Howto make a 200/300 volt coil??

[ray0energy]

Hello to all
I am going to build a magnet motor
Whit coils that need to give me abaut
200/300 volt my core is ferrit of 2 in diameter
by 2 in long
And I want to use 0.800mm coil wire.

this is my 1e time that I make this kind of

coils
so I don't no how many turns I need to get 200/300 volt.

Can anybody help me on this

And like to no also how many turns I need if I do this in Teslas befilare coil.

[EgmQC]

Hello to all
I am going to build a magnet motor
Whit coils that need to give me abaut
200/300 volt my core is ferrit of 2 in diameter
by 2 in long
And I want to use 0.800mm coil wire.

this is my 1e time that I make this kind of

coils
so I don't no how many turns I need to get 200/300 volt.

Can anybody help me on this

And like to no also how many turns I need if I do this in Teslas befilare coil.

Its the ratio in number of turn who will tell you if its a step up or down or isolation coil. if you have 10 turn primary and 100 turn secondary with 12v sine wave input , the output will be 120v. For the energy output you need to know at which frequency you will work to calculate accurately the impedance. There alot of information about transformer on the net with all the math for it.

Best Regards,
EgmQC

[Sephiroth]

do you mean for a generator coil...

Couldn't tell you the precise spec you would need... that depends on too many factors, like the stength of your magnets, their speed, their size, but I don't think you will be able to get that kind of voltage with 0.8mm wire... I would go for something much finer....

[tjnlsn255]

L = (d2n2) / (1 + 0.45d)

Inductance of a single layer coil...so...

if d is the diameter of the coil and n is the number of turns ...

If I take a coil with 100 turns with 20 guage wire and replace the wire with 18 guage wire the 18 guage wire is fatter so there will be a larger diameter but the number of turns will be less.... so...

If the toroid is the same and we increase wire size or decrease wire size what happens to the inductance in Henrys.....?

Hopes and Dreams....

Tj

[ray0energy]

Generator coil

do you mean for a generator coil...

Couldn't tell you the precise spec you would need... that depends on too many factors, like the stength of your magnets, their speed, their size, but I don't think you will be able to get that kind of voltage with 0.8mm wire... I would go for something much finer....

Well I order magnets for a Muller generator of 2ins wide by 1ins long
de have about 250 pounds pull power.

So the plan is to have like 30 2 times 15 coil that will
go to a diode to make DC of it that will go in to a big cap bank
of 200/450 vdc.
so I will not use direct the HF AC comming from the coils
I find a way to make from DC 200/450 caps agen ac 220vac
at 60hz but that come later 1e find my self a laser cutter;-)

[juju]

hello ray of light

i will tell you the values of my smaller motor, i can get 6 VAC out of 3 pound force magnets ... the resistance of my coil is 200ohm, but is like 0,2mm thin. Here is my calculation, just to have an idea.

3 pound - 6 Volts
250 pound - ?

250P * 6V / 3 = 500 VAC

But im not shore if its the right way to do the calculation, and im talking of values without load, but my conclusion is that you should have 100/150 ohm coil resistance, to get the 200/300VAC. Someone can tell me if this calculation can be applyed?

The current is irrelevant?

I can get 60/80VAC of 3.4pound magnets, with a 1.6K ohm coil but very low current, or 2 Volts from a 10 ohm coil but with very much high current on load.

but that something that you may be already aware.



king regards

[Harvey]

The voltage you induce in your coil will be dependent on how fast the magnetic flux of your permanent magnet passes through it. The faster the motion, the greater the voltage.

So your first step will be to identify the geometry involved and determine the angular velocity of your moving magnets when the device is at operating speed. From these two, you can determine the change in flux relative to the stationary coil.

Once you know the change of magnetic flux over a specified period of time you can derive the voltage from the Law of InductionDYOXO

[ray0energy]

thanks guys

The voltage you induce in your coil will be dependent on how fast the magnetic flux of your permanent magnet passes through it. The faster the motion, the greater the voltage.

So your first step will be to identify the geometry involved and determine the angular velocity of your moving magnets when the device is at operating speed. From these two, you can determine the change in flux relative to the stationary coil.

Once you know the change of magnetic flux over a specified period of time you can derive the voltage from the Law of InductionDYOXO

hello guys tanks a lot for the replay

my internet is off at home so i had to do it from my ipod.

any way i find the detail of my magnets
http://

http://

my mathematics ware never that good so agen thanks for the help
wel i will study this tekst a bit more but now u guys have the ditails of my magnets. and for the people that like to no wat i am buiding have a look at this site it was ofline for sam time but its back on (i dont no for how long) i am buildind dubbel this size Magnetricity.com ... NEOGEN Dynamo Project

agen thanks for the help

PS: the hole buiding proces will be on video

[juju]

uauu

harvey, you r the man


only with 6 turns you will get 300V from 250pound magnets? im very impressed...

thats good news for Ray, your coils will not give any trouble to wind... jejeje

lets connect soon you have internet.. have some pics to show you!!


hugs

[ray0energy]

[Harvey]

harvey, you r the man


only with 6 turns you will get 300V from 250pound magnets? im very impressed...

thats good news for Ray, your coils will not give any trouble to wind... jejeje

lets connect soon you have internet.. have some pics to show you!!


hugs

Keep in mind that those are hypothetical values based on 3600 RPM and close coil proximity with a 19" rotor and manufacturers best Gauss readings.

In real world experience the magnets may not give a near zero flux midpoint between them when placed that close to each other. And the flux may distribute differently as well depending on how the magnetic poles are oriented on the rotor. Also, the real world Gauss may be less, and the flux could fall off along the inverse cube rule rather than the inverse square rule.

Using the above equations, you should be able to find a lower RPM and more turns that produce a similar result.

That's why everybody builds prototypes before ever attempting to manufacture a product in production - there are always little things that change the theoretical perfection and bring it 'down to Earth' so to speak

Cheers!