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Confirming the Delayed Lenz Effect

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  • smoky
    replied
    Hi Farmhand & Muon,
    There is a couple of ways to do this without increasing frequency.
    One is to bring the secondary into resonance. Trouble is when power is removed from the circuit it loads down the resonance effect, real power then starts to exceed reactive power. Also with parallel resonance output volts goes through the roof & arcs over inside transformer.

    The second method is to delay the magnetic field created by the primary from getting to the secondary by one quarter of a cycle.
    I am experimenting with this method.
    At 50Hz... it's 5 millisecond delay required, cause one cycle at 50 Hz takes 20 milliseconds for full 360 degrees or one cycle to complete.

    Tesla used the delay method in his US Patent 433702 (in year 1890, a nice easy read too).
    He wound a thin shield of insulated steel wire between the transformers' primary and secondary windings, he left the ends unconnected. Only using magnetic properties of the steel. ie Shielding at first then when saturated field lines pass through same as in air.

    I hope this helps...Gerry

    Leave a comment:


  • Farmhand
    replied
    Oh yeah my transformers work at about 420-440 khz resonant so they produce
    a sine wave, I would measure the real power used by the output transformer but
    it is connected to the generator transformer by only one wire so I can't measure
    input voltage. But I do know it can be adjusted to send most of the reactive
    power back to the source, or build it up in the output transformer. When the
    reactive power is built up in the output transformer the input is more at idle and
    less when loaded.

    When the reactive power is sent back it is less at idle and more when loaded.

    That's how I explain it in simple terms. Maybe I'm a bit off but it makes sense to me.

    Cheers

    Leave a comment:


  • Farmhand
    replied
    Originally posted by smoky View Post
    Simple way to double frequency is to pass sine wave through a full wave bridge. 4 Diodes. It aint pretty but it is double!
    I don't think it will work without using a sine wave. Not 100% certain of that though.

    Which is another thing because OUG's Sine wave from the frequency drive
    controller is a made up sine wave not really pure. And on top of that the
    frequency drive controller increases voltage to the transformer at the higher
    frequency, I think to try to overcome the impedance, Not sure i'm not familiar
    with how they work or exactly what they do. Nifty bit of kit but I don't see many experimenters with one.

    Cheers

    Leave a comment:


  • smoky
    replied
    Simple way to double frequency is to pass sine wave through a full wave bridge. 4 Diodes. It aint pretty but it is double!

    Leave a comment:


  • Muon
    replied
    Then if it takes 18.8 watts to run idle at 950 Hz and 18.5 watts loaded, so a
    .3 watt drop. That's 18,5 watts power paid for, the watt meter says so,
    that's real power.

    So regardless of the drop when loaded more real power is used at 950 Hz to
    power the load than at 200 Hz.

    The extra idle power required to run at 950 Hz as compared to 200 Hz is
    where the power comes from there is no free energy or unpaid for energy.

    Only if the load power exceeds the total power paid for after the wall socket
    can it even be called getting it for free.
    Makes sense... What I'd like to see is whether the watt-meter will work AFTER the frequency-increasing-device. That way, the power actually used in the transformer - with and without load - can be observed directly.

    Is there another way to increase the frequency than using this fancy device? OR -- better -- is there a transformer that will show the delayed-Lenz effect at 50 Hz?

    Nice work, BTW, overunityguide! I enjoyed the vid and appreciate your efforts.
    Steve

    Leave a comment:


  • Farmhand
    replied
    Originally posted by wojwrobel View Post
    NO ! but the meter will not see (read) this power, unless you have reactive power meter , some factories pay extra for reactive power but they have special meters

    power still flows, so if he can switch meter to show not watts but ampers it souldn't change with frequency or sould increase rather than drop!



    anyway i have been testing new idea !

    coil have capacitance right, so its stores energy even when not connected to load (but not in form of magnetic field because this requires current flow) but in bettween the wires i think or core

    so what i do is im connecting load to coil just after magnet pass the coil !
    and whats intresting there is power on meter !!

    im not sure if the power is stored momenterli in coil or core has its own hystherisis delay???

    give it a try its preety intresting

    cheers from poland
    wojsciech

    Hi wojsciech, It seems people still don't get it. If it takes 17 watts to run idle
    at 200 Hz and 17.5 watts loaded at 200 Hz. That's 17,5 watts power paid for,
    the watt meter says so, this is real power.

    Then if it takes 18.8 watts to run idle at 950 Hz and 18.5 watts loaded, so a
    .3 watt drop. That's 18,5 watts power paid for, the watt meter says so,
    that's real power.

    So regardless of the drop when loaded more real power is used at 950 Hz to
    power the load than at 200 Hz.

    The extra idle power required to run at 950 Hz as compared to 200 Hz is
    where the power comes from there is no free energy or unpaid for energy.

    Only if the load power exceeds the total power paid for after the wall socket
    can it even be called getting it for free.

    And if they were to make their own AC power how could it possible help to
    use more real power, only to regain a small portion of it.

    To be a real efficiency improvement it needs to cause less power to be used
    from the source, the real source of the AC power.

    It's a trick and it means very little. I can do it too, it's no big deal. I can get
    bigger reductions in input power, (which loads the source less), while using
    more load power from a setup already running a load. I can do the same
    effect with different loads. And I'm measuring current with a .1 ohm resister
    so less effect is from the resister. Using a 10 Ohm resister further restricts
    current, especially when you add 10 ohms to a primary coil.

    It's like robbing Peter to pay Paul. No free energy at all. I can make my setup
    work the other way too, use very little at idle then draw power when loaded.
    Again no big deal.

    See here.

    Reduced input current under added load effects 33 - YouTube

    and here.

    Reduced input under load effects.wmv - YouTube

    I didn't bother to setup a neat demonstration because it does not warrant it.
    It's a trick.

    Cheers

    Leave a comment:


  • boguslaw
    replied
    Check if power is oscillating, damped wave. It's RLC circuit.

    Leave a comment:


  • Allen Burgess
    replied
    @eternalightwithin,

    He says he charges capacitors in 6 seconds to 200 volts, so there has to be some amount of amperage. The voltage is just right to run backwards into a MOT secondary, then have the higher amperage reactive current to use from the thicker wire primary. He appears to be running merely 2 LEDS off the output, so it can't be too much, but it's all gravy because the input's zilch.

    The important question is: Does FreeEnergy's 3rd Rodin output coil begin to power the spinner as a motor when placed under load? Also, the frequency can be controlled to match the 950 khz of the signal generator, the combintion of effects good chance for O.U.
    Last edited by Allen Burgess; 10-16-2011, 06:20 PM.

    Leave a comment:


  • eternalightwithin
    replied
    Originally posted by Allen Burgess View Post
    The spinner apparently accelerates with the addition of load off an extra coil winding in FreeEnergy26's video. The output winding generates 200 volts, while the input drops to a .8 of a milliwatt.
    What is the amperage of the output?

    Leave a comment:


  • wojwrobel
    replied
    Originally posted by Farmhand View Post

    Are you saying this whole setup is using less power at 950 hz than at 200 Hz ?

    Cheers
    NO ! but the meter will not see (read) this power, unless you have reactive power meter , some factories pay extra for reactive power but they have special meters

    power still flows, so if he can switch meter to show not watts but ampers it souldn't change with frequency or sould increase rather than drop!



    anyway i have been testing new idea !

    coil have capacitance right, so its stores energy even when not connected to load (but not in form of magnetic field because this requires current flow) but in bettween the wires i think or core

    so what i do is im connecting load to coil just after magnet pass the coil !
    and whats intresting there is power on meter !!

    im not sure if the power is stored momenterli in coil or core has its own hystherisis delay???

    give it a try its preety intresting

    cheers from poland
    wojsciech
    Last edited by wojwrobel; 10-16-2011, 09:00 AM.

    Leave a comment:


  • Farmhand
    replied
    Originally posted by wojwrobel View Post
    its not about power consumption its about IDEA

    and idea is to make cos(phi) as close to 90 degrease as posible then your poiwer meter will read almost zero power P=U*I*cos(phi)


    what he is doing is increasing the secondary coil inductive reactance by increasing frequency of primery coil to make cos(phi) close to 90

    but to have some extra work done and no power consumed you have to put your load and inductor in series so your load and inductor will have close to 90 degres this way meter will read almost zero power just reactive power for wich you dont pay!

    to calculate this use this site and insert your figures and adjust to have as close to 90 phase
    Resistor-Inductor AC Behavior
    Idea's are fine and good but I was just responding to the theoretical C.O.P. 18,
    When people write things like that, other people think there is 18 times the output to input.

    When the whole system is considered the the efficiency is very poor and the
    efficiency was made worse by "the delayed Lens effect". Was it not ?

    but to have some extra work done and no power consumed you have
    to put your load and inductor in series so your load and inductor will have
    close to 90 degres this way meter will read almost zero power just reactive
    power for wich you dont pay!
    I think most people can see it is a pointless exercise to increase power input
    by 1.5 watts so that when a .327 watt load is connected the input drops by
    .327 watts, just as an example.

    Are you saying this whole setup is using less power at 950 hz than at 200 Hz ?

    Exactly the same thing can be said about the motor generator setup lots of
    power is wasted to see the small decrease in input power, and yet they are
    saying they are making free energy ? They are making a complete setup less
    efficient and claiming that it is more efficient.

    The motor generator setup used an extra 16 watts or so to show a small
    decrease maybe 2 or 3 watts.

    This is really reducing the input and already running a load.
    Reduced input current under added load effects 33 - YouTube

    More efficient and the load is more.

    Cheers

    Leave a comment:


  • Allen Burgess
    replied
    Spinformer.

    @wojrobel,

    It would make more sense to generate the high frequency a.c. signal from a toroid spinner 3rd, rather than a costly signal generator and then to pulse a transformer primary with that signal. That way we can catch the advantage from both ends! Lenz propulsion and reactive power!
    Last edited by Allen Burgess; 10-15-2011, 04:41 PM.

    Leave a comment:


  • wojwrobel
    replied
    its not about power consumption its about IDEA

    and idea is to make cos(phi) as close to 90 degrease as posible then your poiwer meter will read almost zero power P=U*I*cos(phi)


    what he is doing is increasing the secondary coil inductive reactance by increasing frequency of primery coil to make cos(phi) close to 90

    but to have some extra work done and no power consumed you have to put your load and inductor in series so your load and inductor will have close to 90 degres this way meter will read almost zero power just reactive power for wich you dont pay!

    to calculate this use this site and insert your figures and adjust to have as close to 90 phase
    Resistor-Inductor AC Behavior

    Leave a comment:


  • Allen Burgess
    replied
    The input cost rises per Hertz in the MOT, but drops with the spinner due to BEMF. The input coil grows too highly charged from the spinner rotor working backwards as an alternator, to allow the inclusion of all but a very small amount of input. The MOT is just a linear drain on the drive side.

    High speed pulse coil spinners running close to COP=1, don't need much "Lenz Delay Propulsion" boost to achieve the Overunity "Holy Grail". Looks like "FreeEnergy26" has a couple of LED'S running along with their spinner practically free of charge! The vortex of the spinning magnetic field amplifys the propulsion from the booster coil.
    Last edited by Allen Burgess; 10-15-2011, 03:05 PM.

    Leave a comment:


  • Farmhand
    replied
    Originally posted by Allen Burgess View Post
    Here's a quote from OUG, it may help. He figures it's 18 times overunity!

    "Hello Guys,

    As I had promised, today I should supply you with my input / output cop measurements regarding my MOT 950 Hz Experiment... (I will advice you, hold on to your seat...)

    Input power going to the primary coil:
    Calculated by I2*R (R primary coil) = 0.1A*0.1A*1.8Ohms = 0.018Watts
    (This can be calculated this way, because the primary coil is running purely reactive at 950Hz)

    Output power secondary coil going to the LED Light Bulb:
    First I have to make a correction, in one of my previous posts, I have said that this value was about: 0.94Watts But Unfortunately after doing exact measurements with my scope on the secondary's connected load I had to conclude that it was actually running on: 36V at 0.0091A going to the LED Light Bulb, which gives us: 36V*0.0091A=0.327Watts going to the LED Light Bulb. (with the U and I running in phase)

    At the end this will give us a (theoretical) cop of: 0.327/0.018 = 18

    But I have to say, for now it only works on small loads... I also have tried connecting a 40Watts/240V rated incandescent light as a load with running the primary on higher (more dangerous voltage levels), and there no Lenz Delay was happening at higher power values... But for now it is a beginning of something new and unexplored...

    And further I have to mention, that of course in the MOT experiment my frequency drive controller is consuming a whopping 17.5 Watts only to run Idle. So when you compare this to the 0.327Watts at the output, I must agree that in this way there is no overunity yet... But of course my mostly inefficient frequency drive controller can be replaced with much better and efficient (at lower power ratings) Mosfet H bridge controllers. And further in the video you saw that when comparing the loaded state (18.5 Watts) compared to the primary coil disconnected state (17.5 Watts) Will give you a 1 Watt difference in required input power, which is of course also bigger than the 0.327 Watts output. But this has to do with the primary running purely reactive, for which there is in my MOT experiment no power factor correcting capacitor connected to my primary coil, which can be done in higher efficient replications of my MOT experiment also.

    So for now to conclude in short, my MOT experiment is showing that some interesting effects can take place in MOT like transformers running at a higher frequency. But for now I do think that a lot of experimenting (read: try to run on higher power values) needs to be done.

    My Related MOT Experiment can be found on:
    MOT Microwave Oven Transformer Delayed Lenz Experiment - YouTube

    And at gotoluc I would like to say: Good Work Dude...

    With Kind Regards, Overunityguide"
    OK since my question to Overunityguide went unanswered by him and the
    above quote was posted, I thought I would give my take on it by showing
    what is closer to the total efficiency. Really the power consumed to make
    available the AC wall power should be considered as well but that would be
    impossible so he gets the AC available for free.

    Since the Frequency drive controller is pretty much controlling the MOT and
    without the Frequency drive controller OUG's experiment would not have possible
    to be done the same way, just plugging it into the wall would not work to
    produce the effect, the frequency drive controller or something else would be
    needed to alter the AC power from the grid.

    Considering that I think at least all the power consumed after the wall socket
    should be factored into the efficiency calculation.

    I think these figure's are closer to the real efficiency and more applicable to
    show how the effect reduces efficiency from really bad to even worse.

    It uses at 200 Hz, 17.5 watts to power the load which uses 0.327 watts
    which is 1.86 % efficient.

    And at 950 Hz it uses 18.5 watts to power the 0.327 watt load
    which is 1.76 % efficient.

    So at 950 Hz his entire setup is less efficient to power a tiny load and it is
    less efficient than than anything I have ever before witnessed.

    He was actually able to make a 1.86 % efficient setup, even less efficient by
    a whole 0.1 %.

    Obviously at 200 Hz the MOT is more efficient as it should be because it was
    designed for 60 Hz.

    Cheers
    Last edited by Farmhand; 11-27-2012, 06:06 AM.

    Leave a comment:

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