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Use for the Tesla Switch

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  • Bit's-n-Bytes
    replied
    Originally posted by SeaMonkey View Post
    What is the purpose of Q1?

    You may want to re-think the common connected bases of Q2 and Q3 since one is a 'high side' switch and the other is a 'low side' switch. In normal operation their base voltages will be considerably different while in conduction. You'll have to drive each of those two individually.
    @SeaMonkey, without knowing this circuit in great detail, I would say that when q1 triggers, it sets the coil shown to energize and upon collapsing, it feeds a negitive spike to the batt. This is an attempt to maintain charge. That said, I suggest you build these circuits describe in this thread to explore the non-convential learning of negative energy. I know that you were a large contributer on other fourms, but heed the suggestions from Matt, Citfa, John K. and others (myself) in showing, not telling. We have all been there, done that. Please help us, help you, and return, you help us, oh wait, that is OU. LOL

    Bit's

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  • Matthew Jones
    replied
    John
    Where Q1 is your missing the capacitor and you have the resistor on the wrong side of the transistor.
    Is that intentional?

    I've got one running right now with that addition (hand drawn section). It seems to be holding steady But I did like the schematic said. I also couldn't get it to run stable by adding a load in there so I went back and added bulb like Mr Johns schematic. Its holding its voltage but no charging. I am also paying for the switching with the main battery.

    Matt

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  • John_K
    replied
    Originally posted by SeaMonkey View Post
    What is the purpose of Q1?

    You may want to re-think the common connected bases of Q2 and Q3 since one is a 'high side' switch and the other is a 'low side' switch. In normal operation their base voltages will be considerably different while in conduction. You'll have to drive each of those two individually.
    SeaMonkey,

    I have absolutely no idea. I haven't got a clue.


    John K.

    Leave a comment:


  • SeaMonkey
    replied
    What is the purpose of Q1?

    You may want to re-think the common connected bases of Q2 and Q3 since one is a 'high side' switch and the other is a 'low side' switch. In normal operation their base voltages will be considerably different while in conduction. You'll have to drive each of those two individually.

    Leave a comment:


  • John_K
    replied
    Originally posted by SeaMonkey View Post
    John K.

    Regarding your diagram:

    The base drive circuitry to the tree transistors will be ineffective as a switching speed-up feature unless it is totem-pole driven. In order for the diode/capacitor combination to produce the reverse-bias pulse at turn-off, the input point (opto-transistor) must be connected to the transistor emitter.

    Without the two-transistor totem-pole driver, the stored charge on the capacitors has not discharge current path at the base-emitter junctions. Consequently, the base region carrier storage will not be depleted and the transistors will exhibit very slow turn-off.

    The circuit, as you've shown it, is incomplete. Is it just a simplified example?
    Thanks SeaMonkey, but I'm not looking for fast switching. I'm looking for minimal voltage drop across the transistor junctions.
    Your theory sounds fine from an EE point of view but I am not working with "conventional" electronics. I'm working with scalar electro-magnetics and switching of potentials, not current. Which is very different to what is taught in the text books.

    The circuit is complete. The component names and values were omitted on purpose, as experienced builders already know what they are.


    John K.

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  • SeaMonkey
    replied
    John K.

    Regarding your diagram:

    The base drive circuitry to the tree transistors will be ineffective as a switching speed-up feature unless it is totem-pole driven. In order for the diode/capacitor combination to produce the reverse-bias pulse at turn-off, the input point (opto-transistor) must be connected to the transistor emitter.

    Without the two-transistor totem-pole driver, the stored charge on the capacitors has not discharge current path at the base-emitter junctions. Consequently, the base region carrier storage will not be depleted and the transistors will exhibit very slow turn-off.

    The circuit, as you've shown it, is incomplete. Is it just a simplified example?

    Leave a comment:


  • John_K
    replied
    Scalar Wave Charger

    Hello fellow builders,

    I've drawn up a schematic of what I think the 2 BN-RB diagrams would look like if they were joined together.

    I've replaced the TTL IC's with a PIC and am powering the PIC separately for now, so no need for the capacitor to keep the TTL IC power clean.

    I haven't built it yet, so I'm not sure if it works. I haven't done the PIC code yet, but it is simple - 50% d/c at whatever sub-harmonic resonant frequency your battery is

    Let me know if you spot any errors.


    John K.
    Attached Files
    Last edited by John_K; 07-16-2010, 01:44 AM.

    Leave a comment:


  • citfta
    replied
    Talkers and not builders

    It still amazes me (I guess it shouldn't) that someone who admits they haven't actually built anything will start posting in a thread and tell all the builders what they are doing wrong. This seems to be a common problem on this forum. If you (Seamonkey) had actually read all the posts you would have known the pulse shape and duration etc. have been discussed many times on this thread. So I'll repeat what Matt said. Build a circuit that has the pulses like you think they should be, show us the scope shots and show us how well the circuit works. If you can't or won't do that then don't bother telling us we are doing it wrong.

    Several of us here have gotten the TS to run for days powering a small load and not losing any charge on the batteries. Can you do that?


    If you really want to help then you need to get rid of the attitude. Many of the people on this thread have been working with this technology for several years. I have only been working on the TS for a little over a year and I have learned a lot from these guys. Your writing makes it appear you think these guys are a bunch of dummies. I can assure they are not.


    Carroll

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  • Matthew Jones
    replied
    Originally posted by SeaMonkey View Post
    No, not at the moment. I've completed the most recent efforts to evaluate circuitry function for the topics of interest in this thread.

    I'll be 'on the side' as an observer to see how the flow of progress develops and may occasionally 'chime in' with hints from time to time.

    But I would like to emphasize once again the importance of the pulse characteristics and the need for fast and efficient switching. Once that is attained the other 'stuff' will fall into place.
    Ya we need another steering wheel like we need a .....
    Nothing personal...
    LOL

    Matt

    Leave a comment:


  • SeaMonkey
    replied
    That real pretty talk but have you actually tried anything. Something you could share. Test results, similar builds, a good story. Are you planning on trying anything?

    Matt

    No, not at the moment. I've completed the most recent efforts to evaluate circuitry function for the topics of interest in this thread.

    I'll be 'on the side' as an observer to see how the flow of progress develops and may occasionally 'chime in' with hints from time to time.

    But I would like to emphasize once again the importance of the pulse characteristics and the need for fast and efficient switching. Once that is attained the other 'stuff' will fall into place.

    Leave a comment:


  • Matthew Jones
    replied
    Let me know how much I owe ya and PM your paypal or address or somthing.

    See what he'll sell them all for.

    m thinking that when the device is tuned to the sub-harmonic resonant frequency of the battery, the load (bulb) is seen as a dead short so the linear instrument all read zero. This is why the bulb shines so bright. Remember they were using a 48W bulb, or 4A @12V. That's like a quartz halogen bulb.
    My 4 amp quart halogen shine full bright at about 400 microseconds as a straight load.

    Matt

    Leave a comment:


  • John_K
    replied
    108's are available!

    Hi guys,

    Here's the response from the guy in Sydney who has some 108's:

    "I have a lot of SMS cards, so there would be plenty of 108s there.
    I guess I can let go of some. How many do you need?
    What are you restoring?"

    Let me know how many you need guys and I'll see if I can get enough for all of us.


    John K.

    Leave a comment:


  • John_K
    replied
    Originally posted by nvisser View Post
    Thanks guys.

    JohnK , could you post the circuit with the load in parallel with the battery. If I remember correctly from the audio files you send me, it sounded like the bulb was in series as when this thing went into resonance or whatever you can call it the voltage over the bulb measured 0V, so it could not be in parallel with the battery. On the hand drawn diagram signed ,BN-RB,(Bill and Ray), I posted yesterday they don't show the load.
    I also wonder why they show 15000uf caps there?
    Vissie,

    The load is shown on the controller diagram. It's the part of the circuit where the 2w 22ohm resistor is switched via the NTE3042 at the same time as the 'charge output'.
    The part in the audio files is where B&R say that they "put the bulb across the battery, and it shone full brightness" (can't remember the exact words, but it's there)
    I'm thinking that when the device is tuned to the sub-harmonic resonant frequency of the battery, the load (bulb) is seen as a dead short so the linear instrument all read zero. This is why the bulb shines so bright. Remember they were using a 48W bulb, or 4A @12V. That's like a quartz halogen bulb. Scalar waves can do interesting things

    I also think we need to focus on tuning the 'thing' until the bulb lights up full and switch off the meters until we have that.

    I'm going to draw up the full schematic soon, so I'll post it when I'm done.


    John K.

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  • Matthew Jones
    replied
    I went back and read them both, Johns right the pulseout is probably the better command to use.
    I didn't realize its potential.

    Matt

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  • John_K
    replied
    Vissie,

    Here's some data for you:

    "With the -18X the internal resonator has a default value of 4MHz. However it can be increased by the user to 8MHz via use of the 'setfreq' command."

    Some info on the 'pulsout' command:

    pulsout
    Syntax:
    PULSOUT pin,time
    - Pin is a variable/constant (0-7) which specifies the i/o pin to use.
    - Time is a variable/constant which specifies the period (0-65535) in 10us units
    (4MHz resonator).
    Function:
    Output a timed pulse by inverting a pin for some time.
    Information:
    The pulsout command generates a pulse of length time. If the output is initially
    low, the pulse will be high, and vice versa. This command automatically
    configures the pin as an output, but for reliable operation on 8 pin PICAXE you
    should ensure this pin is an output before using the command.
    Restrictions:
    The 14M only supports pulsout on outputs 0,1,2.
    Affect of Increased Clock Speed:
    4MHz 10us unit
    8MHz 5us unit

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