If the container is the same shape as the item being floated,
can you not float anything in only a 1/4 inch of water surrounding
the item being floated?

If yes, then a 6 volt 120mA solar pump for $25 could do the same amount
of work in one hour as lifting a 5000+ lb car 6 inches off the ground.

The hydrostatic pressure creates the upward buoyancy force.
The magnitude of the buoyant force equals the weight of the displaced fluid (water) ..
The key here is not that it did displace any water, but how much
water would have displaced had any water been there to be displaced.

This is how I fudged the numbers to come up with the estimate of work
that could be done.

So, let us say a cubic foot of water is about 60+ lbs.
If we had a square cubic foot of AIR (a square balloon)
which is held into the water at a depth of 6 inches,
the force pushing upward would be about 30 lbs.

square balloon = 12" x 12" x 6" = 864 cu in
square container of water = 12.25" x 12.25" x 6" = 900 cu in

To obtain a 30 lb upward force requires 36 cubic inches of water.
36 cu in = 0.156 gallon = 0.59 liter

Solar Pump Garden Fountain Pond Water Feature Mini kit
1.0 Watt Solar Fountain Pond Water Pump Panel Brushless
A solar 6V, 120mA pump can pump 150L/H, max height 65cm (2 feet) $25

Say this pump does 100 Liters per hour at a 1 foot head (lift).
That would be 169 strokes @ 30 lbs per stoke = 5070 lbs per hour.

Did I get up on the wrong side of the bed or
does this have something of valve?
If it is of value, What's the COP of that?


Randy

You did what to the who now? Can I buy a vowel?

No, seriously I think I need a picture.

Love and light

Picture... Picture yourself trying to push a basketball under water.
That's the force I'm talking about using, except you pump the water in
and drain the water out.

Displacing 1 square foot of water requires 60 lbs of force pushing down..
That could be just as easy be a 30 lb force pushing upwards on whatever
device you have to convert that force into work.

Lots of wave power devices use buoyancy and I've seen a water pump that
uses buoyancy.

I was thinking if it works in the waves and in a stream and it had
almost as much lifting power as you care to design it to do..

Images:THE MITCHELL FLOAT-PUMP
About the pump: THE MITCHELL FLOAT-PUMP

Again the upward force upon the float is equal to the weight of the
water displaced and not upon the amount of water in the float container.

The water in a gravity fed could go on to water a garden or be wasted,
but the water in a solar pump fed could be reused over and over again.

Has potential for high pressure pumping.
It takes only about 4 psi to pump to a 10 foot head.
A $25 solar pump able to only pump to 18 inches, could be used to
pump water to a storage tank at a 20 foot level.

I believe I understand your design after looking at it for a bit. And I see no reason why this wouldn't work. This would be equivalent to a lever. But you should be more clear with the numbers and for gods sake use SI units.

Thanks for the vote that the idea would work.
Sorry the units I have are not SI.

I believe in a water piston design, as this, as all forces are transfered.
The diameter of the water pipe being used, with the two one way valves,
is the water piston.
The water pipe dimension is the one that should be used in any force to
psi calculations.

If the water being pumped is a 1 inch pipe and a force of 30 lbs creates
a 38 psi. Force/area = psi.
The float, air piston/cylinder, water reserve only transfer the force to the
water piston which is the water in the water pipe itself.

Therefore, multiple piston/cylinders have no direct effect upon the transfer
of force between the float and the water piston, other than whatever losses
there might be mechanically. Multiple piston/cylinders would just allow
larger volumes of air and water to be moved during that transfer of the force.

Reference tables here containing PVC pipe clearances for
piston/cylinder construction with or without end caps.

Crud, I misspelled the subject line and Can't edit it.

Easy piston/cylinder design.
Soda bottle is the cylinder and pushed down into the water,
the water becomes the piston.

I only need to design how to move the upward Buoyancy force to
a downward push on the Soda bottle piston/cylinders.

The image was for using 3 liter soda bottles, which a 3/4" pvc
pipe fits into the neck of the bottle.

Edited: 7/31/09 The PISTON/CYLINDER BELOW isn't worth a hill of beans
I should have tested this before I posted it ..
It turns out Hydrostatic Pressure dictates the force of the air leaving this piston/cylinder design
which is about flipping Zero pressure. The air leaving the tubing has nothing to do with buoyancy

Attached Images

SodaFloat.jpg (175.1 KB, 11 views)

I was confused.
The topic title for this thread is Wrong.

Hydrostatic Pressure has nothing to do with the Buoyancy force.

A totally submerged object's Buoyancy force does not change.
1/100 th of an inch under water or 1 mile under water, it's the same value.

if Hydrostatic Pressure effected the Buoyancy force,
we could launch rockets to the moon, by dragging them to
the bottom of the ocean and then liftoff..

Depth has to do with Hydrostatic Pressure, not Buoyancy force.

Buoyancy force has to do only with the weight of the fluid displaced
by the object in the fluid. Change the density of the fluid and now
you got something.

Yep, I realized that as well not so long ago
THINK, what the **** would have happened to the world if it was the opposite?!?!? Objects would get sucked straight to the bottom of the ocean, accelerating, if they had too much water above them. Sounds like a scary nightmare....

Your comment made me see I used the word but instead of the word by
in my previous post. .. I also realized it awhile back .. but was waiting
until I had something else to post other than my OPPS