

    Is it safe to assume that anything over 3000 is going to show the effect? Meaning there would be no higher RPM that would start to show a decline in the effect.

    If so I guess shooting for 1(L/Rtotal) would be optimizing the prime mover, so as to not expend any unnecessary energy on higher speeds.

    Would be nice to hear your thoughts, and thank you for the videos you put up. Good documentation, things are a bit clearer.

    Best regards,

    Marcel

    Leave a comment:


  • Allen Burgess
    replied
    Coils.

    The thread spool axle bearing spinner core on the left was designed for the same two wraps as it's big brother to the right of it, with the spiral coil sphere spinner inside. A twin wire coil sleeve, with one counter wind of 18 gauge over a multi layer of 32 gauge, needs to slip over the bearing shaft, which needs to be cut flush to the outside of the inner core wall. Thane loops his output back to his power coil. I haven't tried this yet. I have only looped back to the run battery so far.

    Coil-rotor adjustment is easier with the small CD top, than the larger spiral coil unit. I have yet to finsh wraping the thread spool model, but I believe it has the potential to out perform the larger model. I think replacing the Reed switch with a Hall effect transister might help improve the tube spnner unit too.

    I tried wireing a 32 gauge outer bifilar coil wrap in series like the power coils, but it made the spinner buck and jolt. Very bad results! Both those outer wraps have to be single wire. So that's how the tiny one's supposed to look when finished.

    So that yields two "Lenz Delay Propulsion" coils, one inside the core and one outside. This leaves the bifilar thread spool power coil secondary BEMF to light big LED bulbs like 62498 does in his "test tube sphere" video. I believe this type of very simple unit has the potential to go overunity. It sounds like Thane's claiming COP>5 on one of his regenerative accelerators. The tiny one with just a Reed switch does not present a great challenge for the beginning experimental builder. Let me stress once more though, it's the costly precision ceramic bearings that make the "Lenz Delay" RPM's possible. I noticed Boca improved the bearing and doubled the cost.

    There's a simple wireing schematic for the Reed switch in series, and further to the right, a "Lenz Delay" spiral coil and tube magnet I dimpled like a golf ball to increase speed. The magnet's on wheels and free to re-orient itself by spinning around in the wooden cup. This feature helped set new speed records. This setup caught the "Lenz Boost Effect" at high speeds too. I invented the coil. I hit 58K with the 1" with it, way over anything Skycollection attained with his squashed Rodin Starship coil and levitating spinner. Those tiny "Boca" ceramic bearings did the trick.

    The spinner takes a few minutes to build speed slowly up to about 15k, but when the "Over Drive" effect kicks in, it begins to gain around 5k every few seconds.
    Last edited by Allen Burgess; 06-21-2017, 11:48 AM.

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  • minoly
    replied
    I found this vid by magluvin to be extremely useful and right along w/ what I have been noticing as well:
    Finding resonance lock with coil and rotor - YouTube

    Patrick

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  • mbrownn
    replied
    I noticed something on some of these tests. Some of these circuits contain a regenerative path. Once a curtain motor speed has been reached you get an acceleration of the motor, this can be because the frequency required for the regenerative circuit has been reached. when this happens you get a pulse that is effectively 100% duty and the motor power will go up. This is an effect that can give an efficient pulse motor double the current that you are putting in and has nothing to do with lenz's law.

    The acceleration you get with shorting the generator coil is something else but it is worth watching the amp draw on the input to the motor and not from the supply because if there is an increase in amps then it is likely that this has something to do with the regenerative circuit.

    The basics of this type of regenerative action is, is once you reach a pulse frequency that the current on the discharge of the coil hasn't dissipated before the next pulse, it adds to the current on the next pulse until the circuit cannot flow any more amps due to ohms law. http://www.energeticforum.com/attach...uits-regen.jpg



    If this is not the reason for the acceleration then truly something interesting is happening.

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  • qvision
    replied
    Thanks for that Allen, i'll try it out.

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  • Allen Burgess
    replied
    Coil face.

    @qvision

    What's the diameter of your coil face compared to the diameter of your rotor magnets? Note that the diameter of my air core thread spool coil face is around the same size as my magnet spinner diameter in the demonstration device above. The thread spool wire wrap is tapering at the ends and bulgy in the middle.

    Now take a close look at Thane's. Look at the oblong shape of the green tape wraped output coil at the forefront of Thane's generator. He shows you an egg shaped one faceing out. Notice that the coil face is not much larger then the coil core, and around the same size as his rotor magnets. I maintain the same kind of size proportion in my tiny "Lenz Delay Propulsion" demo device. These are critical factors, they can't be ignored and need to be worked into your formula.
    Last edited by Allen Burgess; 04-07-2016, 09:56 PM.

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  • qvision
    replied
    wings i am speaking of just one magnet passing just one coil, all of the above maths is about one instance of a generator coil

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  • wings
    replied
    Originally posted by qvision View Post
    I don't understand please explain.
    with 4 6 magnets the cycles are 4 6 each rotation then the RPM for one cycle is 1/4 , 1/6

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  • qvision
    replied
    I don't understand please explain.

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  • wings
    replied
    Originally posted by qvision View Post
    OK i got the maths wrong before !

    I'm sure it's right now but please check.

    Using OUG's component values :

    L : 0.01756
    R1 : 19.2
    R2 : 220

    TC = L/(R1+R2)

    TC = 0.01756/239.2 = 0.0734113712 mS

    So, to beat the rise time the magnet must pass over the core very quickly.

    Rotor diameter is 150mm, magnet diameter is 20mm so magnet centre point is 65mm from centre so the effective diameter is 130mm and our effective circumference (the travel line through the magnet's centre)is Pi x D = 408mm.

    Let's say the magnet has to pass over the core in 0.07ms, so it must travel 10mm in 0.07ms.

    So, how long does it take for one revolution ?

    The circumference to travel is 408mm, so 408/10 = 40.8 and it will take 0.07 * 40.8 = 2.856 mS for one revolution.

    How many revolutions is that per second ? One second divided by desired speed = 1000/2.856 = 350.140056022409.

    And in RPM, 350.140056022409 * 60 = 21008.40336134454 RPM !

    Please check my maths !

    I have put it all into a spreadsheet :

    lenzbend.xls

    Leave a comment:


  • qvision
    replied
    ******** Maths Update ********

    OK i got the maths wrong before !

    I'm sure it's right now but please check.

    Using OUG's component values :

    L : 0.01756
    R1 : 19.2
    R2 : 220

    TC = L/(R1+R2)

    TC = 0.01756/239.2 = 0.0734113712 mS

    So, to beat the rise time the magnet must pass over the core very quickly.

    Rotor diameter is 150mm, magnet diameter is 20mm so magnet centre point is 65mm from centre so the effective diameter is 130mm and our effective circumference (the travel line through the magnet's centre)is Pi x D = 408mm.

    Let's say the magnet has to pass over the core in 0.07ms, so it must travel 10mm in 0.07ms.

    So, how long does it take for one revolution ?

    The circumference to travel is 408mm, so 408/10 = 40.8 and it will take 0.07 * 40.8 = 2.856 mS for one revolution.

    How many revolutions is that per second ? One second divided by desired speed = 1000/2.856 = 350.140056022409.

    And in RPM, 350.140056022409 * 60 = 21008.40336134454 RPM !

    Please check my maths !

    I have put it all into a spreadsheet :

    lenzbend.xls

    Leave a comment:


  • qvision
    replied
    OK, coil wound.

    6.5 Henries
    3 kOhms

    No delayed Lenz effect with either an Adams type motor going up to 4000 RPM or a diametrically magnetised cylinder magnet going up to 30,000 RPM.

    Godammit !

    I'm beginning to think 'free energy' is a fairy-tale made up by magnet manufacturers and copper wire manufacturers in cahoots with each other ;+}
    Last edited by qvision; 09-14-2011, 06:40 PM.

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  • qvision
    replied
    LOL Allen, OK

    Cheers frenky, i'll do that this time, just been and bought a new spool.

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  • frenky
    replied
    @qvision:
    If you don't plan on reusing the coils wire then you could add a few drops of instant glue every few layers while you wind your coil.

    Leave a comment:


  • Allen Burgess
    replied
    Coil.

    @qvision,

    Looks real familiar! Been there and done that. Drop it off at the salvage yard for the smelter.

    Leave a comment:

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