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Lockridge Device - Peter Lindemann

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  • mbrownn
    replied
    Yes but I didn't get overunity on the output shaft that time even though I was running the motor on close to 200w with about a 60w input but I did burn up my motor

    I don't have a variac and just connected it to rectified 220v, big mistake. I need to do a test to establish how I need to organize the power in the circuit, using a variac you can limit the power and avoid my mistake.

    Using a standard 12v motor we need to measure the torque and power at high voltage input but lower than normal amps. For example if the motor running at 12v draws 6 amps I want to know how the torque and power compares at say 24v and 3 amps. Is the torque down and how much even though the power is the same?

    If this is the case as I expect, I will need to use a different configuration or run the motor at higher power but with a lot more cooling.

    The circuit that I have posted multiplies the power when compared to the input but it does it with higher voltage. If I reduce the amps I expect I will have reduced torque and a very inefficient motor. The whole point of this thread which Peter was driving was to give ampere turns and eliminate BEMF. I have worked out how to mitigate the BEMF but I need to confirm this will reduce the efficiency.

    I have a circuit which does increase the amps, or at least maintain their level while multiplying the voltage which is good news but I need to compensate for the drop in efficiency.

    It is relatively easy to run a standard motor at its normal power with only a fraction of the input but I believe the efficiency is down; however there is a way to create a negative resistance with the trifler coil

    I'm willing to share if you can do the test for me.

    The other option is to run a 220v motor on 220 volts but at reduced speed to mitigate the BEMF

    The first key to the Lockridge device is to recycle the power, next is to supply it to a motor in a way that is efficient for the motor or get a motor that works at that voltage and current. There are plenty of 220v universal motors but their efficiency is low at 35%, multiply that by the generator efficiency at 70% and you have only 24.5% meaning you will need a COP>4 to make it self running.

    I have posted the first part already, the recycling circuit which multiplies the COP although I did understate how it is done . A standard servo motor or golf cart running at 50% duty cycle under PWM is close to a COP of 2 under light loads. That is the second part of the circuit. I don't have the third part fully sorted yet but I am working on it anthough Aviso has posted part of it even though he is using a different technique.

    Building things is very time consuming and expensive when you make mistakes, fortunately I have the time but I don't have the budget at the moment. I want to build a team that will build, test and replicate what I am doing so that the info gets out. Hope you can help

    Mike

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  • N O G
    replied
    Question first

    Hi there MBrownn ,
    Have you built something like this or is this just theory youve put together as building things take time and effort and is a different world . The external commutator system is the same John B uses in his motor /generator setup , like what Watson made . I made a small one a while ago but it kept destroying the batteries i used , not saying i was doing it right but it did work to a point , this was many years back when I knew heaps less (i still got most of the parts for it here somewhere i think) . I can put something together as a side project but im a busy boy . cheers Jason

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  • mbrownn
    replied
    Nice vid.

    If you want to get a Lockridge device working I can lead you through the process. I have run my circuit past Peter and this is what he said

    "The schematic you posted is very good. You have seen the light!! The "bi-polar" switch on the front end and the twin diode return circuit to an isolated capacitance, allows the creation of a "DC RESONANCE" event described by Tesla. The circuit can product repeated, high power impulses to an output system, while the true power supply only needs to make up the real losses in the system, which include voltage drops on the semi-conductors, changes of inductance between charge and discharge, and the like. You now see that the "LOAD" is not the real dissipator of the electricity!

    Good work!"


    We CAN do it with an unmodified motor but there are a few things we will need to do for that.

    1) The switching has to be at both sides of the motor, ie it is switched both on and off on both the input and the output simultaneously, trapping the inductive spike. More on this later.

    2) The switching has to be very fast.

    3) We have to make an external commutator or use PWM

    4) we will need a fixed load

    I see you have a variac so you have the power input for the tests and you can easily make a pony break.

    Do you want to do it? Well make an external commutator where you can vary the position of the brushes to shorten the pulse with connections as shown in the image.
    Attached Files

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  • N O G
    replied
    Mini Lockridge Device

    Hi there Everyone ,
    He is a video i made showing a motor made for testing and learning , this setup on the motor can be changed easyly for different config's . The motor is a bit small as are the brushes but hey it still runs .Ive moved on to some bigger stuff now , still exploring some things i have in my head . cheers Jason Mini Lockridge test device - YouTube

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  • N O G
    replied
    Lockridge device

    Hi there Mbrownn ,
    Nice to see someone is still at it . The bi polar circuit is good ive built a couple of window motors some good some very chit and even tried to run a 3 phase windmill generator on one phase just to see what i could do at the time but havn t done any more on that side since then (one thing at a time or my head caves in) . yer id like to hear what you want to show as im very open mined on everything . cheers Jason

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  • mbrownn
    replied
    Yes, I am still at it, but I don't think you need to modify the motor. I have sent some of my info to Peter and he likes what I am doing.

    Quote "The schematic you posted is very good. You have seen the light!! The "bi-polar" switch on the front end and the twin diode return circuit to an isolated capacitance, allows the creation of a "DC RESONANCE" event described by Tesla. The circuit can product repeated, high power impulses to an output system, while the true power supply only needs to make up the real losses in the system, which include voltage drops on the semi-conductors, changes of inductance between charge and discharge, and the like. You now see that the "LOAD" is not the real dissipator of the electricity!"

    It may be possible to do it with the commutator on the right motor but it is simpler to put an external commutator on a standard unmodified motor. My experience is that we cant get the switching fast enough with the modern low inductance motors and so a DC generator would be better, rings a bell doesn't it?

    Do you want to know more?

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  • N O G
    replied
    Still at it

    Hi there Everone ,
    Im still at it - Done heaps of tests with small motors and have learnt lots what to do and definitely what not to do ( smoke ) . Just got some big motors to play with ( big commutators ) Yer im excited finally some big motors to play with . So back to work for me - anyone still building or are you all slak and lazy . cheers jason

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  • tournesol
    replied
    Originally posted by Aaron View Post
    Hi Everyone,

    This thread is for the discussion of the Lockridge Device concepts that
    Peter shared in his presentation.

    You can order his presentation here very soon:
    Free Energy, Products, Books and DVDs

    This is basically part 2 of the original Electric Motor Secrets.

    We're not talking about lockridge device, but Peter concept about it
    I'm full on the topic.
    Isn't it?

    Is there people here who has explored deeper the theory?

    High voltage induce copper losses, the average of the current by the voltage is not the same as average current by average voltage.

    Who agree, who disagree, why.
    let go further together

    Leave a comment:


  • mbrownn
    replied
    I think this may be of interest but I don't want to clutter this thread or take the subject off at a tangent.

    http://www.energeticforum.com/renewa...tml#post155577

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  • tournesol
    replied
    So, where goes the suposed dissipated power losses of the BEMF.
    Heat? It would produce more heat as observed.
    And where can it be localized physically?

    I'm not in confrontation, be sure.
    I just want to understand.

    You said that BEMF is accross the winding, not in serie like for calculation.
    I'm agree.
    You speak about 72W power supply and 36W of usefull power.
    Why not 72W of usefull power if powered accross the winding.

    We also may hypothetise that BEMF act as a charge barrier.
    The current is reduced, but overpotentialized with exact applied power.
    I don't think so, we don't need it, but it's an idea...

    I don't know, i just want to understand why Electric motors have apparent COP 2, but electrical enginieers never see it.

    I want to understand, just like you

    Don't be hurted please
    I sincerly love your work, and quality of presentations
    Last edited by tournesol; 08-23-2011, 11:20 PM.

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  • tournesol
    replied
    Hi Peter!

    Effectively, i need more background in physics and mathematics.
    It's why i'm here, to understand more.

    I did the experiment and did'nt found any unusual things
    This is why i go back to paper

    How a voltage can be generated without separation of charge and flow of current?
    I know (according to Bearden) that the source charge is not the source of energy.
    But charges makes the dipole. And the dipole create scalar potential.
    You say that the motor is able to create a pure voltage, so pure scalar potential, whitout charges dipole.
    That's new for me.

    I had understood that the motor need to keep the same speed, in order to keep the same operating point.
    Why going faster when speed makes BEMF
    In the point of view of the motor, it feels to go slow slower.
    Isn't true?

    I'm agree that the power is the speed times the torque.
    And i'm also agree that I can't calculate the mecanical output.
    This is why I made a cross calculation with the nominal operating point.

    I know this is wrong, but it can be usefull for an approximation.
    And this is enough to improuve the theory.
    If there is somethings else, you didn't talk about in your video


    I'm conscious that i'm not scientist, but i just want to understand more about it
    I'm here to correct myself in order to go further on the theory.
    For me, and all others in this tread


    Thanks a lots for your critics
    Last edited by tournesol; 08-23-2011, 09:50 PM.

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  • Peter Lindemann
    replied
    You and I disagree

    Dear Tournesol,

    Welcome to the forum and thank you for reviewing much of the analysis on my Electric Motor Secrets 2 DVD. You and I definitely disagree on a number of important points. First of all, BEMF is definitely a VOLTAGE, not a current. In the DC motor, the current only moves in one direction, but the Back EMF (reverse generated voltage) definitely opposes the Applied Voltage, as a PRESSURE or FORCE against the driving force.

    While your analysis mathematically analyzes the electrical input side of the equation, you do nothing to analyze the MECHANICAL POWER consequences of the new set of conditions when the motor operates at a HIGHER SPEED. After all, mechanical power is determined by TORQUE times SPEED. You will not be able to do this without a full computer simulation, OR an actual model on your bench.

    There are many other things wrong with your analysis, but I don't have time to go through them right now.

    I can see you are deep thinker. That is good. But unless you actually build models and see what they actually do on the bench, you won't have an opportunity to think about anything new!

    Peter

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  • cwaugs
    replied
    You gentlemen totally inspire me and as soon as I can get my economy affected business running more on it's own I'll be back to joining youall. Keep up the excellent work! Wayne

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  • tournesol
    replied
    What about that

    Hi everybody
    This is my first post on this forum
    Not new as reader.
    Iím French guy so my English is not really rich

    Thanks all for your precious work!
    Specially for you, Aaron and Peter.
    It is so rare to find people like you who are open source minded, and take time for explaining things clearly.
    You inspire me to do the same

    I saw the 2 DVD on electric motors secret and Energy from the vaccum #14 on the Lockridge device presented by Bedini.
    Iím not really interested by practical experimentation since I donít really understand what Iím doing.
    This is why I tried to redo the complete calculation shown on the electric motor secret 2, but I found some misunderstanding that I want to share with you.

    For being clear about what we are talking, I redo the graphics

    This is the classical view of an electric motor


    Here the simplified curves explaining the operating point


    Now, let expand this graphic whit pulsed voltage


    When reducing to the area of the motor possibilities
    We have reduced the Bemf and increasing current for the same apparent operating point


    Now, take an example
    As you said Peter, a motor hide a poor efficiency but a COP of 2 Max.


    What happen if we pulse the motor by a voltage ten time more the nominal with a 10% Pwm ratio
    We are approaching COP 2


    But!
    What about that?


    Peter, in your calculation, do you take account of the dissipated power in the windings?


    Here is the new COP taking account of the theoric current power factor of 2


    My COP calculation is so low that itís seems me to have made a mistake


    Why not another explanations of the phenomena






    In my pictures, I take 10% of PWM ratio as example, like said in the video, but the average current is 11.4.
    Is this case, we are not anymore in the apparent nominal operating point. We should take a PWM ratio of 5,26 % for having 6 Amps.
    But itís okay for demonstration


    This way of viewing the lookridge device seems to me less and less credible for two reasons:
    -As we know that electrical engineers are working on lots of parameters of motors, it seams strange to me that this simple concept could be ignored for so long time.
    (In order to get the best capability of a motor, a electronic controller drive it by regulating more than 50 parameters.)
    -Since classical EM doesnít permit open systems, every free energy device could only exist within a new electromagnetic model. Your theory, using classical EM, show that it could even be simulated on computer. Did you try it?
    I never saw any simulated OU device reported. And we can understand why.
    Last edited by tournesol; 08-10-2011, 09:58 PM.

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  • Kenowen
    replied
    missing messages?

    I do not see any messages from June 17 until today Aug 5. Were there messages posted between these dates? I looked for a refresh or re-read link but nothing.
    Thanks

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