Originally posted by Jetijs
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Ok, with the resistor where you placed it, it IS measuring BOTH the input current AND the output current. If the resistor had been about .01 Ohms, the wave-form would have been more of a linear ramp than the arching form you see. Never the less, it tells me what I want to know.
The rise-time of the inductance is filling the entire ON-TIME of your commutator.
What we want to do is cut the inductance by at least 75% so we can get about 4 times the RPM. So here is what I recommend.
Unwind the remaining wire from your coil. Take the three strands of wire and fold them in half. Cut all three strands at the half length. Then, take one set of wires and wind them onto a spool and set them aside. Take the other set of three strands and fold them in half again. Then cut them at this new half-way point. Now take all six strands and twist them together along the length until you have at least one full twist per inch of length. Then wind this twisted six wire group back on your core.
Wire up three of the wires to the transistors as the power coils and use the other three as isolated output windings with a common negative and a diode on the positive of each of the three windings. Connect the dedicated output windings to your output battery or light bulb.
This should give you about 60 turns on 6 strands of wire. The wire lengths should be approximately 1/4 the length of your current windings.
Please draw this up and post so I can see that you understand what I am asking.
Also, please remove the 0.5 Ohm resistor from the circuit. It has served its purpose and is too high a value to leave in place as the frequency and power levels rise in your model.
Peter



Thank you for your understanding.

The first time I was afraid that the whole thing will fly away
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