My LAHF
I am part way through a LAHF build.
I am planning to use a 15000 volt 30ma Neon Sign transformer for the disasociation arc.
Take a look at my calcs
Hydrogen Bond Dissociation Energy = 432 kj/mole
Neon Sign transformer delivers 15000v x .032a = 480 watts/second
therefore = 900 seconds to dissaciate 1 mole @ 100% efficiency.
I am arbitrarily guesing 50 % efficiency so 1800 seconds to dissociate 1 mole.
1 mole of hydrogen at STP = 22.4 litres
therefore 1 litre dissociated in 80 seconds.
This is so I can set a reasonable gas flow rate for the arc I have.
According to Bill Lynes book 1 mole of recombined H2 = 196200 BTUs
= 49441Kcal
1 Kcal of heat will raise the temperature of 1 litre of water 1 degC
Therefore 1 litre of recombined hydrogen should raise the temperature of 1 litre of water 220degC.
The energy supplied by the arc in 80 seconds is 38400 joules = 9.2 Kilocalories.
My water container is about 2 litres and with heaps of heat loss etc etc if I see the temperature rise more than 4.5 degC then I will be on to something.
If I can raise it 80 degrees then I ould call the experiment a great success.
anyway if someone could check my figures and see if theere are any glaring mistakes.
Thanks LV
I am part way through a LAHF build.
I am planning to use a 15000 volt 30ma Neon Sign transformer for the disasociation arc.
Take a look at my calcs
Hydrogen Bond Dissociation Energy = 432 kj/mole
Neon Sign transformer delivers 15000v x .032a = 480 watts/second
therefore = 900 seconds to dissaciate 1 mole @ 100% efficiency.
I am arbitrarily guesing 50 % efficiency so 1800 seconds to dissociate 1 mole.
1 mole of hydrogen at STP = 22.4 litres
therefore 1 litre dissociated in 80 seconds.
This is so I can set a reasonable gas flow rate for the arc I have.
According to Bill Lynes book 1 mole of recombined H2 = 196200 BTUs
= 49441Kcal
1 Kcal of heat will raise the temperature of 1 litre of water 1 degC
Therefore 1 litre of recombined hydrogen should raise the temperature of 1 litre of water 220degC.
The energy supplied by the arc in 80 seconds is 38400 joules = 9.2 Kilocalories.
My water container is about 2 litres and with heaps of heat loss etc etc if I see the temperature rise more than 4.5 degC then I will be on to something.
If I can raise it 80 degrees then I ould call the experiment a great success.
anyway if someone could check my figures and see if theere are any glaring mistakes.
Thanks LV
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