Captret - Perpetual Light with Dead Batteries

[redrichie]

if you didnt watch it or missed the post, see lasersabers youtube video of his experiment. he is running his circuit off and charging a supercap, no batteries!!
off one almost dead super cap starting at .62 Volts he is showing steady increase in Voltage. Great job laser!
@ lasersaber: I hope you dont find any difference when you put it into Faraday cage.

[ibpointless2]

Yeah.. In particular try to get one that charges like you have been saying. I have not been able to get one that charges at all but I have the original that maintains the voltage after the caps fill up. So that is very impressive to say the least.

Thank you for helping me to see that potential is what it is all about. I suspected that there was something very simple to show this fact of nature but never could find the perfect example of this premise. Thank you again Ibpointless2!

I want to let everyone know that the circuit that self charges from the standing voltage usually takes 12 hours before i notice a change in voltage. Bigger farad and higher voltage caps will make it go faster. Even though charging is slow its still better than anything else out their, especially when you consider that i'm also running a LED too. I really do believe that i have tap into free energy.

I've got another one charging a rechargeable AA battery, but instead of a LED it uses a 1n4004 diode. Its slow to but it started out at 1.137 (standing voltage, the voltage that there from sitting for a day) and within 24 hours its now at 1.140 volts! Slow charging also rules out the phantom voltage.

So everyone trying to make my other captret self charging circuit just be patient.

[Jbignes5]

This would help immensely.

Today i'm going to see if i can build a radio shack captret circuit of my one that self charges from the standing point. I figure if i get the right parts then people could easily make it and only thing they'll need to do is just go to their local radio shack. Hopefully this make the disbelievers into believers. Simpler the better, i'm going to make it very simple for any one to make.

Yeah.. In particular try to get one that charges like you have been saying. I have not been able to get one that charges at all but I have the original that maintains the voltage after the caps fill up. So that is very impressive to say the least.

Thank you for helping me to see that potential is what it is all about. I suspected that there was something very simple to show this fact of nature but never could find the perfect example of this premise. Thank you again Ibpointless2!

[Jbignes5]

My original experiement is still going.

For 3 days now i believe. I have been running the original version of this circuit. My battery has lost nothing in voltage on a very weakly charge. The battery has a self standing voltage of 10.2 and is still there while running an led for days. The voltage is still the same. I am gonna run this for a week but I was wondering what the self discharge of a lead acid battery of 12 ah design would be. Seeing that it is a 12 volt battery normally and this battery is at 10.2 volts it would mean that there is very little left in the battery yet it is still the same voltage as I started with after 3 days of running the led.

I guess this got me thinking about what we could do with the 3v or so that is across the terminals of the caps and I came to the conclusion that we could run a ton of things like cmos maybe? With enough parallel caps we could run much more for free.

Since I am waiting to get more leds I wanted to know if someone could do some tests for me on parallel leds. I wanted to know if someone could read the resistance of the led in parallel if there is any. Because I had five leds in parallel and this worked great until I had a mishap.

As for my description of what is happening inside the caps well thats the only thing I could come up with from my observations. Just from the voltage readings we can tell whats going on. The only thing that is being consumed here is a very very small amount of leakage current thats why I brought up the idea of using super caps or ultra caps seeing that they have a smaller leakage then these cheap-o aluminum caps. One thing is for sure we need polarized caps to enable the flow in certain directions with a parallel plate to induce the voltage on. I think we have a very tiny Potential(voltage) pump here and that is evident by the power of the plates getting better with more parallel caps that are used, this could be akin to the gas engine with multiple pistons in parallel. The more of them there are the more powerful the action is between the plates.

[ibpointless2]

Today i'm going to see if i can build a radio shack captret circuit of my one that self charges from the standing point. I figure if i get the right parts then people could easily make it and only thing they'll need to do is just go to their local radio shack. Hopefully this make the disbelievers into believers. Simpler the better, i'm going to make it very simple for any one to make.

[ibpointless2]

To make a good captret the higer the farads and the voltage the better, but too high and you'll results you don't want.

Not every capacitor works, you've got to find one that does.

[wetissues]

People in this are stupid (in a way)

It is impossible to get a battery to charge itself with these conditions of circuitry. It is more volt feedback than current feedback that supposedly 'charges' the cell, if you hook this to an oscilliscope, or prove in a way that this is oscillating, then the battery would use current to 'bump' up voltage. IPPOINTLESS, try to switch your multimeter to amp draw, then you would realise how much energy a run down 9 volt has. A run down 9 volt has MAhours but not alot of current. This circuit draws mA so the cell will last longer.

[CosmicFarmer]

I couldn't wait so I just had to try.

I made 4 captrets, but the one as "schematic no 2" with the 2 captrets and the regular cap I couldn't get working that well... so only 3 worked right.

Also I notice that the LED and + battery connection does not need to go to the capacitor to get the LED to light... no word though on if that helps or hurts the charge effect.

First captret using 2 depleted 9v's one was at 8.02 and the other was 7.89. When added together they had 15.88... Also 1 uF at 50 v. (stolen from old TV) with a 3.2 vF white LED.

Well, I was tinkering and putting this together and the battery dropped all the way down to 10.23... When I had finished tinkering and just let it sit for a time test, the voltage was 9.18. I was measuring current with 70 wraps of magnetwire around my clamp meter and the circuit was showing nothing.. maybe .01 or so but was not accurate... So how could I loose battery voltage so fast (less then an hour from 15 to 10) without any amps?!.... Anyway, I then let it sit for some time and these are the voltage measurements...
9.18
8.06
8.20
(Zzzz goodnight)
9.53
9.62
9.70
And climbing...

The second captret I used a "supercap" of 4700uF at 25v, and the white LED. MUCH brighter light, but had a visable amp draw when first connected. Using 10 wraps on my amp meter, it read .35 amps at first, and after an hour, went down to .07. So remember, its really .035 amps down to .007 amps.
Here are the readings so far, 1 battery.
9.17 (.035a)
9.10 (.007a)
8.96
8.93
8.96
8.94
8.82
8.66

Ok nothing special here I think I may have made it wrong. The visable amp draw should have told me that.

Third captret was a .47 uF at 100v with an AMBER led with 1.7 vF.
8.83
8.82
8.81
8.79

Hm. First circuit is the winner winner chicken dinner because of its rebound, but it still has to pay back its debt of almost 5 whole volts.

Maybe my next step is to remove the LED and try chaining the caps in series or parallel. I think Lasersaber had them in series, O to - , and at the end his + went back to the battery +. "Electricity" is advising to hook them in parallel and combine the - and O. In my opinion which is worth less then 2 cents, I think by combining the - and O would only do to increase the surface area of the - and maybe increase capacitance a little... But I will try it anyway.


Heres a good source of capacitors and LEDs... Disposable flash cameras! Go to your local CVS or Rite Aid or convenience store that takes those disposable cameras. Ask them if you can help the environment by helping the store recycle their old cameras. I usually walk out of the store with a huge trash bag full of old cameras each time.

Inside each camera is the following JUICY technology...
Fancy HV transformer trifilar,
Fancy HV transformer like a car coil but smaller,
A red LED
A WHOLE AA battery! (Usually full too!)
transistors, diodes...
Large Cap from 80-300 uF and usually 300-400 V.
other stuff...

Its basically an oscillator.

If the helpful person taking your request is fearful of doing the "right thing" and dosn't want to get in trouble with their boss by giving stuff away, and summons the boss, this is what you do. The boss might say something like the camera place recycles them for the store, or something, but its all hogwash. Just tell him its for a "science project" on saving the ecology and creating light from waste. Maybe take the whole "green" movement and use similar verbology. Even when I got the hard line boss, I was atleast able to walk out with 1 camera. I never was turned down. My best haul was over 50 cameras... Filled my car full of them!

Now I have a huge bag of caps and batteries!

------------
Ok one question.
I have those 550 farad super caps that I would love to try but they have no O hookup. you think it would be the same if I just added foil around the outside? I probibly need an electrolyte to make it work right... Anyway..

[plengo]

and another interesting relation ship between the input and usable Captret's output.

Captret - Capacitor and Electret

Fausto.

************************************************** ************
I think this thing is very powerfull. Look at this picture. On the right I have one LED in series with the Captrets and the battery.

It is fully lit. Running a wopping 1.84ma at 24.80v (pun intended). On the left I have 4 of the exact same LED fully lit (both sides seems to the eye at least same luminosity). The four LEDs are in series.

Those LEDs on the left are what the Captret is running for that miserable 1.84ma of input. To me it sounds like the Captret is capable of making an input run four times stronger for the price of one.

More voltage is absolutely better. I can run many LEDs at an amazing less than one miliamp fully using this technique.

Fausto.
************************************************** ************

[ibpointless2]

Here my new findings: Captret - Capacitor and Electret

I am showing a link simply because the pictures are very big.

Fausto.

************************************************** **************
I have a new version of Captret that I think will make some not very confortable. Since the theories around has to do with voltage not current and some people seems to be able to replicate this phenomena and others only see the usual, I decided to share my new findings.

So please no need to flame me. I am only sharing my DATA with no conclusions about why and how it works.

I connected the circuit as shown on the picture attached. The two caps are identical eletrolitic caps 560uf and 250vdc. Bought on ebay from one nice batch of 15 (cheap too).

They are connected to two 12 volts lead acid battery of 100amp/h and 70amp/h car batteries. The idea here is not to see if the battery will charge but if they will discharge and at what rate.

I am using a 25 watt LED (also from ebay) that is lit to subjectively speaking 1/10 of its power and still very bright to the eye. Difficult to look at it.

Resting voltages totaled 24.8192v steady (since they have been not used for days now). As soon circuit was connected voltage drop to 24.6550v and have being going up steadily. I later started measuring the current in both negative and positive poles of the batteries and surprisingly enough the current consumption is not equal in both sides. Current has stabilized at 3.5ma (one can see the picture notes).

I measure the temperature of the LED and it is room temperature, feeling cold to the touch. I used an electronic laser meter for the measurement.

I decided to test another LED of exactly same type (25 watts) and see how much current it would take to light it up to "eye compatible luminosity" and I was not surprised to see it takes at least 200 ma at 20v. It also gets very hot at that power consumption, going to as high as 60 degrees Celsius.

To me it is very difficult to understand how I can light an LED to that brightness (as seen on the photo) with so little current (under 5ma at 24+volts).


Fausto.
************************************************** ********

Its the captret effect that causes it to run cool.

I've notice that my captret circuits run cool, especially the batteries themselves are cold to the touch.

[LaserSaber]

This is really strange. I am very surprised by what I have found in experimenting with this Captret stuff. Check out my video: YouTube - Testing the Captret: is this free energy?

[plengo]

For me it is only words. I try to take it with a grain of salt sometimes.

My whole point is that until we sit down and do the experiments. We need to do the work and observe the results or we will never have an understanding of this. Weather it is statics or Aether it is something we have never even paid attention to. We shoved it off as anomalies or even unwanted junk. We need to start sitting down and focusing on the real in front of our eyes.

Although this circuit is very very interesting and brings a lot of real observations it is still highly subjective because what we are trying to get a handle on is mostly invisible. Call it what you will it behaves much like static electricity. Seeing that I can run an led on it for quite a long time with no appreciable lowering of the voltage of this very weak battery I am convinced this has only to do with half of what we think electricity is. The potential is what we need to concentrate on if we are to find the key here. Since the original circuit rebounds after being started, back to the starting battery voltage, it shows proof positive this is only using a difference of potential and no current is being passed that would amount to lowering the voltage of that weak battery.

If we look back at Tesla about mass and how surface area changes the way that mass presents it's potential to the surrounding environment we can certainly figure out that even in this situation the energized plate is presenting it's potential to the second plate (-). If you put a led across the +,- we see that division of potential as it applies to the led. The led also serves the purpose of creating a one way flow between that division. With most of the energy to drive the led is from a weak induction between the plates. If you attach a meter on the negative of the battery and test each post of the cap as the led is running you will see how it works. The led runs off of the induced negative plate lowering the potential of that plate without disturbing the positive plate because they are now both positive but unequal because of the led's consumption of the potential from the negative plate. This is where the flow is coming from for the led.

Lets look at it like this:

battery before connection 10.2 v
battery after connection after balancing (rebound) 10.2 v

Negative(battery) to cap +, 10.2 v
negative(battery) to cap -, 8.38 v Solid
led voltage 1.78v

actually this is what the voltages are from the cap after the led was removed: from bat- to cap +, 10.20 v
bat- to cap -, 6.20 v then dives very easy

So this means after the led conducts across the cap it maintains the flow. Kinda like a whirlpool. weather or not there is an ac signal there is pointless. It's the flow that makes better sense. Follow the flow and you can see what is happening here. By the way adding more caps just increases the flow and that allows for better lighting from the led without using anything but the separation of the potential.

I really like your explanation. It is as if we just created a diapole that we simply don't kill (aka Bearden) simply because Capacitors don't allow current flow therefore no current gets to the other side of the diapole to kill it.

my 2cents.

Fausto.

[plengo]

Here my new findings: Captret - Capacitor and Electret

I am showing a link simply because the pictures are very big.

Fausto.

************************************************** **************
I have a new version of Captret that I think will make some not very confortable. Since the theories around has to do with voltage not current and some people seems to be able to replicate this phenomena and others only see the usual, I decided to share my new findings.

So please no need to flame me. I am only sharing my DATA with no conclusions about why and how it works.

I connected the circuit as shown on the picture attached. The two caps are identical eletrolitic caps 560uf and 250vdc. Bought on ebay from one nice batch of 15 (cheap too).

They are connected to two 12 volts lead acid battery of 100amp/h and 70amp/h car batteries. The idea here is not to see if the battery will charge but if they will discharge and at what rate.

I am using a 25 watt LED (also from ebay) that is lit to subjectively speaking 1/10 of its power and still very bright to the eye. Difficult to look at it.

Resting voltages totaled 24.8192v steady (since they have been not used for days now). As soon circuit was connected voltage drop to 24.6550v and have being going up steadily. I later started measuring the current in both negative and positive poles of the batteries and surprisingly enough the current consumption is not equal in both sides. Current has stabilized at 3.5ma (one can see the picture notes).

I measure the temperature of the LED and it is room temperature, feeling cold to the touch. I used an electronic laser meter for the measurement.

I decided to test another LED of exactly same type (25 watts) and see how much current it would take to light it up to "eye compatible luminosity" and I was not surprised to see it takes at least 200 ma at 20v. It also gets very hot at that power consumption, going to as high as 60 degrees Celsius.

To me it is very difficult to understand how I can light an LED to that brightness (as seen on the photo) with so little current (under 5ma at 24+volts).


Fausto.
************************************************** ********

[Jbignes5]

Yeah...

For me it is only words. I try to take it with a grain of salt sometimes.

My whole point is that until we sit down and do the experiments. We need to do the work and observe the results or we will never have an understanding of this. Weather it is statics or Aether it is something we have never even paid attention to. We shoved it off as anomalies or even unwanted junk. We need to start sitting down and focusing on the real in front of our eyes.

Although this circuit is very very interesting and brings a lot of real observations it is still highly subjective because what we are trying to get a handle on is mostly invisible. Call it what you will it behaves much like static electricity. Seeing that I can run an led on it for quite a long time with no appreciable lowering of the voltage of this very weak battery I am convinced this has only to do with half of what we think electricity is. The potential is what we need to concentrate on if we are to find the key here. Since the original circuit rebounds after being started, back to the starting battery voltage, it shows proof positive this is only using a difference of potential and no current is being passed that would amount to lowering the voltage of that weak battery.

If we look back at Tesla about mass and how surface area changes the way that mass presents it's potential to the surrounding environment we can certainly figure out that even in this situation the energized plate is presenting it's potential to the second plate (-). If you put a led across the +,- we see that division of potential as it applies to the led. The led also serves the purpose of creating a one way flow between that division. With most of the energy to drive the led is from a weak induction between the plates. If you attach a meter on the negative of the battery and test each post of the cap as the led is running you will see how it works. The led runs off of the induced negative plate lowering the potential of that plate without disturbing the positive plate because they are now both positive but unequal because of the led's consumption of the potential from the negative plate. This is where the flow is coming from for the led.

Lets look at it like this:

battery before connection 10.2 v
battery after connection after balancing (rebound) 10.2 v

Negative(battery) to cap +, 10.2 v
negative(battery) to cap -, 8.38 v Solid
led voltage 1.78v

actually this is what the voltages are from the cap after the led was removed: from bat- to cap +, 10.20 v
bat- to cap -, 6.20 v then dives very easy

So this means after the led conducts across the cap it maintains the flow. Kinda like a whirlpool. weather or not there is an ac signal there is pointless. It's the flow that makes better sense. Follow the flow and you can see what is happening here. By the way adding more caps just increases the flow and that allows for better lighting from the led without using anything but the separation of the potential.

[Joit]

Regarding Post #232 and #237

I think i will do a break from this Topic too,
I dont have a Problem with it, to stay as Observer
until the Replys are in a matured Way and not like from
'some Peoples on a bad Trip'.
Maybe thats why Energetic Forum is hated from some,
because some childish Guys could feel the Boots,
after they could not appreciate a good Treatment,
what they usual do get from other Members here.

I only can left a Note here for them.

http://www.energeticforum.com/forum-help-support/announcements.html