Originally posted by citfta
View Post
Bob Smith,
Originally Posted by Bob Smith View Post
I am watching this topic with interest here and on a couple of other forums. I have been working with a set of three series-wound bifilar pancake (swbifip) coils for about a week. My focus is on the interaction between the swbifip coil and the local electrostatic environment.
If I am not mistaken, an inductor pulsed below resonant frequency will be dominated by resistive reactance, while pulsed above resonant frequency, capacitive reactance dominates. In simplest terms, below resonance, the inductor behaves like a resistor, and above resonance, begins to behave like a capacitor. At resonance, neither predominates.
However, given the low reactance and high capacitance of the swbifip coil due to its configuration, what actually happens to its capacitance (let alone reactance) at resonance?
I'm going to throw out a thought - if reactance in an inductor drops to zero at resonance, and we transpose this understanding to the swbifip coil, is it possible that at resonance, its extremely low reactance might drop below zero, effectively giving it negentropic characteristics of a negative resistor?
There are some decent YT videos out there showing a rise in voltage amplitude at resonance in this coil. Is it another animal entirely, for which another set of parameters has to apply?
Bob
First thing is you have a couple of things slightly confused. Capacitive reactance goes DOWN as the frequency goes UP. Inductive reactance goes UP as the frequency goes UP. So below the natural resonant frequency of a coil the reactance will be capacitive and above the resonant frequency the reactance will be inductive. And you are correct that at the resonant frequency they both cancel each other out and the result is that only the DC resistance remains.
I have not seen any evidence that the reactance can drop below zero. If you can link a video or other evidence showing that I would like to see it.
The only real difference in the bifilar series connected coil and a normally connected coil is the added capacitance of the bifilar coil. It also makes no difference if the coil is a pancake coil or a normal solenoid type coil the extra capacitance is still there if the coils are bifilar. Several tests were done on the OU.com site that confirm this.
The added capacitance of the bifilar wound coil is that it allows the coil to be resonant at a much lower frequency than a normally wound coil. As was pointed out on the OU site at the time Tesla was working with high voltages and high frequency, capacitors that met those requirements were hard to make and so Tesla was looking for a way to make a coil resonant without the need for capacitors and thus came up with the bifilar wound coil. Now high voltage capacitors are fairly easy to come by so the need for bifilar wound coils is not as great. They are still an interesting device for studying resonance and especially for learning about inductive and capacitive reactance.
I hope this helps some.
Respectfully,
Carroll
Originally Posted by Bob Smith View Post
I am watching this topic with interest here and on a couple of other forums. I have been working with a set of three series-wound bifilar pancake (swbifip) coils for about a week. My focus is on the interaction between the swbifip coil and the local electrostatic environment.
If I am not mistaken, an inductor pulsed below resonant frequency will be dominated by resistive reactance, while pulsed above resonant frequency, capacitive reactance dominates. In simplest terms, below resonance, the inductor behaves like a resistor, and above resonance, begins to behave like a capacitor. At resonance, neither predominates.
However, given the low reactance and high capacitance of the swbifip coil due to its configuration, what actually happens to its capacitance (let alone reactance) at resonance?
I'm going to throw out a thought - if reactance in an inductor drops to zero at resonance, and we transpose this understanding to the swbifip coil, is it possible that at resonance, its extremely low reactance might drop below zero, effectively giving it negentropic characteristics of a negative resistor?
There are some decent YT videos out there showing a rise in voltage amplitude at resonance in this coil. Is it another animal entirely, for which another set of parameters has to apply?
Bob
First thing is you have a couple of things slightly confused. Capacitive reactance goes DOWN as the frequency goes UP. Inductive reactance goes UP as the frequency goes UP. So below the natural resonant frequency of a coil the reactance will be capacitive and above the resonant frequency the reactance will be inductive. And you are correct that at the resonant frequency they both cancel each other out and the result is that only the DC resistance remains.
I have not seen any evidence that the reactance can drop below zero. If you can link a video or other evidence showing that I would like to see it.
The only real difference in the bifilar series connected coil and a normally connected coil is the added capacitance of the bifilar coil. It also makes no difference if the coil is a pancake coil or a normal solenoid type coil the extra capacitance is still there if the coils are bifilar. Several tests were done on the OU.com site that confirm this.
The added capacitance of the bifilar wound coil is that it allows the coil to be resonant at a much lower frequency than a normally wound coil. As was pointed out on the OU site at the time Tesla was working with high voltages and high frequency, capacitors that met those requirements were hard to make and so Tesla was looking for a way to make a coil resonant without the need for capacitors and thus came up with the bifilar wound coil. Now high voltage capacitors are fairly easy to come by so the need for bifilar wound coils is not as great. They are still an interesting device for studying resonance and especially for learning about inductive and capacitive reactance.
I hope this helps some.
Respectfully,
Carroll
Thanks very much for this. I'll make the corrections this evening.
Bob



Leave a comment: