Captret - Perpetual Light with Dead Batteries

[electricity]

Large Captret

You guys need large capacity to see fast result.

No less than 200v - 50000 uf is ideal to charge dead 9v

I have ran my 4 gallon captret and also a 5 gallon captret.

You can light 4 cfls @ full brightness perpetually, pics to follow soon.

[LaserSaber]

What is size of source Cap? I might have missed in video. Three caps in captret array are what?

I think the source cap was a 1000uf 100v Capacitor. The others are all less than 300v 400uf. I did the same setup once using only 1000MFD 35VDC caps. Link: It seemed to work just as well.

[LaserSaber]

The question "is this free energy" is carried over from my previous video. It's just the question that is driving my research on the Captret at the moment. I will rename the video to cut down on possible confusion.

[gmeast]

size

Testing the Captret: is this free energy? Part two: YouTube - Testing the Captret: is this free energy? Part two.

Nice LS,

What is size of source Cap? I might have missed in video. Three caps in captret array are what?

Thanks.

Greg

[Jbignes5]

I highly doubt that it is free energy in that setup..

Testing the Captret: is this free energy? Part two: YouTube - Testing the Captret: is this free energy? Part two.

Without a source of steady potential I doubt you have free energy but you do show that once the led is on it will run for a long time on the potential differences of the plates and the hull.

Leds are pretty much super efficient at converting potential into light with little current requirements at the lumens were are getting.. Thats why we are getting the results we are getting with a source of potential like a dead battery. It settles into a comfortable low current that can be provided by a cyclic flow of potential that is created by the cap and led plus the additional virtual diodes with one being for each plate in the original version of the circuit. Since you have proven that it indeed charges a cap in your first experiment then I would say that this is a verified effect. Weather it comes from the rebound effect of the cap or not it is a good effect none the less.

We could figure out eventually that having multiple caps in parallel and switched from cap tp cap to collect the rebound energy into another real cap in the normal method could net us a gain but I think it would be to small of an increase to net much unless we had 100's of them running in parallel.

[LaserSaber]

Testing the Captret: is this free energy? Part two: YouTube - Testing the Captret: is this free energy? Part two.

[gmeast]

hovering here

16 VDC, 60,000uF electrolytic
9V NiMH Battery
Red clip on DVM Common (black) is "o"

393.5 mV: It's been floating around this number for quite a while.

Perhaps a bunch of these in series can provide enough to charge a cap and flash an LED ... maybe.

I will also run this without the "o" to see if the effect is REALLY just the Cap restoring itself (by whatever mechanism, as they already do without the "o")

http://02d1852.netsolhost.com/radiant/big_cap.jpg

Greg

[ibpointless2]

Here is the latest captret i've been working on. battery started with 6.31 volts but now is up to 6.37 volts . The other battery voltage went up to 1.661 volts but has been dropping and is now at 1.122 volts. Whats weird about his circuit is that higher charge battery should be the one going down and the lower charge battery should be going up so that they would equal themselves out, but the opposite happens.

The voltage in the capacitor - and the + are also going up too.

I'm thinking about replacing the lower battery voltage one with a super cap to see if i get the same effect.

The lower voltage battery's negative terminal becomes the positive and the higher battery negative terminal becomes the negative.

[ibpointless2]

A fully charged capacitor is not infinite resistance like what your meter would say, over time it becomes negative resistance.

I'm seeing negative resistance with the capacitors(captrets) and that is the reason why the batteries are charging.

Think of it this way, the cap is filling up and the amps are going down. The amps get to zero and the meter says infinite, because 0 times anything is 0 (ohms law). But our number system doesn't stop at 0 it goes into the negatives. So if it goes into the negatives then according ohms law at 12 volts time -1 amps equals -12 watts, and negative resistance equals negative watts which means a charging effect is happening.

[Jbignes5]

from my experience...

Also, I may be mistaken but the LED seems to have gotten slightly brighter. Might just be me since I see the battery Voltage increase. But if the Voltage is increasing wouldnt the LED brightness increase as well?

Usually in my experience the led gets dimmer as the higher the battery charge. This has to do with a build up on the negative plate of the capacitor(s).

My next question had to do with running other stuff besides the leds. I suppose transistors run then from your description?

My thought was to run a transistor into a coil to boost the voltage? then apply that back to the battery.

[miki02131]

Hey Guys,

I have some good news for the serious experimenters. I have a few Soda Can size Military grade capacitors I would like to make available for cheap. Actually, your biggest expenses would be the shipping cost. Contact if you're a serious researcher and interested: [email protected]

I will show pics before any offer. I have a varity between 30 and 50 rated capacity ranging from 3500mF to 20000mF and 20V to 250V.

Miki Out.

[redrichie]

Also, I may be mistaken but the LED seems to have gotten slightly brighter. Might just be me since I see the battery Voltage increase. But if the Voltage is increasing wouldnt the LED brightness increase as well?

[redrichie]

I will post a video when I find the cable to my camera. Here is my experiment for the evening:
Captret running 1 200V 1500uF cap. The captret is powering a Joule Thief, that is driving an LED. When tunning The Joule thief I get the LED to flash brightly about 1-2 times per second, or continuous light. The LED is not a full brightness when in continuous light.
The source is a dead 12V SLA. I am using an analog meter to measure the Voltage at the battery. Which has went up almost a Volt in 2 hours. (.9V). While this may not seem all that impressive, what is strange is the Amp draw. In order to get the best charging I have to tune to a higher amp draw of 8 miliamps. However, The Amp draw has decreased over the last 2 hours at the same rate as the Voltage on the run battery increases. It went from 8mA to right at 6mA and dropping. the LED has not changed in brightness. The battery seems to be charging and the circuit is drawing less current as time goes on. Battery and capacitors and all wires are running cool. The transistor is cool as well.
The amp draw has decreased to 5.95mA since I started typing this message.

[ibpointless2]

Anyone else notice when you take a captret thats been used and short out the + and the - leads of the cap with the top of cap, and disconnect them it always bounces back up to some voltage. This is the electret part of the captret that i found out when i first was playing with the capacitors.

[Jbignes5]

well...

ok so the new caps take a bit to condition or build up these diodes inside of them. My 8 pack 220uf 100v finally is heating up a new Superbright led. 3995 mcd 5mm white 3.7Vf@20ma. This thing is so bright it is hard to look at. Also like I said it is getting warm to the touch. The 12v 12ah battery I have is running this beast and is getting back up there on charge. 10volts as we speak. Now to see if I can push this new 8 banger to the max.

I picked up two of the super bright leds @20 ma each. right now it doesn't matter if I use one or two they seem to be the same brightness. When I put two on the heat disappears and run cooler. Weird...