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  • Michael John Nunnerley
    replied
    not what I am looking for

    Originally posted by pengrove View Post
    a simple ion swapping reaction
    Reaction, yes, swapping is not the word for it and NO it is not what I am looking for as an answer.

    They all go to form an explosive material, on their own, or in part of another mix. Nitrogen is the most important part, you FIX the nitrogen first and after you can make what you want.

    Nitrogen fixation is the hardest part, it is so reactive once fixed that it will revert back to molecular nitrogen in 0.5sec or less by grabing one of its own

    Mike

    Leave a comment:


  • pengrove
    replied
    Originally posted by Michael John Nunnerley View Post
    Hi All

    This is something I want all to think about, if you take ANY nitride and mix it with ANY hydroxide, what do you get that is common to ALL?

    Mike
    a simple ion swapping reaction

    Leave a comment:


  • Michael John Nunnerley
    replied
    Nitrides

    Hi All

    This is something I want all to think about, if you take ANY nitride and mix it with ANY hydroxide, what do you get that is common to ALL?

    Mike

    Leave a comment:


  • Farrah Day
    replied
    Forgot to respond to this:

    As far as ammonium nh4, do you think all four bonds hydrogen bonds are
    identical?
    Honestly I don't know, but I would assume so. Remember however that as the nitrogen has one more proton than electron, it is NH4+, a molecular ion.

    Farrah

    Leave a comment:


  • Farrah Day
    replied
    Hi Aaron

    Do you think that at 78% nitrogen in the air that just because it takes
    less to split O2 and H2 that all that must be split first before any N2 is
    split?
    Yes. Higher energy reactions will always be preceded by lower energy reactions.

    Only N2 and O2 are in the air as far as what is concerned for
    this process. So all the 21% O in the air has to be split before any nitrogen
    can be split?
    Yes, that's how I see it.

    Does that hold true if there is a lot of surface area of grids
    and/or rods in a ionizer for example? Or do you think that having more than
    3 times the amount of nitrogen than oxygen may just allow some to be
    split even before all the O is split?
    I really don't know if it holds true under every condition, it is only my opinion. It may well come down to how you intend to dissociate the N2. But to illustrate my point, if you consider ozone generators for example, you never hear of them dissociating nitrogen do you? And they reside in this sea of N2.

    Nitrogen releases a tremendous amount of heat when recombining into N2.
    Yes, I would have thought so, do you have any figures for this reaction. I have not yet looked further into this.

    You may find some of this nitrogen information interesting:
    Allotropic Nitrogen - Active Nitrogen

    Only a small amount of "hho" is needed.
    But this brings us back to my others point, if we are getting all the energy from the recombination of atomic nitrogen, what part is the HHO playing - if anything?

    If solely for the creation of ammonia as a by-product... why go to all this trouble? Let's face it, ammonia is not a particularly nice product to be issuing forth from your exhaust pipe into the atmosphere.

    Still no clear or distinct path to follow in all this yet. I'm still struggling to find any logical sequence of events that instantly make sense, and feel that my Eureka moment is still some way off yet.

    What property of the arc dissociates H2?
    You asked me this before and I'm unsure as to what specific answer you're looking for. Are you looking for heat?

    The problem as I see it is that no one has yet laid down a specific set of events and reactions that take us logically from A - B. There seems to be much doubt about what reacts with what, where in the sequence of events these reactions actually take place, where the high energy exothermic reaction fits in, and indeed what the resulting 'ashes' are?

    Clearly many people here have there own ideas, which greatly confuses and complicates the issue - particularly as no two ideas would seem to be the same.

    The best thing for everyone to do would be to lay out their interpretation of the reactions and the sequence of events, from the very start, to the very finish. This way we could compare everyones views and analyse better the possible results.

    Farrah

    Remember: It's what we learn after we think we know it all that really counts!

    Leave a comment:


  • Aaron
    replied
    @Farrah Day

    Originally posted by Farrah Day View Post
    For the same reason it has the affinity to form the molecule in the first place, it wants to fill it's outer shell with electrons to stabilize.

    A nitrogen molecule can only dissociate into two atoms or two ions, not both, unless you provide a way of adding or extracting electrons.

    If nitrogen ionised so that we had N+ and N-, the hydrogen affinity would logically produce NH4+ and NH2-.

    The only way to get ammonia is by the reactions of atoms N and 3H.

    Of course if any ionising does occur anywhere in the process, then reactions will be different.

    But because the ionisation levels of oxygen and hydrogen are lower than that of nitrogen, clearly nitrogen would be the last gas to ionise, unless it was separted from air in the first place.

    I'm unfamiliar with the resulting energy released when nitrogen recombines into molecules, but if it is proportionally similar to the recombination of atomic hydrogen, then this reaction alone might prove to be the best source of energy. After all, unlike H2, we don't have to use energy producing the N2 in the first place - we're surrounded by the stuff.

    Could it be that ammonia is simply a useful by-product of atomic nitrogen recombing into molecules? But this would of course mean still going to the trouble of producing at least some H2... the mystery goes on.

    Of course Tut apparently has all these answers, so it's a little frustrating for us all to have to play this guessing game. But I daresay it's what we've all come to expect.

    Are you using a plasma arc somewhere in your process Tut?

    Regards, Farrah
    As far as ammonium nh4, do you think all four bonds hydrogen bonds are
    identical?

    In any case, according to your analysis, by splitting N2, will we wind up
    with two nitrogen atoms that are equal in charge to each other?

    Do you think that at 78% nitrogen in the air that just because it takes
    less to split O2 and H2 that all that must be split first before any N2 is
    split? Only N2 and O2 are in the air as far as what is concerned for
    this process. So all the 21% O in the air has to be split before any nitrogen
    can be split? Does that hold true if there is a lot of surface area of grids
    and/or rods in a ionizer for example? Or do you think that having more than
    3 times the amount of nitrogen than oxygen may just allow some to be
    split even before all the O is split?

    Nitrogen releases a tremendous amount of heat when recombining into N2.

    You may find some of this nitrogen information interesting:


    Only a small amount of "hho" is needed.

    What property of the arc dissociates H2?

    Leave a comment:


  • Aaron
    replied
    drawing?

    Originally posted by Vickers
    I mean your drawing my friend. Can buy a nascent? plug in any auto parts store.
    Please post the drawing or a link to the picture you're talking about. I have
    no idea what you're talking about.

    Leave a comment:


  • sebosfato
    replied
    Hi faraday

    I believe that, reacting charged gases inside the combustion chamber would lead us to achieve certain reactions during combustion.

    Meyer said that he could improve the energy yield by not allowing the water to reform.

    I just figured that if we cheaply charge our air or exhaust gases positively by electrostatic induction, (the gas that is going to react with our initial HHO) we would have initially oxygen with maybe 3 open holes. This kind of oxygen could link to 3 H atoms, thus if you are injecting 3H2+3O (from electrolysis) and as output (after combustion) you have 2H3O + O You are not allowing the complete reformation of water.

    i think that tutanka formula is like this:

    Assuming that nitrogen is also charged it will tend to want to fill its holes too.

    Thus if you input 3H2+30 and than have N2 charged positively you would form maybe 2N2H3+3O thus he takes this resulting gas to pass in a heat exchanger than inside the electrolyzer where the N2H3 ion will break the water into nitrogen and hydrogen. Somehow

    Basically i think that he have a greater energy output because he is using the byproduct of the combustion to break the water molecule and at the same time to behave as a two combustible system. Hydrogen and amonia...

    or maybe nitrogen hydroxide have a lower voltage limit than 1,24v...

    Regards

    Leave a comment:


  • vrand
    replied
    Originally posted by tutanka View Post
    Fabio,
    The process is more simple.. no metal catalyst are needed, I don't use injector system I create gas outside of engine. Regards
    No metal catalyst is needed because a Magnet is used as natural EEC? Can a permanent magnet work, or need an electromagnet? A pulsed HV electromagnet?

    Regards, Mike R.

    Leave a comment:


  • Farrah Day
    replied
    Seb. OK, to me there is a logic in this reaction.

    I'm studying molecular and atomic physics in the university, and in the last class i had a discussion on my theory about creating oh oh instead of h2o as exhaust and they think that it is possible if we ionize the oxygen negatively adding to it 1 electron because it would fill one of the 2 holes of the oxygen, allowing only one hydrogen to bound per oxygen atom. Thus combusting the hydrogen with more oxygen than that from electrolysis... Actually i thought that if we could fill both holes we would not allow the reformation of the H20.
    However, it begs the question why would you want to end up with the OH- hydroxyl ion rather than water? What purpose would this serve?

    edit: changing question...

    If you break n2's triple bond, what does it try to attract to itself in that state?

    If that atomic nitrogen is in the presence of atomic hydrogen, can nh3 form?

    If n2 is split is the atomic nitrogen an ATOM of nitrogen, ION of nitrogen or both
    at the same time?
    For the same reason it has the affinity to form the molecule in the first place, it wants to fill it's outer shell with electrons to stabilize. Just as hydrogen and oxygen atoms will quickly reform into H2 and O2 molecules. When ozone is formed, by a molecule of oxygen dissociating and each atom joining with another O2 molecule to form O3, ionisation is not occuring. It effectively breaks cleanly into atoms. O3 is not an ion.

    A nitrogen molecule can only dissociate into two atoms or two ions, not both, unless you provide a way of adding or extracting electrons.

    If nitrogen ionised so that we had N+ and N-, the hydrogen affinity would logically produce NH4+ and NH2-.

    The only way to get ammonia is by the reactions of atoms N and 3H.

    Of course if any ionising does occur anywhere in the process, then reactions will be different.

    But because the ionisation levels of oxygen and hydrogen are lower than that of nitrogen, clearly nitrogen would be the last gas to ionise, unless it was separted from air in the first place.

    I'm unfamiliar with the resulting energy released when nitrogen recombines into molecules, but if it is proportionally similar to the recombination of atomic hydrogen, then this reaction alone might prove to be the best source of energy. After all, unlike H2, we don't have to use energy producing the N2 in the first place - we're surrounded by the stuff.

    Could it be that ammonia is simply a useful by-product of atomic nitrogen recombing into molecules? But this would of course mean still going to the trouble of producing at least some H2... the mystery goes on.

    Of course Tut apparently has all these answers, so it's a little frustrating for us all to have to play this guessing game. But I daresay it's what we've all come to expect.

    Are you using a plasma arc somewhere in your process Tut?

    Regards, Farrah
    Last edited by Farrah Day; 05-03-2010, 07:57 AM.

    Leave a comment:


  • sebosfato
    replied

    Leave a comment:


  • tutanka
    replied
    Fabio,
    The process is more simple.. no metal catalyst are needed, I don't use injector system I create gas outside of engine. Regards

    Leave a comment:


  • Aaron
    replied
    @Vickers

    Originally posted by Vickers
    I mean your drawing my friend. Can buy a nascent? plug in any auto parts store.
    The nascents aren't available now. That plug belongs to other people,
    not myself.

    What drawing are you talking about?

    Leave a comment:


  • sebosfato
    replied
    Lithium nitride reacts violently with water to produce ammonia:

    Leave a comment:


  • tutanka
    replied
    Originally posted by sebosfato View Post
    However if we think that we are again, charging the oxygen positively lets say leaving it with a deficiency of 1 electron we would have H3O+ formation witch would be more likely to be what meyer said because it would lead to the formation of half the molecules of water used as output. Witch would also relate to a decrease in mass!!! A huge decrease, as oxygen represents the 88% of water weight! This would generate oxygen too! but would really consume the water! than water would evaporate receive sun rays and bound with other oxygen becoming water molecules stable again..
    How about this tutanka???

    The H3O+ ion getting inside the water become an electrolyte... maybe??
    Meyer create ions with steam resonator but I have found another simple solution, in all case you need to create controlled chain reaction using right water and right sequence of process ionization. The theory on nitrogen atomic is correct, that bond simply when found atomic hydrogen atoms. Regards

    Leave a comment:

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