Electric Motor Secrets

[Aaron]

Electric Motor Secrets

Here is the new Electric Motor Secrets release.

Peter Lindemann is making Part 1, Part 2 and Advanced Motor Secrets available for a discount as a complete package - you can see details here: Electric Motor Secrets by Peter Lindemann

[Vincevl]

Try touching the leads of your ohm meter together and read the ohms. Now record that number and then measure your coil. Subtract the the first number from the second and that will be a closer reading ( although still not very accurate ). On a harbor freight meter the first reading will usually be about .8 ohms.
Garry

You were right on! When I touched the DMM probes together I measured 1.2 Ohms! Here I was thinking it was a decent meter. No wonder my reading was wonky. I was able to measure the actual resistance by putting a constant 100mA load on the coil and measured the voltage drop across it to determine the resistance. It turned out to be 0.41 Ohms.

Many Thanks!
Vince

[iflewmyown]

Try touching the leads of your ohm meter together and read the ohms. Now record that number and then measure your coil. Subtract the the first number from the second and that will be a closer reading ( although still not very accurate ). On a harbor freight meter the first reading will usually be about .8 ohms.
Garry

[gyula]

Hi Vince,

unfortunately it is only you who can this figure out, (you can do hands-on tests and visual inspectations... LOL)

The 17A current indicates 0.7 Ohm coil resistance instead of the 1.9 Ohm. Maybe try to move the wire connections up and down, and also sideways when your Ohm meter is hooked up, there must be somewhere a short between the turns.

I see the cross-spanner keeping the prongs distance for the air gap, is it magnetisable steel? sorry for this question...

Gyula

[Vincevl]

Rotary Attraction Motor

Attached is a picture of my RAM but I'm having a problem. My coil is wound with 245 turns of two pair Litz wire 18 AWG. The resistance of the coil is 1.9 Ohms. I assumed if I connect it to a 12VDC power source it would draw about 6 Amps but in fact it draws around 17 Amps.

Can anyone shed some light as to why?

Thanks,
Vince

[Blargus]

Hi,

There seems to be some successful builds that I think are really exciting . Wanted to ask if anyone has any tips on how to put a hall effect or optical timer on a Bedini SSG to get a step closer to the rotary attraction motor I would appreciate any help. Thought this might be relevant/interesting to the topic:

Tesla Patent 381,968 - Electro-Magnetic Motor

"The disk D in Fig. 9 is shown as cut away on opposite sides; but this, I have found, is not essential to effecting its rotation, as a circular disk, as indicated by dotted lines, is also set in rotation. This phenomenon I attribute to a certain inertia or resistance inherent in the metal to the rapid shifting of the lines of force through the same, which results in a continuous tangential pull upon the disk, causing its rotation. This seems to be confirmed by the fact that a circular disk of steel is more effectively rotated than one of soft iron, for the reason that the former is assumed to possess a greater resistance to the shifting of the magnetic lines."

I don't know if a circular steel rotor would affect the recovery side of the rotary attraction motor though...

[Robert49]

Wow, 69.5% back.

If I remember correctly I got 17% recovery so allowing for capacitive losses that would be 34%. OK it wasn't a good test and the supply should have been higher voltage but that was all I could do at the time. 120 - 220v would have produced much better figures.

How did you measure the recovery?
What is the motor mechanical efficiency?

You have to include all outputs to get your COP

Hi.

Right now I am only looking at how much energy is coming out of the collapsing fields of the attraction motor (B). I have measured the voltage of those spikes to be over 2000 volts when running the motor at 50 volts and probably over 3000 volts when running at 100 volts.
I charged a 2000 volt capacitor and the voltage exceeded 2000 (and burned my H.V. transistors and diodes.) I have a 30kv voltmeter by the way.

I have noticed that the higher the input voltage the better the figures but there's also the fact that my attraction motor is running on 12 pulses per rotation so at 95 volts I measured 9100 rpm = 1820 pulses/second.I think this plays a good part in the recovery.

The input was on motor "B" at 63.65 watts 9100 rpm
The recovered energy is running motor "A" at 44.268 watts 4550 rpm
So 44.268 is 69.5% of 63.65 .I may not be doing this right? You tell me.

I have no means of measuring the mechanical energy but it looks good??

I am going to try running the attraction motor with variable pulses and fixed voltage like perhaps 50 volts and see what numbers come out .


Robert

[mbrownn]

Hi People.

I experimented with this setup and got this!

Motor "B" is my "Rotary attraction motor".
Motor "A" is a 110volt dc motor.

I ran motor B with 95volt at .67amp = 63.65 watts
It was running motor A at 217volt at .204 amp = 44.268 watts.
I was getting 69.5% back.

The pulley ratio is important and is probably not right. It needs to be reduced.I will fiddle around with it.

When I slow down the combination, motor B uses more power but also produces more power to motor A wich accelerates to compensate.

Wow, 69.5% back.

My replication is here Imhotep's Lab Interactive FAQ - View topic - Rotary attraction motor using an induction motor as the donor.

Some test results Imhotep's Lab Interactive FAQ - View topic - Rotary attraction motor

If I remember correctly I got 17% recovery so allowing for capacitive losses that would be 34%. OK it wasn't a good test and the supply should have been higher voltage but that was all I could do at the time. 120 - 220v would have produced much better figures.

How did you measure the recovery?
What is the motor mechanical efficiency?

You have to include all outputs to get your COP

[Blargus]

Hi People.

I experimented with this setup and got this!

Motor "B" is my "Rotary attraction motor".
Motor "A" is a 110volt dc motor.

I ran motor B with 95volt at .67amp = 63.65 watts
It was running motor A at 217volt at .204 amp = 44.268 watts.
I was getting 69.5% back.

The pulley ratio is important and is probably not right. It needs to be reduced.I will fiddle around with it.

When I slow down the combination, motor B uses more power but also produces more power to motor A wich accelerates to compensate.

Wow that's very exciting! Wonderful looking machine. Thanks very much for sharing!

[Robert49]

Hi People.

I experimented with this setup and got this!

Motor "B" is my "Rotary attraction motor".
Motor "A" is a 110volt dc motor.

I ran motor B with 95volt at .67amp = 63.65 watts
It was running motor A at 217volt at .204 amp = 44.268 watts.
I was getting 69.5% back.

The pulley ratio is important and is probably not right. It needs to be reduced.I will fiddle around with it.

When I slow down the combination, motor B uses more power but also produces more power to motor A wich accelerates to compensate.

[jtanguay]

This primer on DC motor/generators is AMAZING!

Really helps bring into perspective of Peter's rotary attraction motor if you look at the magnetic flux lines.

[jtanguay]

This primer on DC motor/generators is AMAZING! Fast forward to 9:22 for an interesting view of a 4 pole DC generator

Really helps bring into perspective of Peter's rotary attraction motor if you look at the magnetic flux lines.

[mbrownn]

yes there has been much discussion on the forums about this.

[jtanguay]

Just to add, anyone see this video?

Very impressive gain on the motor from the external magnet placement. If the motor has the same input, then if connected to a generator, it should be able to sustain itself.

[jtanguay]

By the use of this motor the pollution in the air can be stopped.I would use a small appliance motor I scrounged out of a vacuum or fan. Ten pounds is not that much just test out your gears or belts to be sure you don't over amp your motor. I would bet the motor from an old hand held drill or such would be small enough to hide well and strong enough to lift your ten pounds. Make sure you gear it down so the speed will not shoot anything into orbit when you open it.

The air pollution is not good for our health, but does not affect our planet as badly as what removing the oil from the ground does in the first place. Burning the fossil fuels releases CO2 which helps plants grow, not a bad thing. When the oil is removed from the earth, it creates voids and cavities that will most likely fill up with water. Water has a far lower boiling point as we all know, and it does get fairly hot deep down where the oil is extracted. That being said, we do need these free energy technologies not only to keep this planet from self destructing, but to also free ourselves from the bondage of fossil fuels. In any type of emergency situation we are at the mercy of whoever can provide fuel so we can drive around. It is like an invisible tether that must be severed.

I am thankful to those willing to share their knowledge to make this possible. I think the key to success is utilizing the magnetic gate principle to change the flux path of a permanent magnet, in essense switching by electronic means with a micro controller as the rotor passes to create motive force. It should only take a small amount of electricity to switch the flux paths to achieve a large amount of motive force which could then be used to generate electricity flow to power the micro controller. The arduino unit would be perfect for this and could even be embedded into the rotor with an RF transmitter to receive signals to regulate RPM and torque if necessary. That might be a little bit too complex though, and so a brushless design wouldn't be too difficult to implement either. I wish I had the funds/equipment to design such a motor.

The concept comes from the flux switch transformer. I believe Tom Bearden been working on a design for such a flux switch transformer.

Didn't want to throw the topic off course, but maybe bring new light into it.

As for the 'perfect wind' I too am curious. I've wound a custom solenoid transformer, but have no idea on the amount of turns etc. I wish I had a means of measuring wire length so as to be able to wind coils of equal length wire bifilar or even trifilar. That way the impedance would be virtually the same. From what I gather, coil winding is of the utmost importance with any device as a circuit should be designed around the coil and vice versa.