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  • #46
    I edited my last post to apologize to Thane because I hastily made a very silly
    mistake because of my inexperience.

    Again sorry for that, I will make it clear, it was my mistake.

    I still think it's a bit suspicious

    Cheers

    Comment


    • #47
      Originally posted by nueview View Post
      well to my line of thinking it all goes to the COP more or less it is all a form of leveraging the amount of input for the amount of output.
      so the method to get a performance is important.

      in my shop i have a rotary phase inverter it takes in 220 volt single phase at 20 amps and gives me 220 volt 3phase at 15 amps per phase is this not a cop device some have called it OU but i would not though it was invented by Tesla it is seldom talked about even on these posts.

      in all the cases mentioned there is no OU all the field reactions are accounted for as is all the energy and how it is derived or aquired though they can have a better COP than is normally gotten.

      in your case i would think there is some mutual reaction such that the load is increasing the resistance in the primary lowering input power this is not uncommon with resonant chokes.
      Martin
      How could the load on the output transformer be increasing the resistance in the primary of the other transformer when it is only connected by one wire ?

      I load the output transformer and the other one which is the one energized by the battery and only connected by one wire reduces input power.

      I know exactly why it does it but that is irrelevant in my opinion, it does it.

      I can make them do all sorts of things.

      How do I measure the input power when only one wire connects them, they
      can be 40 feet apart and one in a steel shed connected by only one wire and
      they still work.

      I am at a loss to work out the input power from one wire.

      Cheers

      P.S. nueview can I ask what you mean by "resonant chokes". They are two Tesla Transformers.

      ..
      Last edited by Farmhand; 10-21-2011, 08:15 AM.

      Comment


      • #48
        Here is my basic setup, the supply transformer (transmitter) is powered from a 12 volt battery.

        As far as I can tell there is no power input to the output transformer because
        no voltage is applied to it there is current flow back and forth, but I can't
        measure any voltage across a resistor in the single wire connection as yet.
        Further more with only one wire there is really no voltage applied to the
        output transformer.

        So there is a challenge for someone. Is power transferred to the output
        transformer or only current ? If it's only current the power is zero.

        Unless someone can tell me exactly how to measure power to the output
        transformer I am going to make some really outrageous claims.

        Claims like Zero input power and a 0.8 watt load power equals infinity C.O.P.
        And the whole setup is 200% efficient or more because of the input
        power drop to the supply transformer when the output transformer is loaded.



        Uploaded with ImageShack.us

        I can make wild claims too.

        Cheers

        Comment


        • #49
          Originally posted by Farmhand View Post
          I'm glad you took the time to read it mbrownn it does seem to say that the magnetic field manifests from outside the core and the wire, so in free air.



          Yes, I've thought that for a while. I was waiting for you to read it. I was
          shocked to see it in a document. I did post some drawings a while ago but
          they were a bit rough and I thought it was far fetched, I am reluctant to post
          the drawing, but here it is. I'm not saying it's true but it's the theory I work
          by. In a transformer using AC it's different I think.



          This is the original drawing I made and posted a while ago and is still linked on
          the other site. Of course it was just my own personal theory at the time and
          when I shared it no one seemed interested.

          I don't think of the Aether as particles, I see it as flux kind of like magnetism but not..

          Cheers
          P.S. I think it could be nature's way of giving back the work it took to make
          the current flow, to maintain unity as nature must.

          ..
          I see what you are saying, not easy to explain is it. I use the word "particles" for want of a better explanation. If the aether is as I imagine it could explain a thing or too.

          Imagine a ping pong ball with a small bar magnet going through it from equator to equator, now imagine electrically charged poles set at 90 degrees to the magnet poles and gravitational poles set at 90 degrees to the other two. Now imagine that the surface of the ping pong ball has a force field strong enough to keep it apart the other similar ping pong balls. Just think what a swimming pool full of these ping pong balls sort of floating equidistant from each other and the interactions they would have. Now imagine a wind constantly causing a turbulence between them, that's how I see the aether although there may be other forces with poles as yet undiscovered in the ping pong balls too.

          Now imagine that two balls manage to get close enough together that the opposite poles can now overcome the repelling force of the surface, be it either electrical, magnetic or gravitational. If enough of these come together it may become a photon and still more would make the sub atomic particles we know of. Now imagine what would happen in this sea if we introduce random forces such as electrical charges, magnetism and gravity. Quite a complex model isn't it?

          Now imagine someone places a wire through it and runs current through it in pulses and also what would happen if someone coiled that wire. I think that this may be the way the the aether interacts with inductors or something like that.

          Maybe I should not think so much

          Comment


          • #50
            Now you have a picture of my aetheric model. I will introduce some oveunity concepts.

            By creating a charge or dipole we can attract some of these aetheric ping pong balls with their electricl poles into our system and as the dipole is shut off these ping pong balls will shoot back out. If we pass a current through the wire it will cause the attracted poles to line up and move along the wire with the current, as the electrical poles are lined up so will the magnetic ones at 90 degrees to the electrical ones, causing the magnetic field around the wire. The gravitational poles are still random so no gravitational effects are seen.

            The same will be true if we create a moving magnetic field, it will drag along electrons with the electrical poles lining up but at 90 degrees to the magnetic field. I am leaving gravity out of it at this stage as we will need a second force to bring that into play.

            In either case the "free" thing is a force, not energy, at 90 degrees to the force we created and it will not be of the same type as what we created ie magnetic causes electrical and electrical causes magnetic. What gives us the energy is when we make the force do work, in other words when we make the force interact with matter. The free energy is when the force created is switched off and the aether goes back to its normal random interactions but momentarily interacting with matter. The movement caused by creating our force is what we had to pay for. Hopefully this explains what is happening in a Bedini circuit.

            Now to make the free energy flow we can do it in two ways, the first is by creating standing waves in the aether by using oscillating circuits and using the potential difference to create a flow in our circuits. The second is actually simpler to do, when we charge a coil we pay to charge it by passing current through it, upon discharge we get more current for free only reduced in power by ohms law. As there is current flow there is a magnetic field created by the alignment of the aether with the discharge being for free. Remember that the only energy consumed was due to ohms law so if we collect the discharge in a capacitor and use it to power the next pulse with a little top up that we have to pay for. It is only the top up, ie losses due to ohms law, we have to pay for and NOT the load or work done by the Aether.

            I hope I explained this well enough to understand as my brain hurts now

            Comment


            • #51
              I think you're ping pong balls in a pool analogy is a good one. It is very deep
              because as explained by Walter Russell and Crookes too I think everything is
              born from the Aether.

              It can be headache inducing. And I am more interested in studying and
              experimenting to improve my understanding of it. How could it ever be proved,
              The way I see it as I understand it from studying Walters book The Universal
              One, the Aether is constantly fluctuating charges. Forever cancelling each
              other into mass (integration) and back (disintegration).

              Efficiency calculations seem insignificant in the big scheme of things.

              The Universal One Book Link

              Formula of locked potentials


              Uploaded with ImageShack.us

              Basis of the Atom


              Uploaded with ImageShack.us

              Gravity and Radiation


              Uploaded with ImageShack.us

              Gravity and radiation 2


              Uploaded with ImageShack.us

              Induction - Conduction


              Uploaded with ImageShack.us

              Enjoy

              Comment


              • #52
                Upon connecting the hi-impedance generator coil to interact with
                the magnets, the motor's work value goes up 40% without the
                required change of input power of 50%. In this case its performing
                the work of a 294W system with 212W, generating 82W in addition
                to the amount going to the load connected to the lo-impedance coil.

                His idea is then to use the output of the hi-current coil
                for powering one of his regenerative transformer systems.



                [ video ]

                Comment


                • #53

                  Comment


                  • #54
                    Originally posted by geotron View Post
                    Upon connecting the hi-impedance generator coil to interact with
                    the magnets, the motor's work value goes up 40% without the
                    required change of input power of 50%. In this case its performing
                    the work of a 294W system with 212W, generating 82W in addition
                    to the amount going to the load connected to the lo-impedance coil.

                    His idea is then to use the output of the hi-current coil
                    for powering one of his regenerative transformer systems.



                    [ video ]
                    Hi Geotron,

                    What is the electrical output in watts ?

                    And what is the mechanical power supplied to the generator shaft in watts ?

                    Answer those two questions. Then divide the electrical output by the
                    mechanical input. That will give the overall efficiency of the generator
                    section alone.

                    Then divide the electrical output by the total input provided, That will give
                    you the total system efficiency.

                    Energy cannot be created, if you want to believe it fair enough.

                    See generator efficiency above.

                    Good luck to him on those plans. I wish him the best. And I hope for
                    humanity's sake he is right.

                    If he is going to use the definition for the efficiency of an electrical generator then it's linked above.

                    All we need to know to find the efficiency of the generator is the mechanical
                    input power provided to the shaft of the generator and the electrical output.
                    We know neither. The rotor speeding up is not output. An electrical generator
                    output is electrical power, that's all nothing else.

                    This quote from my post above. If it is creating energy he should be able to
                    decouple the motor and the generator will keep going. Simple.

                    Another way to determine the mechanical power supplied is to run the motor
                    at speed up speed, then remove the rotor and coils, then run the motor without
                    any adjustment, measure the input to the motor, then re-install the rotor and
                    coils, run it again and measure the input power to the motor again, then the
                    difference between them is the power supplied to the generator from the
                    shaft.

                    Then take the load power and divide that by the power supplied to the
                    generator, to get the efficiency.

                    That is the efficiency of the generator section.
                    like I said if it's OK for him to ignore the unloaded power consumption then it's
                    ok for me too and anyone else, that'll open a real can of worms.

                    Cheers

                    P.S. If a 40% RPM increase requires a 50% Power input increase then a 40% RPM increase can also be achieved with a 50 % reduction in drag as far as I can guess anyway.

                    ..
                    Last edited by Farmhand; 10-21-2011, 12:06 PM.

                    Comment


                    • #55
                      Also Geo, Even though the efficiency calculations seem correct for the BiTT I
                      have my doubts it can run a useful load as efficiently as that. And considering
                      the size of the thing for the output he used to do the calculations I personally
                      don't think it means all that much.

                      I never get too excited seeing efficiency calculations done in the milli watts.

                      Cheers

                      Comment


                      • #56
                        hi farmhand
                        i want to say mbrown did a good job of explaining the power back feed of the resonant choke by fields but he seemd to miss one important part in the case of what you are doing as you increase the resistance you increase the tension of the virtual capacitor at the top of your coils and store this potential in the or should say across the load and as it returns the amount of current is increased making resistance rise for the input.
                        static charges seem to increase potential with the increase of resistance.

                        hope this is of some help
                        Martin

                        Comment


                        • #57
                          Originally posted by nueview View Post
                          hi farmhand
                          i want to say mbrown did a good job of explaining the power back feed of the resonant choke by fields but he seemd to miss one important part in the case of what you are doing as you increase the resistance you increase the tension of the virtual capacitor at the top of your coils and store this potential in the or should say across the load and as it returns the amount of current is increased making resistance rise for the input.
                          static charges seem to increase potential with the increase of resistance.

                          hope this is of some help
                          Martin
                          Where does he explain that ? I have to say that is that first time I have
                          heard someone call a Resonant Air cored Transformer a resonant "Choke".

                          I know how my setup works in general terms. And like I said as far as I can
                          tell there is no voltage applied to the receiver coil by the transmitter coil.

                          Help with what ? All i want to know about my setup is. Is there power
                          transferred or just current ? If is power transmitted where do I measure the
                          voltage ?

                          What resistance is it I am increasing ?

                          Did you look at my drawing ? The load is connected to two wire's on the
                          output transformer. How is the tension in the open capacitor stored across
                          the load the load is connected to a different coil.

                          How does the current returning increase the resistance ?

                          So what is you are saying ?

                          Cheers

                          P.S. All I am asking is, if there is voltage applied to the receiver coil, where do I measure it ? I don't think there is.

                          I think i see what you're saying now. Yes it is a feed back response.

                          ..
                          Last edited by Farmhand; 10-21-2011, 09:19 PM.

                          Comment


                          • #58
                            What happens in simple terms I think is the transmitter charges it's own
                            terminal and in doing so causes current to flow through the single wire and
                            through the receiver to it's terminal when the current passes the output coil it
                            induces a current in that coil and the load, somehow this original current causes the
                            receiver terminal to be charged to high potential just like the transmitter one,
                            Then the receiver basically transmits the energy back to the transmitter
                            where the same thing happens but the primary pulses again at just the right
                            time to top the system back up. I can also run a load in series with the
                            connecting wire.

                            A ground connected Tesla Transformer pushes the current into the ground,
                            as far as I can tell. Like I said these Transformers can be separated by easily
                            30 or 40 feet with the transmitter housed in an almost completely steel lined
                            and enclosed shed, with the receiver in a partially enclosed steel shed with
                            only the one wire connection. They work pretty much the same if they are 3
                            meters apart or 20, I am limited by the input voltage of 12 volts and HF
                            losses.

                            I can light a 18 watt fluro from the transmitter and two 10 watt fluros from
                            the receiver almost full brightness, others are claiming output by the lighting
                            of bulbs of certain watt value's. Maybe I should too. 20 watts of light bulbs
                            lit with 4 watts input. And doing that reduced the input (to the transmitter) approximately
                            from 8 watts to 4 watts or less. So even better efficiency.

                            If others are going to make crazy claims without anyone questioning them
                            then so will I.

                            So 20 watts of fluro's lit with Zero power input to the receiver ? At the same
                            time the receiver is lighting 6 x 5 mm LED's and a 2 watt filament globe, all
                            with no power input to the receiver.

                            It's easy to make claims without proof.

                            Cheers
                            Last edited by Farmhand; 10-21-2011, 10:42 PM.

                            Comment


                            • #59
                              Now getting back to the generator efficiency, there is no baseline established to
                              calculate the overall efficiency of a generator according to this below. It says

                              It says watts available in load circuit divided by mechanical power supplied.

                              Only two values are required.

                              See here.


                              Uploaded with ImageShack.us

                              Thane seems to be using the definition of an electrical generator to determine
                              the efficiency of his setup but he then seems to be including the increased
                              speed of the rotor as part of the calculation. No need for that. just measure
                              the mechanical power provided to the shaft of the generator then divide the
                              watts available in the load circuit by that.

                              I think a magnet provides mechanical power doesn't it ?

                              Cheers

                              Comment


                              • #60
                                So if a magnet provides mechanical power not electrical power, then any power
                                supplied to the shaft of the generator by any magnet would be mechanical
                                input, wouldn't it ?

                                If so that would mean any increase in mechanical power supplied to the shaft of an electrical generator from anywhere is input not output, wouldn't it ?

                                So to work out the efficiency of the generator all the input provided to the shaft
                                is used and the output watts available in the load circuit are divided by all the
                                mechanical input to the shaft.

                                Now things are becoming more clear.

                                Like I said if the generator is applying mechanical force to the rotor then decoupling the drive motor should see the generator run on it's own.

                                If he wants to include the rotor kinetic energy he needs to forget about
                                generator efficiency and calculate total efficiency of the whole system.

                                Cheers

                                Comment

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