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Captret - Perpetual Light with Dead Batteries

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  • dragon
    replied
    I had the cap connected to the + lead and holding the + of the LED with the same clip, while holding the neg side of the LED lead to the cap neg by hand I grabbed the neg side of the battery to connect it to the can and it lit right up. Ground connection was made through my body. Strange to see that low of voltage causes the same effect as connection to the can portion of the cap. Maybe an earth ground could be incorporated to remove the battery completely.
    ________
    Vaporizer Review
    Last edited by dragon; 05-11-2011, 10:59 AM.

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  • sseti
    replied
    ibpointless2

    Its your diagram, I just show how to disconect cap+


    Hmmm?
    how to upload picture?

    instead of bat + going to cap + and than to led + , you yust connect bat + to led + and cap + leave in air.
    I think that will do
    Last edited by sseti; 11-08-2010, 09:40 PM.

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  • sseti
    replied
    Also had put a cap 1F @ 5.5 instead of 9V battery, but voltage has been gone
    down (slow but id does). I noticed best results with low volt caps and high uF (in my case 6,5V@2200uF) shown in light brightnes and current drawn

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  • ibpointless2
    replied
    Originally posted by sseti View Post
    Did anyone noticed the same effect when cap + is disconected from the circuit?

    What do you mean? can you draw a diagram?

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  • sseti
    replied
    Did anyone noticed the same effect when cap + is disconected from the circuit?

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  • ibpointless2
    replied
    I used 10F @ 2.3 volt super caps. It took about 30 minutes for the LED to show light, My LEDs turn on at about 1.5 volts across the + and - of the super cap.

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  • Zooty
    replied
    Originally posted by ibpointless2 View Post
    I just tried using a super cap. The LED didn't turn on right away but slowly came on and is still getting brighter. The 9 volt battery is a new one that is slowly charging up while the the power inside the super cap builds up and as the super cap builds up the LED lights up more!
    What spec is your supercap?

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  • Zooty
    replied
    Just ran the experiment and i am getting the same results. Can't say if the battery is charging or not because it might just be bounce back from the initial charging of the cap but it has gone up a couple of millivolts. Current draw from a 12v 2.3ah battery is 0.09ma and the voltage across a 3v blue led is 2.4v. The led is not really bright but its definitely lit. I am also getting the AC voltage in one direction across the led and cap top and the 50hz signal on the scope. Interesting experiment.

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  • ibpointless2
    replied
    I just tried using a super cap. The LED didn't turn on right away but slowly came on and is still getting brighter. The 9 volt battery is a new one that is slowly charging up while the the power inside the super cap builds up and as the super cap builds up the LED lights up more!

    Leave a comment:


  • rave154
    replied
    batery at 12.67V now...amp draw 0.220 mA

    tried the "earth" connection at al places on the circuit..no change

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  • rave154
    replied
    ok,

    decided to start again with a fresh new cap ( same value 10 uF )..same battery started at 12.63V

    batt now at 12.65V..drawing 0.580mA and dropping

    i was pondering, wether to also have the top of the cap.connected to a "ground" in the house?


    also have attatched a scope shot... 100mV per div....4mS per div time scale..definitely 50Hz
    Attached Files

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  • ibpointless2
    replied
    Originally posted by broli View Post
    This is one of the first things I measured. When measured stand alone it starts around 1M ohm and goes up in a few seconds out of range of the meter. If you let it rest for a bit it can start from 400k ohm and go out of range.

    However when you have used it in the above mentioned circuit it starts out negative goes through zero and starts to rise and go out of range over quite a bit of time.

    Also for a more accurate light intensity reading it's best to use a photodiode:
    Measure Light Intensity using Photodiode : Low Cost USB DAQ
    I think its more than just a resistor, there is some strange things happening; like how it starts negative and goes to zero and into out of range. It being a resistor wouldn't explain the increase in voltage when read in AC mode of the meter. A resistor would drain the battery but other like me have experienced the voltage go up on a battery. The captret is very unique and i think i may have something here.

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  • broli
    replied
    Originally posted by miki02131 View Post
    You might be able to tell for sure whether this captret effect is really an open system effect by measuring the resistance between the [O] lead and the [-] lead. If the resistance is infinite then you have discovered something big. If that resistance is in the megohms, then this circuit is simply equivalent to power up an LED through a few megohms resistor. In the latter case, there may not be too much hope in this effort.

    Miki Out.
    This is one of the first things I measured. When measured stand alone it starts around 1M ohm and goes up in a few seconds out of range of the meter. If you let it rest for a bit it can start from 400k ohm and go out of range.

    However when you have used it in the above mentioned circuit it starts out negative goes through zero and starts to rise and go out of range over quite a bit of time.

    Also for a more accurate light intensity reading it's best to use a photodiode:
    Measure Light Intensity using Photodiode : Low Cost USB DAQ
    Last edited by broli; 11-08-2010, 07:23 AM.

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  • rave154
    replied
    measured the resistance as asked.csame to just over 1Mohm

    also..went back to only 1 LED after briefly trying 2.now drawing 0.113 mA...battewry at 12.68V

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  • miki02131
    replied
    You might be able to tell for sure whether this captret effect is really an open system effect by measuring the resistance between the [O] lead and the [-] lead. If the resistance is infinite then you have discovered something big. If that resistance is in the megohms, then this circuit is simply equivalent to power up an LED through a few megohms resistor. In the latter case, there may not be too much hope in this effort.

    Miki Out.

    Leave a comment:

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