Originally posted by dragon
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Yes, you must run all of these little side experiments to see the truth of what is going on in a circuit like this. Another simple test is simply to test the voltage of a battery with a multimeter, and then add a 1K resistor in-line with the test probes and test the voltage of the battery again. As long as your contacts are good and clean, the voltage should read exactly the same as without the 1K resistor.
So, the question is: how much "voltage drop" is there across a resistor?
If the answer is "NONE" as it appears to be, then it becomes clear that we can light the light bulb (resistor) if there is "some current" and a "potential difference" across the bulb. No energy (or at least very little) needs to be dissipated to light the light!
Keep up the great work!!!!
Peter
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