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-   -   AC to Cap Dump (http://www.energeticforum.com/renewable-energy/20873-ac-cap-dump.html)

 nilrehob 11-16-2017 10:38 AM

AC to Cap Dump

1 Attachment(s)
A really simple circuit, makes it easy to calculate input to the battery.
And yes, I'm splitting the positive in a FWBR ;-)
Be aware that the cap may get hot.

https://youtu.be/F2gmZ-9CmKM

/Hob

 BroMikey 11-16-2017 11:09 AM

Quote:
 Originally Posted by nilrehob (Post 306311) A really simple circuit, makes it easy to calculate input to the battery. And yes, I'm splitting the positive in a FWBR ;-) https://youtu.be/F2gmZ-9CmKM /Hob

 nilrehob 11-16-2017 11:18 AM

Quote:
 Originally Posted by BroMikey (Post 306313) Could you say more about your splitting the positive experiences?
No, its a joke,
look at the circuit and locate the FWBR and you will see that I have 'split the positive'.

/Hob

 nilrehob 11-28-2017 11:09 AM

Hi everyone,

Comparing whats going in to whats coming out of the battery I'd say I have overunity:

/Hob

 Wistiti 11-28-2017 02:44 PM

Hi nilrehob.
Have some question:
- have you try with a larger cap?
-I see you have change the value of the resistor in your last video... what is the effect of using a bigger value resistor? Did you use a variable resistor to find the sweet spot?
-what is the best voltage to use on ac side, you find ?

Thank you for sharing your experiment! :)

 nilrehob 11-28-2017 03:44 PM

Quote:
 Originally Posted by Wistiti (Post 306620) Hi nilrehob. Have some question: - have you try with a larger cap? -I see you have change the value of the resistor in your last video... what is the effect of using a bigger value resistor? Did you use a variable resistor to find the sweet spot? -what is the best voltage to use on ac side, you find ? Thank you for sharing your experiment! :)
I have tried all kinds of caps, but caps are not made the same, different kinds of caps with the same capacitance can give very different results. Some get hot others don't, some charge the battery really well on low voltage others don't even though the have the same capacitance. I tried a really high-capacitance cap at low voltage but the diodes fried!

A bigger gate-resistor requires a higher AC-voltage, otherwise it will not trigger, but once it triggers it just consumes energy so its god efficiency to have a high resistance. Note the possibility to switch the position between the SCR and the battery. No variable resistor, but a variable transformer.

The current into the battery depends on capacitance*AC-voltage. But the energy in the cap depends on capacitance*AC-voltage^2 which makes me wonder whats going on. This together with the differences between cap-types makes it difficult to test. I need more caps. Motor-caps seems like the way to go.

You're welcome, I'm glad you liked it.

/Hob

 nilrehob 12-04-2017 07:49 PM

I did a new run with a logging voltmeter on the battery. I calculate that the energy dumped from the battery to the resistor was 1643Wt (where a tick (t) is 255s) and the energy going into the battery during charging was 1068Wt (in the video I wrongly calculated it to be 1188Wt). For unity the charging should have taken 4 days but was finished 14h or so ahead.

https://youtu.be/WBOPQOEBEIU

/Hob

 nilrehob 12-05-2017 07:39 AM

Power out is simply Vbat²/R where Vbat is the voltage across the battery and R is the dump-resistor.

Power in is Vbat*f*C*(Vcap-Vbat) where f is the AC frequency, 50Hz where I am, and Vcap is the voltage across the cap just before the dump to the battery and C is the capacitance of the cap. C*(Vcap-Vbat) is the charge Q being dumped from the cap as in Q = C*V and so f*Q is the total charge during a second which in turn is the average current. Work done is Vbat*Q which for one second is the same as the avg power.

Does it make sense or am I making a mistake somewhere?

/Hob

 BroMikey 12-05-2017 08:38 AM

Quote:
 Originally Posted by nilrehob (Post 306787) Power out is simply Vbat²/R where Vbat is the voltage across the battery and R is the dump-resistor. Power in is Vbat*f*C*(Vcap-Vbat) where f is the AC frequency, 50Hz where I am, and Vcap is the voltage across the cap just before the dump to the battery and C is the capacitance of the cap. C*(Vcap-Vbat) is the charge Q being dumped from the cap as in Q = C*V and so f*Q is the total charge during a second which in turn is the average current. Work done is Vbat*Q which for one second is the same as the avg power. Does it make sense or am I making a mistake somewhere? /Hob
Just the right frequency to the plates, some call it radiant, others say
growing finer material on plates TOO!! I think all of that is true. There
can be some sort of strange happening if the correct tuning is hit
but the chemical process keeps moving over and so you need to

 nilrehob 12-05-2017 08:56 AM

Quote:
 Originally Posted by BroMikey (Post 306788) Your thoughts?
Too early to tell, I have a few more experiments to do first.
But it's encouraging :thumbsup:

/Hob

 BroMikey 12-05-2017 09:15 AM

Quote:
 Originally Posted by nilrehob (Post 306789) Too early to tell, I have a few more experiments to do first. But it's encouraging :thumbsup: /Hob
I know a couple of guys who have abandoned batteries all together
because of the shift away from any process you engage it with. They
use capacitors and capacitor grow material on them as Bedini would say
about battery plates. Some say the capacitor was conditioned.

Anyway according to these other guys capacitors are easier to engage
with respect to increasing surface area but not only that. The new area
that took time to transformer had a much lower resistance to an incoming
charge. This made it not only a small amount more efficient to add charge
to a plate but made it twice. Caps do not have to follow a "C" rate
like a battery, but batteries can show all of these same increases.

If you create the standing resonance a transient may appear and be
absorbed into your battery or reflect off the battery plates into the
circuit, i am not sure what it does. It adds energy to the system?
This effect is magic.

One guy claims he rings his cap like a bell and has 5 watt units out
of a tiny circuit. It is a continuous output of 5 watts or bigger if he
wants.

he uses 2 ultra fast recovery diodes in a row after the transistor in
all of his circuits.

 nilrehob 12-05-2017 07:59 PM

I've just completed another discharge and its almost exactly as the previous one,
so the charging seems OK!

/Hob

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