No thank you for trying to help me, I have actually failed several times in other concepts which I thought could work, like the siphon tread you can find in overunity.com.

But here's what I think; basically you are right that the water will push back with the same pressure as the static pressure of water column will push, it's newtons third law of motion. However, this would only happen if the water didn't have any place to escape.

Think of your weight. If you stand on the ground you are applying a force to the ground, but the ground is also applying the same force back on you.
However if the ground had moved because of your weight, for example if you stood on a big lever, then it wouldn't apply the same force back on you.

In this case the water is allowed to travel up in the thin pipe. As all systems want to reach equilibrium, they will, as long we give them the opportunity, but here the way it happen is changed from the normal equal height/static pressure because a simple machine has been employed, giving leverage.
A simple machine is just another word for a gear,piston,hinge or whatever.
It chances the relationship between force F and distance D, but they equal to the same value.


Specifically about the air pressure, yes it will push back with the exact same force as from the water column, so they are equal, meaning that neither of them can push each other. What is not equal is the force from thin pipe because of it interaction with leverage. If you watch some of the youtube clips about Hero's fountain you will see that it alone at least work.

What I want to do here is to take it further, by combining two of them, each feeding each other instead of just sending the high squirt of water back into the lower tank, which I think is a complete waste. I want to use that high water for power!


But don't worry, I'll try the concept with soda-bottles before I try it with larger buckets, I have learned my lesson before
Julian