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Stanley Meyer tec devices test and debugging suite

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  • h20power
    replied
    Hi Everyone,

    Eric eluded to yet another use for the Gas Processor I have read that before and another gas processor is place in the system seemingly taking the place of the catalytic converter. This gas processor is made to breakdown NOx created by the HICE prior to entering our atmosphere. Meyer also talks about other ways to reduce the production of NOx in the combustion chamber saying to add in more exhaust gases to the overall fuel mixture. Now for me this is where the knowledge of water used to absorb the heat of the reaction comes in handy. Basically turning the HICE into a steam engine as the water mist will absorb the heat energy of the reaction turn to steam and aid greatly in pushing down the piston keeping the heat down so no NOx are produce in the process. Use water to solve water related problems, that is my keeping it simple.

    So even Stanley Meyer knew that this process can create unwanted NOx gases and told of methods to use to prevent these unwanted NOx gases. Fond in patent 5293857 and other patents of Stanley Meyers. So if you hear someone saying the Nitrogen is a desired part of the reaction and is involved in the thermal explosive energy ask them to show you the chemistry and math of the processes involved and they will be unable to do so for Nitrogen is not apart of this reaction. Patent 4826581 also talks about what atoms are involved with the thermal explosive energy created by this process.
    Hydrogen and oxygen are the reactive components of this process, everything else is just along for the ride and tends to get in the way of this reaction or as Meyer puts it, "impedes the reaction." So remember production of NOx is undesirable as it is a harmfully greenhouse gas.


    h2opower.
    Last edited by h20power; 01-22-2010, 06:03 PM.

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  • bussi04
    replied
    schema update done

    Originally posted by Tecstatic View Post
    Lets have an updated diagram before we proceed. See my previous post (remember preview and scroll down before submitting a post as a time saver).

    Do you have some spare 4046 ?
    @tecstatic
    I have updated the scheme now.
    Last edited by bussi04; 01-24-2010, 01:32 AM. Reason: scheme revoked (not up to date)

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  • Tecstatic
    replied
    From what I have seen so far, I think VIC replicators should take a look and get an understanding of what Armagdn03 shows in the oldest 5 videos.

    Without that knowledge the PLL IC 4046 will IMO be a tough master to conquer.

    Thanks Andrew for these very instructive videos:

    YouTube - tortuga0303's Channel

    Energy Propagation
    Ressonant rise of Parallel LC (3)
    Introduction to resonance
    Resonance cont
    pulse

    Eric

    Leave a comment:


  • bussi04
    replied
    Originally posted by Tecstatic View Post
    Lets have an updated diagram before we proceed. See my previous post (remember preview and scroll down before submitting a post as a time saver).

    Do you have some spare 4046 ?
    yes, I have 2 more 4046 from Texas Instruments and one HEF4046.

    Now I do the update of the scheme.

    Leave a comment:


  • bussi04
    replied

    Leave a comment:


  • Tecstatic
    replied
    Lets have an updated diagram before we proceed. See my previous post (remember preview and scroll down before submitting a post as a time saver).

    Do you have some spare 4046 ?

    Leave a comment:


  • bussi04
    replied

    Leave a comment:


  • bussi04
    replied
    Originally posted by Tecstatic View Post
    "Answer to MOD1421#1: Voltage at C10 = 1.3V with 50mV ripple"

    At what frequency ?

    Definition of the PhaseLockedLoop "locked" condition:

    1. Phase difference between U4 pin14 and 3 are close to zero all the time.
    2. C10 voltage is a DC voltage with low ripple voltage.
    3. Frequency at U4 pin 4 is stable close to the "resonance" frequency of the tank circuit.
    4. U4 pin 1 pulsing at VCO frequency, so D6 is on.

    Q1425#1 Do you have the lock condition now. ?

    Leave a comment:


  • Tecstatic
    replied
    Hi Bussi.

    I think we are quite close now.

    May I suggest you take a copy of your project directory with diagram version 0.5.

    In the diagram, rename the version to SM test 0.1 and make the diagram up to date, as I suspect my picture of the PCB you have is not right, especially around the R12, R13, C10 connections.

    Then we can empty the MOD log when you have posted me the diagram only. You can delete .net and .brd from the project zip file to reduce the size.

    Eric

    Leave a comment:


  • bussi04
    replied
    Addition to MOD1421#1

    addition at point C10-R13 the voltage is 2.5V with positive spikes up to 3.8V max at the falling edge of U4 pin3

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  • Tecstatic
    replied
    "Answer to MOD1421#1: Voltage at C10 = 1.3V with 50mV ripple"

    At what frequency ?

    Definition of the PhaseLockedLoop "locked" condition:

    1. Phase difference between U4 pin14 and 3 are close to zero all the time.
    2. C10 voltage is a DC voltage with low ripple voltage.
    3. Frequency at U4 pin 4 is stable close to the "resonance" frequency of the tank circuit.
    4. U4 pin 1 pulsing at VCO frequency, so D6 is on.

    Q1425#1 Do you have the lock condition now. ?

    Leave a comment:


  • bussi04
    replied
    Originally posted by Tecstatic View Post
    Thanks,

    I just realized that we use phase comparator 2 output to feed R12+13, C10.

    Q1421#1: By SS do you mean Steady State ?

    MOD 1421#1 Please make fixed resistors R12=400Kohm (or 390Kohm), R13=10kohm, C10=10nF Or what you need to make it work, but R13=10kohm is mandatory.
    When running we should see a stable voltage on C10 near 2.5V with less than 20mV ripple assuming the center frequency is set right.

    MOD 1421#2 Connect R12 to U4 pin 2 instead of U4 pin 13.

    Leave a comment:


  • bussi04
    replied
    Originally posted by Tecstatic View Post
    Thanks,

    I just realized that we use phase comparator 2 output to feed R12+13, C10.

    Q1421#1: By SS do you mean Steady State ?
    ...

    U8 pin 5 reconnected to U8 pin 6
    Pin 2 of RV7 connected to VCC
    U2 in circuit again
    Set center frequency to 5600 hz
    R15 = 4.7 KOhm
    R15 cut off from U8 pin 4 and connected to U7 pin 11
    C10 = 500 nF
    C10 connected to pin3 of U6B
    R14 = 100 KOhm
    C11 = 30 nF
    D5 in series with Resistor 1 KOhm
    Inserted Resistor 1 KOhm between C11 and pin5/6 of U8
    Added capacitor 100 nF between pin 14 (VCC) and pin 7 (GND) of U6
    MOD 1415#1: Connect the wire going to U6 pin 3 to U4 pin 9, being the only connection to U4 pin 9

    answer to Q1421#1: No SS = pp = peak to peak (lowes voltage to highest voltage)

    now I do MOD1421

    Leave a comment:


  • Tecstatic
    replied
    Originally posted by bussi04 View Post
    U8 pin 5 reconnected to U8 pin 6
    Pin 2 of RV7 connected to VCC
    U2 in circuit again
    Set center frequency to 5600 hz
    R15 = 4.7 KOhm
    R15 cut off from U8 pin 4 and connected to U7 pin 11
    C10 = 500 nF
    C10 connected to pin3 of U6B
    R14 = 100 KOhm
    C11 = 30 nF
    D5 in series with Resistor 1 KOhm
    Inserted Resistor 1 KOhm between C11 and pin5/6 of U8
    Added capacitor 100 nF between pin 14 (VCC) and pin 7 (GND) of U6
    MOD 1415#1: Connect the wire going to U6 pin 3 to U4 pin 9, being the only connection to U4 pin 9

    answer to Q1417#1:
    U4 pin 4 152 kHz at duty 50% 5V SS
    U4 pin 3 4764 hz duty 50% 4V SS
    D6 on
    U4 pin 5 (INH) constant 0V
    U4 pin 2 5V SS rectangular
    U4 pin1 5V SS variable frequency around 4763 hz duty 90%
    U4 pin9 2 V with spikes down to 0.6V at around 4400 hz
    u4 pin13 1.6V with rectangular rise to 5V duty 15%
    u4 pin14 4764 hz duty 50% 4V SS rectangular
    u4 pin16 VCC no spikes
    u4 pin7 GND short spikes 0.4V SS

    sorry for the delay, I had to repeat the measurement for pin 9.
    Thanks,

    I just realized that we use phase comparator 2 output to feed R12+13, C10.

    Q1421#1: By SS do you mean Steady State ?

    MOD 1421#1 Please make fixed resistors R12=400Kohm (or 390Kohm), R13=10kohm, C10=10nF Or what you need to make it work, but R13=10kohm is mandatory.
    When running we should see a stable voltage on C10 near 2.5V with less than 20mV ripple assuming the center frequency is set right.

    MOD 1421#2 Connect R12 to U4 pin 2 instead of U4 pin 13.

    Leave a comment:


  • bussi04
    replied
    Originally posted by Tecstatic View Post
    Sorry, sorry

    MOD 1415#1: Connect the wire going to U6 pin 3 to U4 pin 4, being the only connection to U4 pin 4

    Should have been

    MOD 1415#1: Connect the wire going to U6 pin 3 to U4 pin 9, being the only connection to U4 pin 9

    I must double check next time.

    U8 pin 5 reconnected to U8 pin 6
    Pin 2 of RV7 connected to VCC
    U2 in circuit again
    Set center frequency to 5600 hz
    R15 = 4.7 KOhm
    R15 cut off from U8 pin 4 and connected to U7 pin 11
    C10 = 500 nF
    C10 connected to pin3 of U6B
    R14 = 100 KOhm
    C11 = 30 nF
    D5 in series with Resistor 1 KOhm
    Inserted Resistor 1 KOhm between C11 and pin5/6 of U8
    Added capacitor 100 nF between pin 14 (VCC) and pin 7 (GND) of U6
    MOD 1415#1: Connect the wire going to U6 pin 3 to U4 pin 9, being the only connection to U4 pin 9

    answer to Q1417#1:
    U4 pin 4 152 kHz at duty 50% 5V SS
    U4 pin 3 4764 hz duty 50% 4V SS
    D6 on
    U4 pin 5 (INH) constant 0V
    U4 pin 2 5V SS rectangular
    U4 pin1 5V SS variable frequency around 4763 hz duty 90%
    U4 pin9 2 V with spikes down to 0.6V at around 4400 hz
    u4 pin13 1.6V with rectangular rise to 5V duty 15%
    u4 pin14 4764 hz duty 50% 4V SS rectangular
    u4 pin16 VCC no spikes
    u4 pin7 GND short spikes 0.4V SS

    sorry for the delay, I had to repeat the measurement for pin 9.

    Leave a comment:

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