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  • Aaron
    replied
    @Pranav

    Hi Pranav,

    The 10ohm 250w should be ok. I really don't know what the difference would
    be from my 110-120v wall compared to your ac wall supply - if you have
    220-240v?

    Anyway, it should work.

    Your diodes should work too but it depends on the polarity of your
    ignition coil. If the hv is negative then you need to simply reverse the
    diodes from hv to primary +.

    Looking forward to your test!

    Leave a comment:


  • pranav2010
    replied
    power resistor

    hi aaron

    i am also using wall power to charge my cdi cap 47 uf. i mix low vol with the high vol i put diode primary + to secondary + just like you

    now I am thinking about power resistor I am going to use 10ohm 250watt

    is this ok ?????

    have wonderful day

    Leave a comment:


  • Aaron
    replied
    power resistors

    Hi Pranav,

    I used eight 10 ohm resistors. They were
    in series and parallel. So 2 in series was 20 ohm
    and I had 4 of those in parallel. I think the
    watt rating of them were 100w.

    It is possible they were 100 ohm resistors, I'll
    check later. In any case, yes, they will get hot
    and melt the solder.

    I have some really large inductive resistors that
    are 10 ohm 250 watts and I would use one
    of those if I charged from wall power again.

    Do you have access to an off the shelf CDI for
    auto ignitions? If so, you can charge the cdi cap
    from that and have that cdi connected to a car
    battery with no problems.

    I charged a cap from the wall for simplicity sake
    so I didn't have to build a real circuit.

    But if you have a CDI, that is preferable. The CDI
    will have a cap around 4uf and 400~600 volts,
    which is usually not enough to get the effect with
    the booster caps. However, with the diode from
    primary to HV on ignition coil you are getting plasma
    two times.

    One is a small plasma burst from the CDI + diode
    setup and the other is to mix that with the booster
    cap. So you're using a smaller plasma to trigger the
    larger plasma.

    The other reason I used wall supply was because
    the cap was 47uf, which is more than 10 times the
    size of one in a CDI unit and wanted to make sure
    it was instantly charged at any speed. Again, the
    wall was for convenience but I'd use a cdi if I did
    it again.

    Leave a comment:


  • pranav2010
    replied
    power resistor

    hi aaron

    can you tell me what is the value of your resistor ?????

    have wonderful day

    Leave a comment:


  • pranav2010
    replied
    power resistor problem

    hi aaron

    i am using 100 ohm 10 watt resistor but while turning circuit on resistor getting heat and after few second it will bust

    your circuit is workig very well but problem is resistor

    now i am going to use 100 ohm 100 watt

    what do think will it work properly

    please reply

    have great day

    Leave a comment:


  • pranav2010
    replied
    test

    hi aaron

    thanks for best wishes

    i will post pic and vid

    have wonderful day

    Leave a comment:


  • Aaron
    replied
    good luck on your test!

    Hi Pranav,

    Good luck on your test! 27 sounds a little small but you can try it out.

    16uf at 1000v would be quite a punch. if you have 1000v at a couple uf,
    might be a safer test.

    Anyway, sounds like you know what you're doing.

    Looking forward to some pics or vids!

    Leave a comment:


  • pranav2010
    replied
    electromagnet

    hi aaron

    i am trying to build 9 stator 3 rotor setup.

    my coil is 125mm length and it has 1000 turns of 27 awg
    my core is transformer lamination it is "I" shape 40mm*50mm size

    tomorrow i will test the circuit i will post video on our thred

    what do you think is everything ok????????

    thanks for reply

    have a great day
    Last edited by pranav2010; 11-24-2010, 07:09 PM.

    Leave a comment:


  • Aaron
    replied
    Pranav's circuit

    Hi Pranav,

    The circuit looks correct. 16uf looks pretty big but should work.

    What size wire are you using for an inductor? What are all the dimensions
    of it, turns, etc...? Core diameter/length, etc...? On a few of my tests
    when I went too much on the voltage, I was sparking through the
    insulation.
    Last edited by Aaron; 11-24-2010, 06:12 PM.

    Leave a comment:


  • pranav2010
    replied
    reply

    hi aaron

    i am wating for your reply

    please reply

    Leave a comment:


  • pranav2010
    replied
    modification

    hi aaron

    thanks lot

    i use 25 amp 1200 volts scr

    16uf means i use 2uf 2kV caps 8 in parallel

    i use all high voltage diode 1x3

    i wrote all details of my circuit on diagram please tell me is every think is ok

    one more time thank you
    Last edited by pranav2010; 12-03-2010, 03:27 PM.

    Leave a comment:


  • Aaron
    replied
    @Pranav

    Pranav,

    This will work - this is virtually identical to what I did.
    Now of course, your goal with this setup is not efficiency at
    the moment but to learn the method first.

    For the capacitor charger on the front end, I would move
    towards an off-the-shelf CDI and add the HV diodes in the
    right direction according to the polarity of your ignition coil.

    If your coil has a negative polarity, then reverse the HV diode string.

    Leave a comment:


  • Aaron
    replied
    revision

    Pranav,

    Your cdi power supply - with full bridge, your scr probably won't turn off,
    start with half rectification. And you may need some power resistors on
    the negative coming off the bridge to limit the current.

    You also need HV diodes from the primary + to the HV +.

    Remove the capacitor that the HV output is connected to. If you do not
    have enough punch, that cap will eat up everything and it will not jump
    the gap. You can try to add that later but leave it out for now.

    Make sure your bridge from the MOT is a 2k or 3k bridge.

    Make your points geometry just like in the Mark McKay drawing. You MUST
    force the HV to hit the LV before it can go to the load/grid point.

    Please redraw it with the above changes and I'll look at it.

    Leave a comment:


  • pranav2010
    replied
    circuit modification

    hi aaron
    please tell me will it work ???

    you are right i found this Mark McKay collection.
    Last edited by pranav2010; 12-03-2010, 03:27 PM.

    Leave a comment:


  • Aaron
    replied
    comments on circuit

    Hi Pranav,

    I would move the SCR to the negative side of the ignition coil primary.
    That way the positive potential of the cap is already inside the coil
    when you switch the SCR. On the positive side, the positive potential
    has to move into the resistance of the windings. I believe it is also
    the standard way of doing it - switching it on the negative.
    However, this should not prevent it from working - but I would switch
    on the negative.

    Your reed is just connecting the trigger of the SCR to ground but you
    need a positive potential there. You show Battery + there so I'm not
    sure if that is what you mean, please clarify. In any case, move the SCR
    to the ground and put the reed across the anode and the gate and you'll
    want to put a resistor between anode and reed.

    With the SCR, if your cap is not discharging enough on each cycle, the
    SCR will not turn off and will remain conducting. From an AC source to your
    cap - for example, if there was a full bridge, that SCR probably won't turn
    off, with half bridge, the SCR will turn off. With the voltage doubler, I'm
    not sure if the cap is able to discharge enough to shut off the SCR. I think
    you are getting 120hz (if you are on 60hz) and that may not allow the SCR
    to turn off. That has been my experience.

    Also, your CDI cap is 200v but I think you should have at least a 400v
    cap so you don't blow it up. You have 120uf on the CDI cap and that
    capacitance should work but I think that is quite a bit to discharge into
    an ignition coil. Again, will probably work at that capacitance because I've
    done it with more but since you have 1000v 2uf booster cap, you can use
    quite a bit lower uf on the cdi cap. I would do 47uf max and you can
    probably get away with as low as 4uf but I'd probably do 10uf~47uf
    range for the CDI cap for this application. And charging a CDI cap from
    the wall, you may want a serious power resistor between the AC and
    ground of cap.

    It is optional, but you could put some HV diode(s) from the HV output
    of ignition coil to the gap. That would prevent any feedback into the HV
    windings from anywhere else.

    Your 3 point gap arrangement looks good. Forcing HV to hit LV before
    hitting grid point.

    On your low voltage source, make sure to use at least a 2kv or 3kv
    bridge if you want 1kv out of it. It will let the microwave oven transformer
    work easier. Common ground looks good.

    On the trifilar, actually only a bifilar is needed. I used a trifilar because that
    is what I had freed up. The recovery winding can be in the same direction
    or opposite. If you check the last weeks posts in the Renaissance
    conference thread, you can see some discussion on the reverse wound
    concept. If you do happen to use a trifilar, do NOT connect the 26 and
    23 gauge (trigger and power) winding in parallel. This slows the decay
    rate of the magnetic field and you want it fast. At least at this point.
    There are some interesting properties to paralleled coils but that should
    be explored later and not when getting it to run.

    Is this the diagram that Mark McKay drew up? Anyway, please make the
    above changes to this diagram and let's move to the next step. Show
    me the changes and I want to double check it before you try it.

    The SCR issue is probably the main reason why it is not working for you.
    If you just put that to the negative side, invert it of course, and put
    reed between anode and gate.

    Leave a comment:

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