Quote:
Originally Posted by Jetijs
elias,
I am a bit confused about your calculations and formulas. I tried to calculate my efficiencies based on your formulas and got a completely different result for my efficiencies. To be sure please calculate the efficiency from my numbers.
V in - 11.42 V
A in - 2.45 A
RPM - 2655
Scale1 - 100g
Scale2 - 10g
Wheel circumference - 0.5 feet
Diameter - 48.38mm
Thanks
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Jetijs,
P = F * L / T That is the rate of doing work. So the circumference of your wheel is 0.5 ft = 152.4mm, So:
D = 152.4 mm = 0.01524 meters.
F = (.100 - .010) * 9.8 N = 0.882 Newtons.
T = 1 /( 2655/60) = 0.0226 seconds (one revolution is done in this amount of time)
P_out = 0.882*0.1524/0.0226 = 5.95 W So dividing this by the input will give your efficiency.
But a question I have is: Why haven't you loaded your motor more than this? It may give you better results.
Regards,
Elias