Motor Generators

[bistander]

Mr. Rakarskiy,
Continuing my critique of your publication, in the section pasted below, please specify where the 9.3ohm value comes from. I see 11.3ohm for the load in the oscillograms.

We can calculate the current on the bulb using Ohm's law I = U/R = 3.4V / 9.3Ohm = 0.36A.
If we apply the general formula for determining the current in a closed circuit, we will not get equality with the measurement of the idle EMF.

I = (E-U)/(R+r) = (9,4V-3,4V)/ (9,3Ω+12,1Ω) = 0,129A

Because the current in the anchor, when the load is closed, contributes to the amplification of the magnetic flux in the circuit (which is visible on the second screen of the FEMM program). Self-excitation occurs, due to which the resulting EMF increases.

We can only calculate this level of the resulting EMF, it will be 26.5 volts.

Let's check: I = (E-U)/(R+r) = (26,5V-3,4V)/ (9,3Ω+12,1Ω) = 0,36A

Also, both the other two equations have math errors.
bi

[bistander]

I have added a slide that explains how an emf is induced in a wire. Hippolytus Pixia's first generator was an alternator. | Patreon

2025-03-15_082544.jpg

If we consider the components of the magnetic circuit and the EMF diagram, we see that the induction of electromagnetic force occurs when the cross-section in which the magnetic circuit is closed changes. Induction is induced only in the wire that is in the focus of the changing magnetic circuit. At the same time, with a complete closure in the minimum or maximum value, the cross-section in which the magnetic circuit is closed, the induction of EMF is not induced. The main element in this case is the change in the cross-section of the conducting circuit in which there is a closed source of constant magnetic field.
Ф = Bm*S, where S = a*b changes

Notice the difference?

2023-11-09_085408 (1).jpg
versus

2025-03-15_082544 (1).jpg

bi

[Rakarskiy]

I have added a slide that explains how an emf is induced in a wire. Hippolytus Pixia's first generator was an alternator. | Patreon

2025-03-15_082544.jpg

If we consider the components of the magnetic circuit and the EMF diagram, we see that the induction of electromagnetic force occurs when the cross-section in which the magnetic circuit is closed changes. Induction is induced only in the wire that is in the focus of the changing magnetic circuit. At the same time, with a complete closure in the minimum or maximum value, the cross-section in which the magnetic circuit is closed, the induction of EMF is not induced. The main element in this case is the change in the cross-section of the conducting circuit in which there is a closed source of constant magnetic field.

Ф = Bm*S, where S = a*b changes

[Rakarskiy]

The modeling is done by taking the dimensions from the actual installation.
1.jpg?token-time=1743206400&token-hash=xWyCJnmtw1hN46brKF_29QOUR-7yWDRqO-6nH8lBwRE%3D.jpg

[bistander]

Thanks for editing, I did make a few typos in my haste, but it doesn't change the essence.

I added another slide where both anchor positions are fixed and in both the function of cutting the anchor wires by magnetic lines is impossible.

1.jpg?token-time=1743206400&token-hash=hkfeg3lNBd_aXFRm-IqgnNJOZzy7rS6ZkFcDpOmeuXg%3D.jpg

You're welcome Rakarskiy.

Your FEMM graphics look strange. Appears that the air gap is massively large.
bi

[Rakarskiy]

Notice in the equation below,

Magnetic flux Ф = Bm S = 1.699 T (0.025 m * 0.005 m) = 0.000125 Veber.

You neglected to multiply by 1.699 and simply used the product of 0.025•0.005 for flux. Correct value of that equation is 0.00021webers.

Thanks for editing, I did make a few typos in my haste, but it doesn't change the essence.

I added another slide where both anchor positions are fixed and in both the function of cutting the anchor wires by magnetic lines is impossible.

1.jpg?token-time=1743206400&token-hash=hkfeg3lNBd_aXFRm-IqgnNJOZzy7rS6ZkFcDpOmeuXg%3D.jpg

[bistander]

Hello Rakarskiy,
I noticed that you updated this
https://www.patreon.com/posts/122452345
and of course I'm interested.

As usual, it's nonsensical and reflects some basic misunderstanding. But I'll stay with an obvious math error in this post, found in this paragraph

The largest value of magnetic induction is 1.699 Tesla, this is in the iron bridge between magnets with a cross-section of S = 25 mm 5 mm. In addition, this is the only place where all the lines of force of the magnetic circuit pass. Thus, we can determine the Magnetic flux Ф = Bm S = 1.699 T (0.025 m * 0.005 m) = 0.000125 Veber.





Next, knowing the switching frequency of 20 Hz and the number of turns of the armature coil (500 turns), we can calculate the no-load EMF (without a connected load) based on the transformer formula of EMF:


E = 4.44NФf = 4.44 * 500 turns * 0.000125 Veber * 20 Hz = 9,42945 Volt


I myself did not expect such an exact hit,

Notice in the equation below,

Magnetic flux Ф = Bm S = 1.699 T (0.025 m * 0.005 m) = 0.000125 Veber.

You neglected to multiply by 1.699 and simply used the product of 0.025•0.005 for flux. Correct value of that equation is 0.00021webers.

This affects calculated voltage in the last equation.
bi

[bistander]

Question: who gave you the diploma, if anyone gave it to you? What the hell is this, the root mean square value of current or voltage, after a diode bridge with a buffer storage capacitor? Where did you see the root mean square value in DC circuits? Why do you think I did all the calculations for a DC circuit and what kind of value is this - the root mean square value of current or voltage, what is it used for? If you recommend calculating a circuit for the root mean square value, then I would not recommend anyone to order anything.
------------------
I am surprised that American trolls from the deep state system are ten levels below the Russians with whom I have been debating for more than 10 years (at the moment I have left many Russian resources). Here you are either a bad agent or a patient in a ward.

Mr. Rakarskiy,
I don't rely on my credentials to convince the reader of the truth and logic of my post. Most often, I include the phrase "look it up", and I often give references. I'll leave it to the reader to judge validity of my posts, and yours.
bi

[Rakarskiy]

If anyone is interested in my publication about magnetic motors:

TURKISH MAGNETIC GENERATOR IN ITALY 2019 | Patreon

1.jpg?token-time=1743033600&token-hash=p3PFt78pQhWFFcoRb0jbHjSOaZtIum9Pzbl6-id5d3I%3D.jpg

[Rakarskiy]

Question: who gave you the diploma, if anyone gave it to you? What the hell is this, the root mean square value of current or voltage, after a diode bridge with a buffer storage capacitor? Where did you see the root mean square value in DC circuits? Why do you think I did all the calculations for a DC circuit and what kind of value is this - the root mean square value of current or voltage, what is it used for? If you recommend calculating a circuit for the root mean square value, then I would not recommend anyone to order anything.
------------------
I am surprised that American trolls from the deep state system are ten levels below the Russians with whom I have been debating for more than 10 years (at the moment I have left many Russian resources). Here you are either a bad agent or a patient in a ward.

[bistander]

142460226.jpg

https://tinyurl.com/26dqhamu

You're restless!

You're changing the original condition or parameter.
This is what you showed:


The symbol for the source with ~ indicates sinusoidal AC and convention is and always has been that the numerical value, 220, is the RMS.

It is a poor, underhanded attempt now for you to imply that you intended for the 220 value in that diagram to be the peak of the AC voltage, which yields 156 V RMS. What country's utility grid supplies 156 volt electrical service?

Also, you begin the paragraph using that diagram with:

we need to know the current strength for a load of 1 kW at 220V: P = UI from here I = P/U = 1000 W/ 220V = 4.545A

To calculate the current from power and voltage necessarily implies the use of RMS values. 220V is the RMS value.
bi

[Rakarskiy]

142460226.jpg

https://tinyurl.com/26dqhamu

You're restless!

[bistander]

You are referring to your socket, where the connected phase is separated from the three-phase network, not the network I am considering, where there is only a generator phase and a load phase. Therefore, in a three-phase network, it will be calculated differently. Secondly, I gave the formula for calculating the capacitor below in that post.

And if you do the full calculation, you will have more places where you will not understand why. All electricians in power grids consider a source with zero internal resistance value.

I really doubt your professionalism. It would be easier for you to act as an observer. It is very difficult for me to change my mind about something, especially with references to impractical training materials, when I have experienced everything first-hand.

91466693 (2).jpg

This is the network of your example. That's it complete.

brcap.gif
Vac = Vdc x 0.71

That is the correct relationship between AC voltage and the resulting rectified filtered DC voltage



Full-Wave-Rectifier-6.png
Look it up.
bi

[Rakarskiy]

MAGMOV LOW COST ELECTRICITY GENERATOR PRODUCTION - YouTube

The company from GEORGIA has been offering a domestic power source for five years. The rotor of the generator is driven by a magnetic motor of a special design. Unfortunately, I have not been able to find any information about the happy owners of this source.
The presentation video personally raises questions for me.
The three automotive generators are designed for a rated speed of 5000 rpm. At what speed must the linear magnet switch move to provide at least 1000 rpm of the drum of magnets that is connected to the generators. Second, a contact of two points on the magnetic pole of the drum, about 1 cm in diameter, unclosed by magnetic interaction, can develop the appropriate torque to turn the three rotors of the generators in the boost mode?

https://magmovenergy.com/

[Rakarskiy]

You are referring to your socket, where the connected phase is separated from the three-phase network, not the network I am considering, where there is only a generator phase and a load phase. Therefore, in a three-phase network, it will be calculated differently. Secondly, I gave the formula for calculating the capacitor below in that post.

And if you do the full calculation, you will have more places where you will not understand why. All electricians in power grids consider a source with zero internal resistance value.

I really doubt your professionalism. It would be easier for you to act as an observer. It is very difficult for me to change my mind about something, especially with references to impractical training materials, when I have experienced everything first-hand.