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Bedini solid state oscillator and Tesla switch combination

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  • 49er
    replied
    There were 3 300cca (42)ah and 1 -18 ah. 12v side was 12.66 and 24.4v on the source side with the switch open. source 2x 300cca charge 1-18 & 1-300cca. Will start the switch closed today Doug

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  • mbrownn
    replied
    If you could give us the start and finish voltage of both the source and charging batteries it would be nice as well as the Ah rating of the batteries.

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  • 49er
    replied
    Hi All

    Last night I charged 2 300cca batteries in less than 5 hrs with only 700 MA and still had lots of charge left in the run batteries. Very happy with this unit.

    Doug

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  • mbrownn
    replied
    Yes. That is exactly what we need. please do share

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  • 49er
    replied
    any testing or data from my testing

    Doug

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  • mbrownn
    replied
    Not sure what you mean by help

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  • 49er
    replied
    Thank you mbrownn
    Is there any help the group needs.

    Doug

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  • mbrownn
    replied
    30 mins to an hour is fine for a rest and yes multiple circuits for larger batteries.

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  • 49er
    replied
    Thank mbrownn

    When you have the switch closed and you need to change the lowest voltage battery is this when you give the batteries there rest and for how long. For larger batteries as in cart size can multy transistors and coils be used? Again many thanks.

    Doug

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  • mbrownn
    replied
    With the switch open you have two batteries charging two batteries in direct and regenerative mode, with the switch closed you have one battery charging three batteries using only the transient spike, which according to electrical theory cannot charge batteries but in reality does.

    The question is, do you get more energy in the charging batteries than is drained from the source with the switch open?

    If your batteries are lead acid, don't drain more than 10% of the fully charged voltage.

    The rest period is to allow the charge to settle and the battery drop to standing voltage.

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  • 49er
    replied
    Hi All

    I have a couple or questions 1. What is the switch for? 2. How low do you take the #1 and or #2 batteries. 3. Do you swap with out a rest peroid.
    I have built a 1 transistor air coil and it is working great with this setup. It is pulling .710ma and Hz of 3.5 and every thing is cold.

    Thanks for the help

    Doug

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  • SkyWatcher
    replied
    Hi mbrown, thanks for your reply to my post.
    I went back to the circuit nilrehob posted as it seems more efficient, with the led directly off the coil in flyback mode then to charging batteries.
    Led is a tad less bright, though the loss to gain ratio seems better.
    Still running the setup and swapping batteries until i see the input side not able to keep up with the load and charging, though so far it is doing very well.
    peace love light
    tyson

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  • mbrownn
    replied
    Originally posted by SkyWatcher View Post
    Hi mbrownn, I am still running tests, though so far the charge batteries are getting a little more than what is being lost from input batteries, though will not know for sure until this setup runs longer.
    The input batteries are bouncing back to almost the same level as they started with when i give the circuit a rest for a bit to check voltages and the charge batteries unloaded are holding the voltage very well, indicating a solid charge.

    Will be running this setup for awhile, since it's only drawing around 20 milliamps and swapping cells whenever needed.
    Hope that helps, right now I have the led across collector/emitter as shown in modified pic, though seems to be even more efficient than original circuit, brighter led also, though would not work with higher voltages with load at that point.
    peace love light
    tyson
    I think the LED would give more conventional charge but may reduce efficiency a little.

    This test is very interesting because it could prove that Inductive kickback and radiant can work together and if the charge does go up faster than the batteries discharge, then indeed we do have an input from another source.

    The normal charge, through the LED will be 70% efficient, a pulsed normal charge is somewhat higher. A radiant charge can be 97%. If Inductive kickback is the same energy as we put in the coil our charge has to be less than 100% although flowing electrons dissipate radiant so a charge of less than 100% cannot disprove radiant. If there is a gain, no matter how small, it proves a different source.

    I tested the original circuit and got a 90%+ charge from the radiant and 30% in the recovery batteries in the return line plus mechanical power from my SSG. Allowing for a margin of error of 10% there was still a net gain.

    So what results you get are important, they might not be truly scientific but important non the less. Then if there is a net gain we have to push people in the scientific community to replicate it with accurate measurements.

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  • SkyWatcher
    replied
    Hi mbrownn, I am still running tests, though so far the charge batteries are getting a little more than what is being lost from input batteries, though will not know for sure until this setup runs longer.
    The input batteries are bouncing back to almost the same level as they started with when i give the circuit a rest for a bit to check voltages and the charge batteries unloaded are holding the voltage very well, indicating a solid charge.

    Will be running this setup for awhile, since it's only drawing around 20 milliamps and swapping cells whenever needed.
    Hope that helps, right now I have the led across collector/emitter as shown in modified pic, though seems to be even more efficient than original circuit, brighter led also, though would not work with higher voltages with load at that point.
    peace love light
    tyson

    Leave a comment:


  • mbrownn
    replied
    Can you compare the charge relieved with the energy drained?. Is their an overall gain or loss?

    Leave a comment:

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