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Water Fuel This forum is for discussion on any water fuel topic dealing with electrolysis, Stanley Meyer, hho, Brown's Gas, Puharich, etc...

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  #61  
Old 12-09-2008, 06:09 PM
Gauss Gauss is offline
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In my opinion hte VIC is the second step after the WFC, the VIC incorporates the transformer and the choke in one component, that is the key component to master to build the gas processor I believe. Stan evolved from WFC to VIC to gas processor during 15-20 years.
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  #62  
Old 12-10-2008, 12:44 AM
h20power h20power is offline
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Okay I will go over the WFC, Injector, and Gas Processor and the role they play.

Quote:
Originally Posted by boguslaw View Post
Well...h2opower, I agree with your theory - you solved part of Meyer plan, but this is only for getting efficient explosive gas for running combustion engine.What about gas burner ? I think we still need complete understanding of WFC for other appliances.
Oh dear...and look for Meyer injector patent.Do you see voltage zones ? It is still based on the same principle evolved from basic WFC device
The WFC
The key to getting the WFC working is the EEC. When electricity passes through water the water molecule has close to a 1:1 break down and reformation ratio. So, when it is like this nothing happens but the hydrogen and oxygen from waters low break down voltage directly at the electrodes. In order to break the chain of the 1:1 reaction Meyer's added in the EEC to consume the negetive ions. This puts the reaction out of ballance nolonger is it 1:1 for the positive ions have no negetive ions to keep the stublility, and free hydrogen is what you get as a result. Once you unballance the equation like this you will see free hydrogen form close the middle of the electrods. In the WFC the EEC shares it's conection with the choke too the positive electrode, and they are 180 degrees out of phase. So when one is on the other is off, like a SPDT switch. It produces the ions in one step and then consumes some of the ions in the nexted, changing the 1:1 ratio. Remember the gap is only .06 - .01 inches. The unit must not have any grounds it must be a comepletely isolated circuit. For if you have a ground in the system when the EEC turns on it will sense the negetive and start producing standerd Faraday electrolysis.

The Injector
The injectors do have a voltage zone but this is to ignite the mixture. But what it is really doing is polarizing the water molecule with a negetive charge so when it is sprayed out as a mist the resulting mist droplets repel each other and not form into larger water droplets. The water mist negetively charged turns into an ever expanding plume of ever decreasing size water droplets as the voltage divids when it evaporates spliting the water droplets as they do. This aids the mixing process as the droplets will be as very small, atomized. Like charges repel each other and opposite charges attract to each other. Meyer used the properties of water and oxygen to aid in mixing and combustion, being that both of them have magnetic properties.

The Gas Processor
The Gas Processor charges the incoming air striping it to higher energy levels, and uses coherent light to aid in this process. It does so be electron and photon bombardment. The EEC on the gas processor is not hooked up too the positive electrode, but is set as a mesh behind the Gas Processor to catch and consume negtively charged electrons/ions that where ejected from the oxygen atom leaving mostly negetively charged atoms to go into the combustion chamber. Again the EEC and the positive electrode are pulsed oppsite too each other, and the coherent light pulses with the EEC. The coherent light should be aimed and/or chosen too hit the absorbtion spectrum of oxygen, since it is the gas we are most interested in concerning the incoming air through the intake system. This also aids to stop the formation of ozone for the oxygen atoms left after the EEC mesh repel each other for they mostly have the same charge and like charges repel each other. The EEC puts a positive voltage zone to consume any electrons that was stripped off of the oxygen atoms so to keep the oxygen atoms from having a full set of electrons. The amp consuming device will complete it's circuit by consuming the negetive ions and electrons, thus lighting up the bulb(s). Plus the EEC's mesh also helps cuts down the formation of ozone.

The recirculated exhaust gases have no net charge and impead the reaction of the positively charged water molecules and the negetively charged oxygen atoms seeking each other by getting in the way, thus slowing down the reaction.

Let the Revolution begin,

h2opower.
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Last edited by h20power; 08-05-2009 at 04:28 PM. Reason: changed electrons to ions and make more clear the EEC
  #63  
Old 12-10-2008, 07:58 AM
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boguslaw boguslaw is offline
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Meyer Injector. Take a look at travelling voltage waves.
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File Type: jpg injector.JPG (50.6 KB, 144 views)
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  #64  
Old 12-10-2008, 06:50 PM
h20power h20power is offline
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And what is it do you want me to see and/or understand?

The negetive voltage zone (67) E10 is grounded for it is screwed right into the head of the engine, eg. replacing the spark plug.

Now I ask you this: What is the cone shapes relationship towards capacitance and magnetic field strength? What happens to capacitance as the area of the cone decreases, and also what happens to the magnetic field as the area of the cone decreases?

What I am asking of you is to pull out of the patent and go back into physics, for it answers the question.

h2opower.
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  #65  
Old 12-11-2008, 03:04 PM
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boguslaw boguslaw is offline
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Another interesting tip you should really consider :

Quote:
Science writer John W. Campbell, Jr, however, envisioned magnetic charges with mutual attraction forces equivalent to millions of volts operating in small practical machines. He speculated that, "A magneto-electret --- consisting of a coil of magnetic conductor carrying a heavy magnetic current --- would develop electric potentials that did not tend to arc across. Perhaps a small magnetic coil would develop 50,000,000 volt potentials that could tear atoms apart".
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  #66  
Old 12-11-2008, 03:10 PM
rdmwc rdmwc is offline
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h2o, in meyers patent on his injector doesnt it show the base of the injector plug (part that screws into the head of the engine) the positive voltage plate? also, i am probably wrong on this due to my lack of education in this matter, but when the lazer priming and eec removes the electrons, doesnt that leave a positively charge ( more protons than electrons) oxygen atom?

Royce
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  #67  
Old 12-11-2008, 05:25 PM
h20power h20power is offline
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Quote:
Originally Posted by rdmwc View Post
h2o, in meyers patent on his injector doesnt it show the base of the injector plug (part that screws into the head of the engine) the positive voltage plate? also, i am probably wrong on this due to my lack of education in this matter, but when the lazer priming and eec removes the electrons, doesnt that leave a positively charge ( more protons than electrons) oxygen atom?

Royce

Wow, your very observent, not many people caught that lie Stanley Meyer told. Trust your instinks, for you are right. But on the EEC look at it this way, you have a ground(-) and a mesh collector(+) in order to light up the light bulb you have to connect it to positive source for the other end is grounded, thus the ejected electrons are consumed, leaving mostly negetive ions to travel into the combustion chamber. The one thing I like to point out in all of this water for fuel technology is this, no laws of physics are broken not a one! Knowing this anyone studing this technology has to constantly go back and forth from the patent to modern science in a real investigative sense. If anyone thinks it was easy to uncover Stanley Meyer patents think again, for it was very hard, for Stanley Meyer didn't make it easy.

But keep the questions coming for that is how the water for fuel technology got solved in the first place I kept asking questions, but more importantly I would answer those questions I had ask myself concerning the water for fuel technology. This video gives a very good example on how to go about asking questions and answering them: What does it mean to be a citizen?



h2opower.
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Last edited by h20power; 02-07-2009 at 09:12 AM. Reason: added more understanding
  #68  
Old 12-11-2008, 05:38 PM
h20power h20power is offline
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Quote:
Originally Posted by boguslaw View Post
Another interesting tip you should really consider :

Listen I don't want any quotes, I want answers to my questions. For the one thing I am trying to do is to get you to look outside of the patent for the answers. If you don't know then tell so, for I will answer the question for you. But at the least I want you to try and answer the questions. Remember I am not picking on you, but only trying to get you to see what was done by Stanley Meyer. The answers can not be found in the patent.

You can do this for I belive in you and belive that you can.


h2opower

Jan 1 2009, this is the answer to the question: How you get voltage to do work is by physically changing the voltage zone. The field always hits at 90 degrees to the surface, so with the cone shape as you move down the voltage zone the area physically gets smaller thus nolonger having the same capacitance capabilities. And the magnetic field lines have less area thus increasing the magnetic field strength as you move down the voltage zone. So capacitance decrease and magnetic field strength increases. Capacitance is only a matter of geometry, not charge, for it is never a function of the charge. That is what the cone shape is doing, hope this aids in your understanding of the pic you posted.


h2opower.
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Last edited by h20power; 01-01-2009 at 08:55 PM. Reason: Added in the answer to the question.
  #69  
Old 12-11-2008, 06:02 PM
rdmwc rdmwc is offline
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so the EEC , the bulb is grounded on one side obviously, but the other is just wired to the mesh? i thought the mesh has positive voltage to it and creates a positive voltage field which attracts the freed negative electrons then they flow to the light bulb being consumed by the filament. ? sorry if my questions annoy you, hopefully they wont; all im asking for christmas are quantum mechanics, physics, chemistry, and electronics text books!
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  #70  
Old 12-11-2008, 06:20 PM
h20power h20power is offline
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Quote:
Originally Posted by rdmwc View Post
so the EEC , the bulb is grounded on one side obviously, but the other is just wired to the mesh? i thought the mesh has positive voltage to it and creates a positive voltage field which attracts the freed negative electrons then they flow to the light bulb being consumed by the filament. ? sorry if my questions annoy you, hopefully they wont; all im asking for christmas are quantum mechanics, physics, chemistry, and electronics text books!
On the Gas Processor the Mesh grid is just after the gas processor and is not hooked up too the choke coil and/or shared with it like the WFC is. Some call it an air battery for in a sense that is how it works. The air flow brings the freshly ejected electrons too the positively charged mesh grid and completes the circuit. And yes it is just wired too the mesh grid I think it has an optocupler to tell it when to come on for it is on when the pulse is off to the Gas Processor.

h2opower.
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Last edited by h20power; 02-07-2009 at 09:16 AM. Reason: had it backwords
  #71  
Old 12-12-2008, 09:20 AM
magnetO magnetO is offline
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postive electrons?

Hi h20power,

may I ask you, what "positve electrons" are?

I have already read many of your contris, but not all yet. It would be very kind of you, giving me a link or something else, where 'your' positive electrons are explained.

Thank you
magnetO
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  #72  
Old 12-12-2008, 10:05 AM
h20power h20power is offline
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Quote:
Originally Posted by magnetO View Post
Hi h20power,

may I ask you, what "positve electrons" are?

I have already read many of your contris, but not all yet. It would be very kind of you, giving me a link or something else, where 'your' positive electrons are explained.

Thank you
magnetO
No, thank you! Like I said in a lot of my postings if I make a misteak don't have any fears in correcting me, for any misteak I make wont stop the Gas Processor from working. It is called a positron e+ found here: Electron - Wikipedia, the free encyclopedia found under "Fundamental properties" So I will call it by the correct name from now on

So, as I was saying the "positrons" need to be consumed so there are no positrons(e+) to form up with the electrons(e-) to make ozone in the intake system after the Gas Processor has primed the incoming air.

Thanks for correcting me for it shows people are reading and will start becoming energy independent soon.


h2opower.
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Last edited by h20power; 12-12-2008 at 10:18 AM.
  #73  
Old 12-12-2008, 11:29 AM
magnetO magnetO is offline
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Hi h2Opower,

puuuh, it doesnt get easier to me. I need to read ALL your posts and the whole thread. Will hopefully do so.
It seems to me you are more likley a physicist, than a electrician. Is it so?

Supposed, we have already split water, what most be done further?


1.Do we get atomic O? If yes, we have to strip e-? How many?
2.Dont we have a chance for O, but only for O2? Do we strip e- from O2? How many?
3.Do we get a proton? Can we prevent from getting e-? I guess, no, but what would you say?
4.So, do we get atomic H? Can we give it some e+? I guess, no, but what would you say?
5.Do we get H2? What doing further?

6.Do we want the ~20% O2 in (combustion) air getting something else? Ozon?


Feel free to answer or not to answer, please.
At first, I should reading, reading, reading,....

Thanks
magnetO
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  #74  
Old 12-12-2008, 03:11 PM
leanderborg220 leanderborg220 is offline
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Hi H20power.
In this Meyer drawing I can`t see any electron collecting Mesh for the EEC. What do you think ?
What gap do you suggest for the air ionizer ?

Hmask
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File Type: jpg gas processor.JPG (74.7 KB, 164 views)
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  #75  
Old 12-12-2008, 04:40 PM
rdmwc rdmwc is offline
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magneto, as far as the taking the electrons away, now H2Opower correct me if im wrong, but i believe we want to take away as many as resonably possible for the more we take away the less stable and more energy they will have... my biggest question right now is what is the purpose of the lazer distibutor and the effect the lazer light has on the mixure at the end of the injector plug... is this his final design that does away w the external gas processor and confines all his technologies into one unit?
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  #76  
Old 12-12-2008, 04:58 PM
h20power h20power is offline
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Quote:
Originally Posted by magnetO View Post
Hi h2Opower,

puuuh, it doesnt get easier to me. I need to read ALL your posts and the whole thread. Will hopefully do so.
It seems to me you are more likley a physicist, than a electrician. Is it so?

Supposed, we have already split water, what most be done further?


1.Do we get atomic O? If yes, we have to strip e-? How many?
2.Dont we have a chance for O, but only for O2? Do we strip e- from O2? How many?
3.Do we get a proton? Can we prevent from getting e-? I guess, no, but what would you say?
4.So, do we get atomic H? Can we give it some e+? I guess, no, but what would you say?
5.Do we get H2? What doing further?

6.Do we want the ~20% O2 in (combustion) air getting something else? Ozon?


Feel free to answer or not to answer, please.
At first, I should reading, reading, reading,....

Thanks
magnetO

Hi MagnetO,
I am going to ask you too read the whole bit of posting for most of the answers to your questions are in there. At the end of your reading if you have questions, use the 5 step inteligence question asking and answering also given in my postings.

h2opower.
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  #77  
Old 12-12-2008, 05:08 PM
h20power h20power is offline
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Quote:
Originally Posted by leanderborg220 View Post
Hi H20power.
In this Meyer drawing I can`t see any electron collecting Mesh for the EEC. What do you think ?
What gap do you suggest for the air ionizer ?

Hmask
Yeah, I have gone over those drawing too, Meyer seems to have left off any showing of the EEC mesh grid.
Things to consider, the electric breakdown voltage of air and the time it takes for O- to seek out and combine with O2 to form Ozone. We will need to do gas speed calculations with the two considerations in mind, for we don't want sparking from the gas processor to the EEC mesh grid, and we also don't want to form ozone. The physical size of your Gas Processor will determine those needs once the gas speeds are known. Remember we don't want the engine trying to suck air through a straw.

h2opower.
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  #78  
Old 12-12-2008, 05:32 PM
h20power h20power is offline
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Quote:
Originally Posted by rdmwc View Post
magneto, as far as the taking the electrons away, now H2Opower correct me if im wrong, but i believe we want to take away as many as resonably possible for the more we take away the less stable and more energy they will have... my biggest question right now is what is the purpose of the lazer distibutor and the effect the lazer light has on the mixure at the end of the injector plug... is this his final design that does away w the external gas processor and confines all his technologies into one unit?
Yes, you are right rdmwc, it's all in percentages. The higher the voltage amplitude the greater the percentage of unstable gases sent too the combustion chamber. That give us control of the process so too make good use of it. The lazer distributor was replaced by direct pulsing of the LEDs in Meyer later designs. The lazer distributor had a beem cutter to send pulsed photonic energy to the mixture aiding in striping electrons from the mixture.

Remember we are talking about energy levels and oxygen. Oxygen has 8 energy levels and I have already given the energies in kJ/mol of each of the energy levels. Remember the energy level of oxygen are so great that they have the power to break down the water molecule with a spark or heat ignition. Too aid this reaction the water has to be atomized and also prevented the water from reforming into larger water droplets. This is accomplished by polarizing the water giving it a positive charge, for then like charges repel each other and no reformation to larger water droplets occur. Now as water evaporates it will divide into even smaller water droplets this aids in mixing with the primed air gases.


h2opower.
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  #79  
Old 12-13-2008, 04:38 AM
h20power h20power is offline
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To correct myself and get back on topic.

Quote:
Originally Posted by h20power View Post
No, thank you! Like I said in a lot of my postings if I make a misteak don't have any fears in correcting me, for any misteak I make wont stop the Gas Processor from working. It is called a positron e+ found here: Electron - Wikipedia, the free encyclopedia found under "Fundamental properties" So I will call it by the correct name from now on

So, as I was saying the "positrons" need to be consumed so there are no positrons(e+) to form up with the electrons(e-) to make ozone in the intake system after the Gas Processor has primed the incoming air.

Thanks for correcting me for it shows people are reading and will start becoming energy independent soon.


h2opower.
Sorry about that I got caught up in the electron thing when it is "IONS" we are talking about. Positive ions and Negetive ions for all of this is based on "Ionization energies." Electrons and photons are being used to strip down Oxygen to lower energy levels, thus yeilding more energy than normally gotten from the reaction at the ground state. So my mistake was to say electrons being consumed when it is ions that are being consumed, the positive Oxygen ions. I must be more careful with my words, but I think I might have gotten that from the patent, will have to look that up. But it is IONS we are talking about, and electrons and photons are being used to push Oxygen from the ground state to higher energy levels.

Sorry for getting confused I'll do better, but as I said before any mistakes I make wont stop the Gas Processor from working


h2opower.
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  #80  
Old 12-14-2008, 02:36 AM
h20power h20power is offline
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Once you step back and take a deep look at this technology you will see it mostly has to do with chemistry. We are dealing in ions and ionization energies, valance electrons and such, not much physics here. Maybe that is why so many can't see the simplicity of it all. This is a controled lightining strom, and lightining storms don't need any plug-ins to make a tremendous amount of power. If fact lightining storms don't need any help from man at all. If you look up a lightining storm right today you will find out that humanity still doesn't understand how they work. For they are disobeying the laws of theromo dynamics big time, but if one stops to think about it, us walking and talking are also breaking these laws.

If energy can't cross the space of a vacuum then how does the sun heat up the earth? You will be suprized to learn that the simplest of things man has very little knowledge about. Know your chemistry and you will understand this technology 100%.


h2opower.
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  #81  
Old 12-15-2008, 07:34 AM
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What I can see is a largely "wasted" magnetocurrent. Have a look at the cap-HV-LV discharge ways of Gray vs Meyer. It is obvious that when you crash the inductor back EMF into the EMF in Meyer´s circuit this magnetocurrent will look for a receiver. What has the highest diel. constant near the diode? Distilled water! BUT the magnetocurrent will expand 90 deg. from the EMF like after an explosion and only some of this will reach the water. Possibly, the diode crash will cause a lot of the energy to be wasted and it will act as an LV anode inside the water, the choke+transformer will be the HV anode.

I believe there are many things about Meyer WFC to learn concerning physics. Plcement of diode is central to success.
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  #82  
Old 12-15-2008, 08:07 AM
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Meyl says that if there is straight magnetic induction line B, then electric field line are close circular around it. If Meyer tubes are two antennas generating magnetic current then electric field is "stuck" on them circularly causing large electrostatic-like effect which Meyer described as voltage potential.
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  #83  
Old 12-15-2008, 10:13 AM
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Is there an option to the Diode we are using. Is there any other way to block a HV pulse? So that it can work for long periods of time...
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  #84  
Old 12-15-2008, 05:44 PM
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Quote:
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Is there an option to the Diode we are using. Is there any other way to block a HV pulse? So that it can work for long periods of time...
I think that diode is not needed.More important if why one of coils was adjustable.
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  #85  
Old 12-15-2008, 07:51 PM
h20power h20power is offline
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The WFC is not needed!

Once again will point at the numbers to show that the WFC is not needed. For in the end not even Meyer used the WFC.
It takes 1836 kJ/mol to break the bonds of water under normal conditions this number was discovered by Dr. Faraday many years ago. Now if you take into account what the Gas Processor is doing is striping electrons from the air making them have a much higher energy content then the answer of where this energy comes from to break the water down is in the air itself.

Looking at the reactions to break and form the water molecule:
4 H-O 459 kJ/mol bonds are broken taking 1836 kJ/mol to do so.
2 H-H 436 kJ/mol bonds 872 kJ/mol and 1 O=O bond 498 kJ/mol are formed yeilding 1370 kJ/mol.
This is why all scientist say it takes more energy to break the bonds of water than you get from combining them, for the net sum of the reaction is negative, -466 kJ/mol.

Lets us look at just oxygen, since it is the most important part of the reaction, here are the energy levels of oxygen:
1st 1313.9 kJ/mol
2nd 3388.3 kJ/mol
3rd 5300.5 kJ/mol
4th 7469.2 kJ/mol
5th 10909.5 kJ/mol
6th 13326.5 kJ/mol
7th 71330.0 kJ/mol
8th 84078.0 kJ/mol

Now the 1st level doesn't have enough energy to get any useful energy yield out of it this way so you must get the oxygen at minimum to it's 2nd level of ionization.

The new reaction to form the water molecule 1st energy level:
2 H-H bonds 872 kJ/mol and 1 O=O bond 1313.9 kJ/mol are formed yeilding 2185.9 kJ/mol. The net sum of the reaction now is positive 2185.9-1836 = +349.9 kJ/mol, so now we are getting more energy out than in. But this reaction is still less than the 4864 kJ/mol of gasoline. So what do we do? Strip more electrons.

2nd energy level:
2 H-H bonds 872 kJ/mol and 1 O=O bond 3388.3 kJ/mol are formed yeilding 4260.3 kJ/mol. The net sum of the reaction now is 4260.3-1836 = +2424.3 kJ/mol, now that is close to half as much energy as the reaction for gasolines 4864 kJ/mol.
Since Meyer says he used the 4th energy level or lower lets look at that reaction.
The new reaction to form the water molecule at the 4th energy level:
2 H-H bonds 872 kJ/mol and 1 O=O bond 7469.2 kJ/mol are formed yeilding 8341.2 kJ/mol. The net sum of the reaction now is 8341.2-1836 = +6505.2 kJ/mol

Now in that reaction the unstable oxygen atoms have the power to not only break down the water molecule but to react with it with far more power than the reaction of the hydrogen and oxygen atoms do at the ground state. That is the key, it's right there in front of you. All that needs to be done is get the water to be atomized, in this new envirenment of unstable oxygen atoms, and give it a spark or heat ignition source. In order to get the water molecules atomized you have to put a charge on it or it will form back into larger water droplets. The Gas Processor and Electron extranction circuit, will effectively change the envirenment in which the reaction takes place. The unstable oxygen atoms have the power to take the hydrogen atoms away from the oxygen atoms already holding on to them and give off what Stanley Meyer calls "Thermo Explosive Energy." If you don't understand the math presented here then use the internet to teach yourself.

For this is the arguement the scientific community puts on why water for fuel shouldn't be able to take place. They speak of the 2nd law of thermo dynamics being broken, and I have shown clearly that it has not been broken. There is no magic here just energies of ionozation being used in a way they have never been used before. It is just chemistry, dealing with ionozation energies of the reaction between hydrogen and unstable oxygen atoms.

Energy independence is now ours for the taking,

h2opower.
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Last edited by h20power; 03-07-2009 at 07:16 PM.
  #86  
Old 12-15-2008, 09:40 PM
Gauss Gauss is offline
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About the choke, remember the diode will splash the magnetocurrent(monopole current) everywhere at impulse(diode probably will transmute too?), each HV-LV collision will be a bit different I guess since neutrinos fly by now and then and convert into electrons inside water. Transmutation will happen at the electrode. So the resonance frequency will change over time and water needs to be discharged completely. I read about a guy who got a terrible shock from the water.
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Old 12-18-2008, 09:02 PM
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Diode is in Meyer schematic for blocking action, and is even named so. I haven't understood it up to now.


Diode is here for blocking BACK CURRENT - ELECTRONS FROM WATER !!!!
I'm 100% sure about it.

That's why also insulation on tubes and amp consuming device before diode.
Electron extraction circuit.

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  #88  
Old 12-21-2008, 05:25 PM
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Re:Stanley Meyer Explained

H20POWER:

I want to personally thank you for this thread. I get it. There is one patent of Stan Meyer where he uses the term Radiant Energy and EASER. "Those skilled in the art..." will see this. If you put 1+1+1 together you get 3. Start with Tesla, study Bearden and Bedini look at all Stan's patents and then ask yourself why the Joe Cell is suppressed. The Joe Cell is in fact an EEC. There's a lot going on in the gas gun. There's 2 sides to every equation. It's not just the hydrogen atom that's involved it is also oxygen. The more electrons you strip the higher the energetic gradient goes. Nature prefers everything in equilibrium (high school chemistry) and I believe in fact that the gas gun is potentially dangerous. All for now...

Regards,
Andy
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  #89  
Old 12-22-2008, 06:27 AM
h20power h20power is offline
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Your very wellcome Handyandy, I am glade that some are getting this information, this way the energy revolution gets underway. For I looked at all veriables and this was the only way to get it out too the people

Any other way would be stopped quick and haulted, for too many have their hands in other peoples pockets.


h2opower.
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  #90  
Old 12-24-2008, 12:50 PM
handyandy handyandy is offline
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more on the EEC

If you look at the David Lawton replication he modifies his basic circuit and introduces a light bulb. This is his EEC. His results state that the amp draw goes down and production increases as the light gets bright. The explanation given is cold electricity. I think the answer is simpler than that. The light bulb is simply pulling the electrons it needs from the water capacitor in order to light. Pulling not pushing and that's why it's cold. I have heard electrolysers described as a load. What is a lightbulb but a load. A load does work. It can be anything in this case it's light. The water capacitor is a limited source of electrons. The load is your throttle for producing gas. I think I've said too much Happy Holidays...

Andy
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