Originally posted by Farmhand
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So some usefull information would be the frequencies of the higher order harmonics of 11.79 Hz. I wonder how to work that out.
And if the magnification effect indeed is like I think it is, then you get an enormous multiplication of the energy, since you have to provide only the energy to keep one dipole of the standing wave going, the other 1696 in this calculating exercise are powered by the zero-point field for free
So, if you want to check wether or not this theory works out like I think it will, you could connect transmitter and reciever trough a coax cable with a length equal to a whole number of wavelengths corresponding to your oscillation frequency. If your oscillation frequency equals 1 MHz, you have a wavelength of 300 meters, so then you would at least need 300 meters of coax. Or maybe a 1/4 of that will also work, which would still mean 75 meters. If my understanding is correct, a coax of 300 meters for 1 Mhz may actually multiply 4 times, because you only have to drive 1/4 resonance yourself, but I am not sure.
So, for practical testing, you may have to go to 10 MHz or higher (as Stiffler does), because otherwise you will have to invest in quite a lot of coax....
Update: If you want to experiment with coax, you have to correct for the velocity difference between the air and the cable of choice, which equals 66% for RG-213, for example:
Wave propagation speed - Wikipedia, the free encyclopedia
So, if your oscillator runs at 10 MHz, you have a wavelength of 30 meters. In that case, if you use RG-213, the length of the coax cable should be a multiple of 0.66*30= 19.8 meters.


What is the opposite term to "improvement" ?



Just kidding please don't answer that question, i'm not sure I want to know that.
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