No Current Polarity Flip Flop Pulse Cap Charge Circuit

[gotoluc]

Hi All,

another couple of short video.

Test 7: YouTube - Polarity Flip Flop Circuit test 7

Test 8: YouTube - Polarity Flip Flop Circuit test 8

Luc

[rave154]

GOTO,

i have nooooooooo idea what youve stumbled upon.....but....


dont stop.


Ahimsa

Me.

[samedsoft]

Dear Luc,

Have you tested with lower main cap voltage and see if idle current draw of H-bridge is lowered?

Also can you try with sphere as antenna?

Thanks.

[Inquorate]

Gotoluc rep

I've replicated gotoluc's findings; the circuit I used was a colpitts oscillator with a Bifilar inductor. One wire off the secondary went to two avramenko plugs using 1n60 Germanium diodes. The other wire went to two more.

Apart from paying the cost to oscillate the inductor, the avramenko plugs to caps with resistors could be 0, 1, 2, 3 or 4 in number with no increase in amp draw.

The price of switching was still quadruple the returns on the caps, (25% efficiency) but the energy gathered didn't load the colpitts oscillator (amp draw to 3 decimal places did not increase).

And I was using a sine wave oscillator.

If we can lower the switching cost (my oscillator drew more amps as I increased voltage) we may be onto something.

Anyone know of a way to oscillate a coil to high voltage with low amperage?

I was using 5 volts, up to 40ma source, but was seeing highest voltage with highest Amperage.

Love and light

[kent_elyue]

Inquorate:

I, too, was thinking about driving a coil using an oscillator circuit to produce the flip-flop voltage effect. However it dawned on me that driving a coil is quite costly current-wise. Simply switching the polarity of a constant stable voltage is far more efficient. There are some very low-current oscillator circuits here:

Oscillators Electronic Circuits-- Main Page
<http://www.discovercircuits.com/O/oscillators.htm>

In particular I suggest the Astable, Square Wave and RF sections.

Some of these are said to draw only 200nA of current. Perhaps one of them could be adapted to a low-current high-frequency switching application, or at least fuel the imagination.

[kent_elyue]

In case it might be of any interest, here is my UNTESTED idea for driving a coil to both polarities. You'll probably recognize it as a variant of a Bedini SS circuit. I simply took a proven circuit and added an inverted drive section to push the coil to the other polarity.

So far I've only run it as a circuit simulation, but I've found that there are a number of factors that can influence the amount of current draw and the operating frequency:

1) The DC resistance of the coils (2 ohms in my simulation)
2) The inductance of the coils
3) The resistor values
4) The transistor used

As it is, the simulated circuit switches between +/-13.5v across L2, and runs around 4Khz, drawing an horrendous 290mA! However different values can impact this significantly for better or worse.

You can attach AV plugs to both sides of L2, though I don't see any reason why one couldn't add a 4th winding to the coil and put the AV plug(s) on both sides of it.

[gotoluc]

Hi All,

many of you will be able to test the circuit without an H-Bridge as long as you have a Signal Generator that is capable of 2Mhz or more. Even though the voltage output on a SG is only about 10v it does not matter as long as the frequency is high enough as the effect is very frequency dependent. As you raise the frequency you can lower the voltage and get the same work out or the other way around, lower frequency and higher voltage.

I made a new video demonstrating the circuit lighting 6 LED's at 2vdc each but using only one leg (hot side) of the SG output. I also added a 1.5 Ohm carbon resistor with the scope probe across it to measure current use.

I am unable to measure any change (current) across the resistor with it connected or disconnected to the circuit.

As far as I know this would indicate there's no current or coupling to ground. My laptop with USB scope are battery powered during the test 9 video to avoid possible coupling to ground in the circuit.

Please feel free to post how you believe to could be possible to see no change across the resistor as I don't understand how it can work. The energy would need to come from the environment through ground or the metal collectors for it to work!... would it not?

Link to video: YouTube - Polarity Flip Flop Circuit test 9

Luc

[Inquorate]

Rep demo

YouTube - Temperature drop with sec

The energy comes from the spatial lattice, or from a reversal of aetheric energy flow re emitted from mass as types of radiation, heat etc.

The energy released may be related to chaos, and lorentz attractors.

And if you're not bothered by the cost, any oscillator will do. Negligible current high frequency is best.

YouTube - rep of gotoluc's flip flop non loading energy retrieval with avramenko plug

Read the info panel pls, and take note of the mistake I made and pointed out with the schematic. And the 1n4148's do work, I was using fried ones.

Love and light

[Inquorate]

low power mhz crystal oscillator

Circuit - Ultra Low Power 32KHz Crystal Oscillator - Circuits designed by David A. Johnson, P.E.

This link is not mhz, but I'm heartened by the current draw, and possibility of using a mhz quartz crystal.

I had an 11mhz crystal over a year ago, and had a thought come to me, ''keep that, you'll need it soon''

Why do I never listen to that little voice? It's always been right.

Crystal oscillator - Wikipedia, the free encyclopedia

I may use 2 crystals at different frequencies, one 1.5 times the other, for the chaos element and other things I've learnt from dr Stiffler's thread.

Edit; found a great crystal oscillator page after hours of searching;

Transistor Crystal Oscillator Circuit :: Radio-Electronics.Com

[Inquorate]

Wow, coincidence?

http://en.wikipedia.org/wiki/Tesla's_electro-mechanical_oscillator

[gotoluc]

@Inquorate

thanks for all the support mate

Luc

[poynt99]

Luc.

I just watched your video number 9 a couple times, and I drew out the circuit quickly for analysis.

One question, How is your FG powered?

After drawing out the circuit and asking the question, "how can this "circuit" be completed?, the answer is fairly evident if things are viewed from a certain perspective. Again, I'm not an expert in this area, but here are my thoughts:

Chances are that if you were to directly short out the scope probe to its ground lead you will still be able to view a voltage wave form on the display. It may be diminished in amplitude, but it will likely be there. This is due to EM pickup on the scope probe because of the frequency you're working with. Both the ground lead and the less than perfect shielding of the probe coax cable itself (and its finite resistance) can allow induced voltage on the probe. This is why when dealing with and measuring high frequency signals, scope probe ground leads must be kept as short as possible.

Using the displayed RMS voltage and the resistance value indicates that there is a 56mA current flow, which is enough to power those LED's. I suspect that the current flows within the probe itself when it is not connected to the circuit, and most of the current is diverted into the circuit when it IS connected.

Now for the coupling to earth ground. This becomes a little more tricky to understand. As you've already observed, when the circuit is connected to a large metallic structure, or the earth ground on your meter, the LEDs glow brighter, or simply more power is available for use. This makes sense in terms of the hidden paths to earth ground.

Even if your FG was not directly powered from the grid (where it would be connected to earth ground), most likely the results would be similar. Electrostatically-speaking, everything around us is "bathed" in earth ground. What I mean by this is that at high frequencies, capacitive effects begin to emerge. Now 1.7MHz is not an exceptionally high frequency, but using square waves does increase the bandwidth of the signal quite a lot. Your generator is capable of 50ns rise and fall times if I recall correctly, and this is sufficient to radiate some fairly high frequency energy in the area. Everything has some coupling coefficient to earth ground, and that the degree of electrostatic coupling is proportional to dv/dt. In other words, the higher the frequency (or frequency content), the higher the coupling, and you have already observed this effect.

So if you were to draw out your circuit for one AV plug being driven from your FG, you would also have to include a "phantom" capacitor to earth ground. In fact all wires and metal surfaces possess multitudes of phantom capacitance to earth ground, but we can envision it as a single capacitor.

Therein lies your hidden path to earth ground I believe, and explains why current can flow with no apparent path. With a more sophisticated test setup with Faraday shielding and proper isolation, you should be able to detect a net power output from your FG. You could attempt to do this with meters and such, but the results may not be accurate.

.99

[gotoluc]

Hi .99

thanks or looking at the newest video I posted today and taking the time to post your thoughts.

Just now I connected my SG to a 12vdc inverter so it's battery powered and I also removed the scope probe and also the circuit side that was using ground.

Just using the 2 circuits (to eliminate the ground) that are connected to the metal objects and added an extra LED to each side so still have 6 LED's total and there is no change in voltage or brightness compared to the test 9 video with it battery powered.

I don't know what more to do other then put together a 555 timer and use it's output to feed the circuit and see if 555 current draw from the battery increases when I connect the circuit.

Do you think that would be a helpful test or prove anything?

Luc

[poynt99]

Hi Luc.

Yes I think that could be a next logical step for comparison. I will not be surprised to see similar results.

But it will be interesting to see if any change in current can be detected from the battery. I would suggest using a 9V battery to power the 555 (see Aaron's 555 circuit for his RA tests. Pull all 3 timing caps out and the 555 should run at about 1MHz and about 50% duty). Perhaps a CMOS 555 can be built to run at your 1.7MHz though.

If you are going to use your power meter for the measurement, try to keep all the wires and leads to it very short.

.99

[gotoluc]

Okay .99 and all,

I did the test using the 555 as single wire SG and it's as we expected ... no current draw!... it actually drops 1ma when connected

One interesting thing I found is, I have a TS555CN CMOS version and tried it to compare with the NE555N version and it behaved differently. Obviously it draws less current and I can get it to go over 2MHz but I could not get it to not draw extra current when I connect to the circuit like the NE version

There's something in its design that's making a difference ... maybe it can't work correctly using a single wire?... it's too bad since it draws so little current and gives a much higher frequency

There's always some kind of block

Anyways, if you can think of what's making the difference between the two, please let me know.

Link to new video: YouTube - Polarity Flip Flop Circuit test 10

Luc