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Old 12-08-2007, 12:32 PM
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elias elias is offline
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A battary behavior when being pulsed by a capacitor

Hi

I did this experiment to find out how a 12V battery responds when applying a 10000uF with 18V of voltage to it. This is the wave form around the battery terminals, which decays like a logarithmic function. The decay time is related to the internal impedance of the battery to the battery. Each square is 5msec and 1volts. RC is approximately 2msec here, therefor R = 2msec/10000uF = 0.2 ohms. The impedance of the battery is somewhat related to the moving ions in the battery, which decreases as the ions move.

Elias
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Last edited by elias : 12-08-2007 at 12:41 PM.
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