Eric P. Dollard

[madhatter]

The answer = a few billion %

I'll have to take a closer look at this Excel business and try the equations on paper instead to see if it's doing anything stupid. Even using something stupid like ϵ = 0.00000000001 just to see what would happen resulted in over 3000% So something is not right somewhere.

Not to worry, try this. Put in cell A1: 1.256E-6 and in A2: 8.854E-12 then use this formula in another cell: =1/sqrt(A1*A2) that should yield: 299,871,658.40

Definitions:
ε0 ≈ 8.854187817620... × 10−12 farads per metre (F·m−1)
µ0 = 4π×10−7 V·s/(A·m) ≈ 1.2566370614...×10−6*H·m−1 or N·A−2 or T·m/A or Wb/(A·m)

The result in the speed of light, must be a typo in the notes above for inches/sec as the result is metric. It can be done in imperial units, it would require all units to be in imperial, not sure why one would do this as SI is metric and going thru to make sure the units are are on equal footing in metric terms is a fair amount to juggle as is.

[Nhopa]

Full size pictures

I use ImageShack® - On line Photo and Video Hosting

When you click on "Share It" for an image it gives different links for thumbnails or full size etc......

Hi dr-Green:
Sorry to bother you. I signed up for the basic service as you recommended. I can upload my pictures but can't transfer them to the forum web page. I don't seems to have the "Share it" function. What I have is
ACTION
create album
create slide show
post to blog
exit images
mark as private
mark as public
delete
get code for forums
get code for websites
get code for email
add tags
remove tags
upload images
None of the above allows me to post to this forum.
By the way I am so glad that you are ahead of me and most likely of others with your project. I was afraid I will run into the same problems you are trying to work out for us who follow.

[David G Dawson]

Extra Coil Working Point

Attaching the drawing I made of the Luminal point where the Extra Coil is working or should be working at.
As you can see from the diagram, Eric's is before the frequency of concern where mine is after and also gives the correct length for the Extra.
Looking at this from what I presented earlier and was talking of 1/8 and 1/4 wave and that is now confusing and please disregard.
Will attempt to explain it so it can be understood clearly and working on that now.

Smokey

[David G Dawson]

Presenting Pictures Full Size

Aaron,
Is there anyway you can assist here to make the presentation of pictures made easier by click and drag method without using a 3rd Party for hosting the pics?

Eric needs to see a full picture and all I/we can provide are Thumbnails which he is unable to see from where he connects in to the site.

Have also noted today that I had to delete previous uploaded thumbnails to make room for today's pics and these I would think have now been lost from the system.

Hope you can help.

Smokey

[dR-Green]

Those photos of RCA Bolinas are amazing, those fractals are beautiful!

DrGreen,
If you have a number in Farads per meter and you want the answer in farads per inch you multiply by meter per inch and the meters cancel.
Eg; Farads per meter * meters per inch
So the number you'd multiply is 0.0254, giving the vacuum permittivity as 2.2489X10^-13 Farads per inch

I'll convert this to equation images when I get home. Does this help your numbers at all?

Raui

Thanks for the effort but that doesn't work either. The way I did it was this

=(8.85418781762*POWER(10,-12))/39.3700787

But both give the same answer so at least that seems to be right. I'm not convinced that it's not an Excel issue at this point. Started the equations from scratch three times and spent countless hours changing things and putting equations and sums in separate boxes in case it's not working out properly by all being in the same box etc, still getting nowhere with it.

[dR-Green]

1 / SQRT(mü*epsilon) = v

[mü] = Farad/m
[epsilon] = Henry/m
[v] = m/s

i.e.

1 / SQRT(1.256*10^-6 Henry/m * 8.854*10^-12 Farad/m) = 2.9987*10^-8 m/s = 299870 km/s

The answer = a few billion %

I'll have to take a closer look at this Excel business and try the equations on paper instead to see if it's doing anything stupid. Even using something stupid like ϵ = 0.00000000001 just to see what would happen resulted in over 3000% So something is not right somewhere.

[Raui]

Those photos of RCA Bolinas are amazing, those fractals are beautiful!

DrGreen,
If you have a number in Farads per meter and you want the answer in farads per inch you multiply by meter per inch and the meters cancel.
Eg; Farads per meter * meters per inch
So the number you'd multiply is 0.0254, giving the vacuum permittivity as 2.2489X10^-13 Farads per inch

I'll convert this to equation images when I get home. Does this help your numbers at all?

Raui

[David G Dawson]

Extra Coil Test

Had the pics in order but are not presented in that manner.
First pic is # 3 My 2nd
Second is # 1 My 1st
Third is # 2 Eric's Math

Smokey

[David G Dawson]

Extra Coil Test

Extra Coils Test:
Signal Generator:
Wavetek Model 191 Pulse FG 20Mhz
Frequency Meter: Sinometer VC3165 0.1 Hz ~ 2.4 Ghz

Extra Coil #1 14awg 54 turns (50.3 calculated) 'The 'Accidental Coil' as I was aware the Secondary and the Extra should be about the same length.
Adjust = 130mm 5.125"
Volts imput = 295mV + 10db output attenuation
Fpeak = 2369.5 Khz (1557 Khz *pi/2 = 2.445.7 Khz) close and needs to lose some turns.
Cvar = 300 pF
Height above Ground Plane = 12.75"

Extra Coil #2 21 awg 125 turns including 1 extra turn - Eric's Math which I am disputing.
Adjust = 65mm
Volts input = 820 mV + 10db output attenuation
Fpeak = 1024.9 Khz
Cvar = 267 pF
Height = 14"

Extra Coil #3 Same as #1 but 11 awg and 56 turns
Adjust = 70mm
Fpeak = 2650.9 Khz - needs to have turns pruned back to about the 50 and would also expect Volts to reduce as well.
Volts input = 780mV + 10db attenuation
Cvar = 212 pf
Height = 12.125"

Hands up those that can see the problem?
Some Math about 1557 Khz - what do you want to do?
Go to the high side of the 1557 or the low side where it is a cow to tune and you are working on the tail end of the Luminal wave and not at the beginning - See my drawing.
1557 *pi/2 = 2.445.7 where I am working.
1557 /(pi/2) = 991.2 Khz where you are working - see Extra Coil #2 at 1024.9 Khz - only a 34 Hz discrepancy.

Hands up all those that have produced the 1N34 pickup head into high impedance Headphones and are able to receive a signal through the air for nothing coming from your Extra Coil some 10 " away without using some large metal receiving antenna where I am using a pin head?

I repeat:
The Secondary and the Extra are the same length!
I have a working passive TMT, you don't!

All of this was displayed at 'n6kph' where you were supposed to be operating and now I feel I am just wasting my time here and you have the audacity to question how 'quiet' we all are!

I will set up some means of charting the Field Intensity Meter but the peak is of a high 'Q' nature and really is not going to reveal much.
Will do Secondary tomorrow after tuning # 1 and #3 for turn peaks for frequency match.

Last pic is of an integrated Capacitor into the Primary which I am not quite happy about and needs strap connections which I have not done as yet.
At least I now have tuning capability on the Primary.

Tried to put up full size pics but not obvious how that is done - Later.
Just feel I am wasting my time.

Smokey

[magnetO]

I'm stuck. Can someone please explain what this highlighted symbol means? Below it is the only thing I was able to find in Condensed Intro To Tesla Transformers page 28, but I have no idea what value it's supposed to have or anything? It's also there again on page 26.

1 / SQRT(mü*epsilon) = v

[mü] = Farad/m
[epsilon] = Henry/m
[v] = m/s

i.e.

1 / SQRT(1.256*10^-6 Henry/m * 8.854*10^-12 Farad/m) = 2.9987*10^-8 m/s = 299870 km/s

[dR-Green]

Thanks but I can't seem to get any sense out of whatever I try. Tried all kinds of things I've been reading about, converting them to imperial etc etc, I just get ridiculous numbers as the result.

[edit] I'm doing it in MS Excel and when doing Tesla's velocity of the wave around the earth calculation before it became obvious that Excel gave a different result to a calculator, the units in Excel had to be converted into radians for the answers to match. So I just realised something like that could be going on here Spent the best part of today and yesterday trying to figure this little number out

[madhatter]

Unless defined by the writer Epsilon naught is the vacuum permittivity: Vacuum permittivity - Wikipedia, the free encyclopedia

also it has a mathmatical meaning as well:
ε₀ - Wikipedia, the free encyclopedia

Or it can be any definition as defined by the author, in one of the cases above it's prescribed to the natural log, base e:
Natural logarithm - Wikipedia, the free encyclopedia
Euler number - Wikipedia, the free encyclopedia
e - Euler's number

Then we get into Eulers equation: Euler's identity - Wikipedia, the free encyclopedia

[dR-Green]

It is a lower case epsilon, ϵ, dielectric constant of the space around the coil.

I don't get it. I have numbers like 7327.84861% 1 is obviously wrong and so is 2.71828.

8.854187817620 x 10^-12 doesn't work either, not least I think because it's Farad/metre and the equations are in inches. 8.85... x materials constant from the list above doesn't yield any reasonable results either. I have no idea what value it's supposed to have. Can someone please advise?

Also what is the 2.54 x 10^-12 about in equation (2)? How is it supposed to be applied? I'm having to use the Radiotron version in cm.

[madhatter]

Quiet, A bit. been busy acquiring stuff off ebay, now to get onto the power supply side.

[OrionLightShip]

Use a variable capacitors to fine tune the inductive p. tesla coil or loop on resonance frequency . (extra butterfly or dual capacitor can give better SWR
however i did not use it by so for got good SWR with just the parallel capacitor. this sytem replace a `normal`antenna tunner .

do not use normal antenna tuners. it will blow up amplifiers . i use mostly 200mWatt or about 24dBm to see if the systems work .

"Are we saying that it's impossible to damage any radio transmitter by having a “bad” load? No, not at all. You can torch almost any transmitter by putting a dead short on it. And you can fry most modern radios by having an open circuit on them, as well, mainly by over-voltage of the output transistors. But it is NOT the SWR that does the damage! NEVER NEVER NEVER. A transmitter always sees an IMPEDANCE; it never sees an SWR. And don't ever forget it. "

Quote from eHam.net article titled, "SWR Meters Make You Stupid"