Hi Peter
the spark in your eyes seems astounding

But of course we are not beating Mister Lenz in this case, please reassure me. ?
So to be very clear in my mind,
the motor is a one pulse "Terrificly torquy" as per a GUN SHOT
which fires its power to a really heavy flywheel
, the aim of which is to transform the gun shot into a smooth steady 360 degree kinetic force,
the aim of which is to spin a generator ( separeted from the motor)
the aim of which is FIRST
to generate electricity to charge a cap ( this is the black powder of of the gun )
,the discharge power of which (SHOT) is to power the pulse of the one pulse ( GUN SHOT ) motor.
SECONDLY to use the exess electricity (if any) to be used for ligting lamps or powering any other electrical machines
And IN PARALLEL and IN COMPLEMENT to all the above actions we look for recuperating some energy back out of the motor
We look for a mean to capture the really strong sharp and very hig voltage FLYBACK SPIKE (which is NOT and has nothing to do with the BEMF) and to redirect it in the cap (or other external battery a la Bedini).
But this spike contain very few energy and will never be enough powerfull to power the motor, it is only a usable energy complement (some more gram of black powder)
And i assume that nobody here will attempt to capture the BEMF (counter generated voltage) of the motor pulse ? Because if you try you will ask to the motor to make a work to produce energy and of course you will get nothing in compensation but the heat Joule lost and the motor will slow down without energy gain.
So far i experimented the best is to leave the inevitable (Lenz ) BEMF free to act (for nothing) but keep it as small as possible. Nobody can beat Mister Lenz but everybody can try to keep him as a gnome

It is why we will have imperatively to use only 1 pulse per revolution and the brush MUST only act on ONE collector section without touching any other section (of course conected to eventually remainig winding).
And if we want to collect the flyback spike it is necessary to adjust the brush in a way as it leaves the power collector section exactly as it touches the recup collector section as Peter explain in his very clear drawings some post ago. If we can not do this we will loose some input power in the recup circuit.
Very challenging isn'it ?
Thank's for your attention and always ready to accept any contradiction

Good luck at all

Laurent
Leave a comment: