Hi folks, I am having some good results from this charging circuit.
I added a 12 volt-1.5 farad car audio capacitor across the charge battery.
I will post the exact circuit i am using sometime today.
I have run many tests and have just made two consistent tests, showing efficiency above 100%.
I am using one 12 volt tractor battery, 235cca as charge battery, as my bank of 3 in parallel, takes too long for testing.
I use a cen-tech inverter with led bulb connected as a discharge load.
Then measure amperage with a 1 ohm resistor at start and end of predetermined discharge, which is based on observing previous voltage of battery under discharge, when it blips to a certain voltage value, then test is done.
Input is 19.45 volts, from a laptop power supply and average amperage is determined by again using 1 ohm resistor to check at beginning of charge run and end of charge, voltage stays the same with this psu.
The input for both tests is 5.7 watt hours, charger is run for exactly one hour.
Test 1:
Input = 5.7 wh
Output = 8.6 wh
Efficiency = 151%
Test 2:
Input = 5.7 wh
Output = 8.9 wh
Efficiency = 156%
All questions, replies, comments much appreciated.
peace love light
Edit: one more thing, be sure to allow the capacitor to keep charging the battery, even when power source is disconnected, because at least with my capacitor, there is a lot of juice left to help charge battery.
I added a 12 volt-1.5 farad car audio capacitor across the charge battery.
I will post the exact circuit i am using sometime today.
I have run many tests and have just made two consistent tests, showing efficiency above 100%.
I am using one 12 volt tractor battery, 235cca as charge battery, as my bank of 3 in parallel, takes too long for testing.
I use a cen-tech inverter with led bulb connected as a discharge load.
Then measure amperage with a 1 ohm resistor at start and end of predetermined discharge, which is based on observing previous voltage of battery under discharge, when it blips to a certain voltage value, then test is done.
Input is 19.45 volts, from a laptop power supply and average amperage is determined by again using 1 ohm resistor to check at beginning of charge run and end of charge, voltage stays the same with this psu.
The input for both tests is 5.7 watt hours, charger is run for exactly one hour.
Test 1:
Input = 5.7 wh
Output = 8.6 wh
Efficiency = 151%
Test 2:
Input = 5.7 wh
Output = 8.9 wh
Efficiency = 156%
All questions, replies, comments much appreciated.
peace love light

Edit: one more thing, be sure to allow the capacitor to keep charging the battery, even when power source is disconnected, because at least with my capacitor, there is a lot of juice left to help charge battery.







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