Originally posted by Ben2503
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Means you have a strong power source, and the transistor opens more then it should. Then are there parts what are burned, because it let to much power through.
There are lesser examples about that these circuits did create own energy.
And the "Fix the world" people would not be "stealing the show" anymore.
So yes, the builder made a fundamental error in his current-measurement setup. He also didn't seem to understand capacitive-coupling - he wouldn't have been trying to measure DC-current if he did! But most crucially, he is not working with a bifilar-coil - so the video-title itself is incorrect! Listen again to how he describes the coil itself and how it's connected - what he actually has are 2 pieces of enameled wire wrapped side-by-side on a coil that are not directly-connected to each other (no DC-coupling like I had already said, but didn't emphasise). To one wire is connected the signal-generator output (its other end connected to nothing), to the other, ground is connected (again, its other end connected to nothing). But AC-current will flow via capacitive-coupling between these 2 wires.
- his coil has 4 output wires. He specifically states that the 2 on the left are one wire, and the 2 on the right are the other wire. He specifically states that he is sending the generator signal into one wire, and that its other end is connected to nothing. Ditto for the earth connection. He then specifically states that there is no electrical connection between the Signal_Out (connected to wire 1) and the Ground (connected to wire 2) of the signal generator, other than through the capacitance of the coil. What he is describing is 2 electrically-isolated pieces of wire wound side-by-side to make a coil!!! Inductive and non-inductive bifilar coils being composed of 2 pieces of wire that are directly connected will obviously have only 2 output wires.
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