What is hung in such educational books does not in any way reflect the real movement of current. In the experiment, there was just a divider effect (voltage reduction system)
Take half the period of the voltage sine wave and see how it looks in all areas. Do not forget that this transformer has a zero terminal, it always has zero.
The ratio of EMF values is expressed by the formula: E1 / E2 = w1 / w2 = k, where E is the EMF, w is the number of turns, k is the transformation ratio.
Considering that the voltage drop in the transformer windings is small, it can be ignored. In this case, the equalities: U1 = E1; U2 = E2 can be considered fair. Thus, the above formula becomes: U1/U2 = w1/w2 = k, that is, the ratio of voltages to the number of turns is the same as for a conventional transformer.
Without going into details, we note that the ratio of the current strength of the upper coil to the load current, as for a conventional transformer, is expressed by the formula: I1/I2 = w2/w1 = 1/k. It follows that since in the step-down transformer w2 < w1, then I2 < I1. [In other words, the output current is much less than the input current.] Thus, less energy is spent on heating the wire, which allows the use of smaller wires.
Considering that the voltage drop in the transformer windings is small, it can be ignored. In this case, the equalities: U1 = E1; U2 = E2 can be considered fair. Thus, the above formula becomes: U1/U2 = w1/w2 = k, that is, the ratio of voltages to the number of turns is the same as for a conventional transformer.
Without going into details, we note that the ratio of the current strength of the upper coil to the load current, as for a conventional transformer, is expressed by the formula: I1/I2 = w2/w1 = 1/k. It follows that since in the step-down transformer w2 < w1, then I2 < I1. [In other words, the output current is much less than the input current.] Thus, less energy is spent on heating the wire, which allows the use of smaller wires.
I think this phrase is enough not to think that more than I calculated was put on the generator rotor. The СOP ratio is maintained.
https://rakatskiy.blogspot.com/2022/...ransducer.html
An autotransformer efficiency of 99% can only be achieved with a small difference between the input and output voltages.
In the experiment 220/117 = 1.88 (almost double the difference), thus no more than 0.6 [45 W (in) * 0.6 = 27 W (out)]
I think the rest of the discussion doesn't make sense anymore
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