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  • StevanC
    replied
    Originally posted by Hoppy View Post
    StevanC

    John Bedini explains that the input is isolated from the output because the coil discharge happens when the transistor is 'off', so the supply battery cannot add voltage to the coil discharge in either output configuration.

    Hoppy
    Hoppy,
    does this picture, i hope i will upload, describe what we are discussing about?

    feel free to edit it to match?
    Attached Files

    Leave a comment:


  • Hoppy
    replied
    Originally posted by StevanC View Post
    I see,
    so You add up the powering battery's voltage to the spike voltage. You get more 'bang for buck' without loosing any more energy, provided the powering battery is below the receiving battery's voltage?

    I tried it, but I'm kind of more comfortable to do it 'vanila' way?
    StevanC

    John Bedini explains that the input is isolated from the output because the coil discharge happens when the transistor is 'off', so the supply battery cannot add voltage to the coil discharge in either output configuration.

    Hoppy

    Leave a comment:


  • StevanC
    replied
    Originally posted by Hoppy View Post
    No, only the coil discharge should charge the receiving battery. I'm talking about the option to either connect the negative terminal of the charging battery to either 0V ground or the positive of the supplying battery.

    Hoppy
    I see,
    so You add up the powering battery's voltage to the spike voltage. You get more 'bang for buck' without loosing any more energy, provided the powering battery is below the receiving battery's voltage?

    I tried it, but I'm kind of more comfortable to do it 'vanila' way?

    Leave a comment:


  • sucahyo
    replied
    Originally posted by Hoppy View Post
    Switching the Joule Thief to positive return coupled with the use of Tesla style bifilar connected power coils should increase the radiant and this will drive big banks of LED's to give very good light output because of the RF content in the output. To test the radiant level, use a capacitor to store the discharged energy from the coil and measure the voltage level. The higher the DC voltage reached, the higher the radiant produced. Too much input voltage could saturate the coil and reduce the radiant level. Because of the high RF content, one wire output working is possile to light LED's.
    Thanks for the info, I guess I have to try to reach that.


    About frequency, anyone ever notice that charging part and lighting in secondary part require different resonant frequency? at least at my circuit the charging part seems to need much higher frequency than the lighting part. The lighting part become dim when the frequency made the chaging part have the most volt.
    Last edited by sucahyo; 02-06-2009, 03:35 AM.

    Leave a comment:


  • Joit
    replied
    i build now one up to, but the same, it didnt work first.
    Coudnt figure, why it should make anything, when the base is connected to Plus.
    Then i figured out, i had to switch the Wires, one from left side and one from right side to Plus, that the Current run opposite and the Coils start oscillating.

    Now it runs with AC DC with my Sharpener and a Pencil over a BC548C as Source and at the OSC with very very weird Waves.

    Leave a comment:


  • Hoppy
    replied
    Originally posted by Bodkins View Post
    Hi Hoppy
    when charging a cap connect a ground to the negative it help the radiant charging.
    YouTube - Maybe negative resistor

    hope it helps
    B
    Cheers for the tip.

    Hoppy

    Leave a comment:


  • Hoppy
    replied
    Originally posted by StevanC View Post
    You mean to let the supplying battery power both the coil and the receiving battery?
    And additionally let the coil strike over the receiving battery?

    or?
    No, only the coil discharge should charge the receiving battery. I'm talking about the option to either connect the negative terminal of the charging battery to either 0V ground or the positive of the supplying battery.

    Hoppy

    Leave a comment:


  • slayer007
    replied
    They do work but the ferrite ones work twice as good.

    Leave a comment:


  • Joit
    replied
    Duuh,
    I am allready wind one, but its a colored Ringcore. Thanks for warning.

    Leave a comment:


  • slayer007
    replied
    Originally posted by Joit View Post
    @Slayer you talk about the Ring- or Cylinder Cores, or Iron and Ferritcores in general?
    Yes the colored toroid cores are made of iron powder.
    They don't work as near as good.
    When you make one make sure you get a toroid core thats ferrite.

    Leave a comment:


  • Joit
    replied
    @Slayer you talk about the Ring- or Cylinder Cores, or Iron and Ferritcores in general?

    Leave a comment:


  • StevanC
    replied
    Originally posted by Hoppy View Post
    Hi Stevan C
    Battery charging and battery conditioning (energising) are different things and require different waveforms. A high frequency, high radiant content waveform will also charge a battery but not as efficiently as a , low radiant, low frequency pulsed waveform. Also, try connecting the charging battery neg terminal to 0V ground instead of the pos supply rail as is the convention with Bedini energisers. I find battery charging is more efficient with a 0V return and conditioning best with a return to the pos supply rail.

    Hoppy
    You mean to let the supplying battery power both the coil and the receiving battery?
    And additionally let the coil strike over the receiving battery?

    or?

    Leave a comment:


  • slayer007
    replied
    I know I posted this a page ago but make sure you use a ferrite core NOT the powered iron.
    With the ferrite cores I can light a 90v neon off my secondary winding Using just a 1.2v AA.
    I have to use a analog meter to read it after it goes through a rectifier.
    My cheap digital meters wont read it they just go nuts.
    I dont know if it's pulsing to fast or if the meters are seeing some of the HV back spike but they don't work to read it.

    I have a colored toroids that is powered iron wound the same way and I can NOT get any voltage out of the secondary coil.
    It reads 0 volts.

    So use FERRITE cores your BEMF will be twice as high and then your secondary winding will to.

    Now I thinking about taking the iron core out of my pulse generator and replacing it with a ferrite core.
    If it makes this big of a differance with the JT it should with that allso.

    Leave a comment:


  • Bodkins
    replied
    Hi Hoppy
    when charging a cap connect a ground to the negative it help the radiant charging.
    YouTube - Maybe negative resistor

    hope it helps
    B

    Leave a comment:


  • Hoppy
    replied
    Originally posted by sucahyo View Post
    I see. So that is the reason to use twice source voltage for charged battery.


    I think Joule thief would be more efficient if we use source positive as return path. Not 0V ground like many has use.
    Yes, this is the big advantage of radiant charging. Small potentials can be converted to much higher potentials for charging batteries that have a higher voltage than the source supply. But the conversion process reduces the available current proportionately, so the battery charges at a slower rate. Its not necessarily that more power is made available to charge a battery than was input to the device (OU) but its the high voltage radiant energy that John Bedini has shown can result in a process within the battery that increases its capacity. The desulfation process frees up cell plate area and this can result in a considerable increase in capacity. Some people have claimed that this is evidence of OU, because their batteries start to perform much better.

    Switching the Joule Thief to positive return coupled with the use of Tesla style bifilar connected power coils should increase the radiant and this will drive big banks of LED's to give very good light output because of the RF content in the output. To test the radiant level, use a capacitor to store the discharged energy from the coil and measure the voltage level. The higher the DC voltage reached, the higher the radiant produced. Too much input voltage could saturate the coil and reduce the radiant level. Because of the high RF content, one wire output working is possile to light LED's.

    Hoppy

    Leave a comment:

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